Moving html table content to sql database - php

Question

I've got a table (grabbed from another website using php) but now I want to import it's content into my database (instead of just printing out the table).
This is the printout (http://i.stack.imgur.com/NnbAo.png) from the table using the following code:
<?php
$uitvoer = getTable();
echo "<table">;
foreach ($uitvoer as $row) {
echo "<tr>";
foreach ($row as $col) {
echo "<td>" . $col . "</td>";
}
echo "</tr>";
}
echo"</table>";
?>
And when I try this nothing happens to my database:
<?php
$con = mysqli_connect("mysql1.000webhost.com","a2902119_lowavol","pswd")
$uitvoer = getTable();
foreach ($uitvoer as $row) {
foreach ($row as $col) {
$query += "'" . $col . "', ";
}
$sql="INSERT INTO test (cel1, cel2, cel3, cel4, cel5, cel6, cel7, cel8, cel9) VALUES ($query)";
mysqli_query($con, $sql);
}
?>
I have little to no knowledge about PHP. Thanks for helping me!

Answer 1

The concatenation operator for PHP is (.) and not (+)
<?php
$con = mysqli_connect("mysql1.000webhost.com","a2902119_lowavol","pswd")
$uitvoer = getTable();
foreach ($uitvoer as $row) {
$query = array();
$insert = "";
$insert_values = "";
foreach ($row as $col) {
$query[] = $col;
}
$insert_values = implode("','", $query) ;
$insert = "'".$insert_values."'";
$sql = "INSERT INTO test (cel1, cel2, cel3, cel4, cel5, cel6, cel7, cel8, cel9) VALUES ($insert)";
mysqli_query($con, $sql);
}
?>

Answer 2

your query will look like this:
INSERT INTO test (....) VALUES (val, val, val, )
which is obviously a syntax error... try and add the fields to an array instead:
foreach ($uitvoer as $row) {
$fields = array();
foreach ($row as $col) {
$fields[] = $col; // TODO: add escaping!
}
// now you can build the values list with implode
$values = implode(', ', $fields);
$sql="INSERT INTO test (...) VALUES ($values)";
See the docs about implode() for more info.

Answer 3

Use a prepared statement:
$sql="INSERT INTO test (cel1, cel2, cel3, cel4, cel5, cel6, cel7, cel8, cel9) VALUES (?, ?, ?, ?, ?, ?, ?, ?, ?)";
$stmt = mysqli_prepare($con, $sql);
mysqli_stmt_bind_param($stmt, "sssssssss", $row[0], $row[1], $row[2], $row[3], $row[4], $row[5], $row[6], $row[7], $row[8]);
foreach ($uitvoer as $row) {
mysqli_stmt_execute($stmt);
}

Answer 4

Try echo-ing $sql. I think there is a comma in the end.
Use
$query = substr($query, 0, strlen($query) - 1)
in order to remove the last character of $query
(edited the command)