JSON array - extract the lat lng - php

Question

I have a function that is trying to get the coordinates from a json array. It has me stumped so I was hoping someone would see my error.
function getCoords($location){
$loc = urlencode($location);
$url = "https://maps.googleapis.com/maps/api/geocode/json?address=$loc&sensor=false";
//echo $url;
//echo file_get_contents($geo_url);
$json_result = json_decode(file_get_contents($url));
$geo_result = $json_result->results[0];
$aCsv = $geo_result->geometry->location;
//see if the it is locating the real address or just apox location, or in most cases a bad address
if($aCsv->location[0] == 200) {
return array('lat'=>(float)$aCsv[2], 'lng'=>(float)$aCsv[3], 'prec'=>(int)$aCsv[1]);
}
var_dump($aCsv);
}
The var dump is below I need to extract just the lat and lng in this format 42.3584308,-71.0597732, 21.3069444, -157.8583333
object(stdClass)#12 (2) { ["lat"]=> float(42.3584308) ["lng"]=> float(-71.0597732) } object(stdClass)#6 (2) { ["lat"]=> float(21.3069444) ["lng"]=> float(-157.8583333) }
I think this part is where I am running into my issue
if($aCsv->location[0] == 200) {
return array('lat'=>(float)$aCsv[2], 'lng'=>(float)$aCsv[3], 'prec'=>(int)$aCsv[1]);
TIA steve
Guys is there a way to access the JSON data outside of the function? I would like to take the actual address that is being parsed and show that in the result ing calculation.
Sometimes google maps does not use the exact location for instance if I type in KLAX - Los Angeles airport if uses a address in Germany but if I put LAX it uses teh LA airport so it would be nice to see the parsed address as well.
I can echo the address thats being parsed within the function but when I try to use it outside the function it is NULL.
Thanks Again for your assistance.
Steve

Answer 1

Trees and woods? You already have it !!
function getCoords($location){
$loc = urlencode($location);
$url = "https://maps.googleapis.com/maps/api/geocode/json?address=$loc&sensor=false";
$json_result = json_decode(file_get_contents($url));
$geo_result = $json_result->results[0];
$aCsv = $geo_result->geometry->location;
echo 'lat : '.$aCsv->lat.'<br>';
echo 'lng : '.$aCsv->lng.'<br>';
}
getCoords('alabama');
outputs
lat : 32.3182314
lng : -86.902298

Answer 2

try this
$data = json_decode($ResponseData);
if('OK' === $data->status){
$latitude = $data->results['0']->geometry->location->lat;
$longitude = $data->results['0']->geometry->location->lng;
}

Answer 3

It's easier to work with a assoziative array so you can use this:
$json_result = json_decode(file_get_contents($url),true)
(http://php.net/manual/de/function.json-decode.php)
Then the values are available with:
$json_result["lng"]
etc.

Answer 4

Use this
$geocode = file_get_contents('http://maps.googleapis.com/maps/api/geocode/json?address='.$loc.'&sensor=true');
$output = json_decode($geocode);
if($output->results)
{
foreach($output as $data)
{
$lat = $data[0]->geometry->location->lat;
$long = $data[0]->geometry->location->lng;
$location = $data[0]->formatted_address;
}
}