I need to call a html data inside a twitter modal window from a .php file. How to call this function? This below script is inside a php file, i need to call this inside a modal window once we click the link. I am able to trigger the modal window but not the data.
<html xmlns=”http://www.w3.org/1999/xhtml”>
<head>
<meta http-equiv=”Content-Type” content=”text/html; charset=utf-8″ />
<title><?php echo $post->post_title; ?></title>
<meta name=”robots” content=”noindex”/>
</head>
<body>
<div style=”"><?php echo $image; ?></div>
<?php echo $post->post_title; ?></b>
<p style=”float: left;”>Testing</p>
</body>
</html>
you can achieve this by putting your HTML inside a file called remote.html, then run this:
<a data-toggle="modal" href="remote.html" data-target="#modal">Click me</a>
Alternatively, you can insert HTML into the modal window using jquery, kind of like this:
$('.modal-button').click(function() {
var myHTML = "[YOUR HTML]";
$('.modal-body').html(myHTML);
});
what you want is to display the image and title data inside the modal right?
<div>
<div id="image"></div>
<span id="myTitle"></span></b>
<p style=”float: left;”>Testing</p>
</div>
Place this content inside modal and fetch the image and title data through an ajax call
$(function () {
$.ajax({
type: "POST",
contentType: "application/json; charset=utf-8",
url: "Fetch.php",//give the path of the php file or the function
data: '{ "query": ' + data + ' }',//place the query data
dataType: "json",
success: function (msg) {
AjaxSucceeded(msg);
},
failure: function (response) {
alert("Failure");
},
error: function (jqXHR, textStatus, errorThrown) {
alert("Error " + jqXHR + " " + textStatus.responseText + " " + errorThrown);
}
});
});
AjaxSucceeded(msg){
//replace the div with the image and the title
$(#image).innerHTML=msg.Image;
$(#myTitle).innerHTML=msg.Title;
}
Cheers!!!
Related
Here I have an .ajax function within a PHP function, like this:
function phpFunction($ID) {
print "<script>
$('.uparrow').click(function(){
request = $.ajax({
etc... the rest isn't important.
Anyway, the class .uparrow is an html element that runs this .ajax function when clicked. The other thing you should know is that this function: phpFunction() is called a few times in the document, like this:
phpFunction(1)
phpFunction(2)
phpFunction(3)
However, the problem is that when I load phpFunction(), and I click on the .uparrow element, the .ajax call is made on behalf of each instance of phpFunction() that follows the one whose element I clicked on.
So if I clicked on the .uparrow of phpFunction(1), I would also be virtually clicking on the .uparrows of phpFunction(2) and phpFunction(3). Essentially, I need .uparrow to just be a local class that only applies to the instance of phpFunction() that is currently being called.
The only solution I could think of is to replace .uparrow's class name with something unique to each call of this function. The only difference between each instance of phpFunction() is their input $ID and I was thinking I could redefine .uparrow as:
class = '$ID.uparrow'
or
class = $ID + 'uparrow'
But that doesn't work. So how do I make sure that when I click on .uparrow within phpFunction(1), that the .ajax function only gets called that one time?
This is pretty confusing to explain and probably to understand, so please tell me if there's something that needs elaboration.
Let's say you have a list of elements, and when you click one of them, you want to do an ajax call.
click me
click me
<script>
$(function(){ //on DOM ready
$('.uparrow').on('click', function(){
//do ajax call
$.ajax({
url: 'url here'
type: 'post|get'
data: $(this).attr('data-id'), // you only send the ID of the clicked element
... callbacks, etc
})
});
})
</script>
Now you only have a function that makes an ajax call and takes the parameter to send from the element you clicked.
I hope this is what you wanted to achieve
Try something like this
$('[class="uparrow"]').click( function () {
var request = $.ajax({
// Your ajax call
});
});
this will execute ajax on the clicked element with .uparrow class
HTML
<a class="uparrow" href="#" data-ajax="I'm the first element">Click Me</a>
<a class="uparrow" href="#" data-ajax="I'm the second element">Click Me</a>
<a class="uparrow" href="#" data-ajax="I'm the third element">Click Me</a>
JS:
$('[class="uparrow"]').click(function () {
var currentAjax = $(this).data('ajax')
console.log(currentAjax);
});
And the DEMO
Do not call your php function multiple times. Just one time is sufficient.
Modify the markup of your .uparrow element to include the id like so:
<a class="uparrow" data-id="<?php echo $id; ?>" href="#">TextM/a>
Then re-write your php function like so:
function phpFunction() { /* no need to pass the ID */ ?>
<script>
$(function(){
$(document).on('click', '.uparrow', function(){
$.ajax({
url: 'URL',
type: 'POST'.
data: $(this).attr('data-id')
})
});
})
</script>
<?php } ?>
Call your phpFunction like so:
phpFunction();
UPDATE
<!doctype html>
<html>
<head>
<title>trop</title>
<meta charset='utf-8'>
<link rel='stylesheet' href='css/postStyle.css' />
<link href='http://fonts.googleapis.com/css?family=Exo+2:400,300,200|Homenaje&subset=latin,latin-ext' rel='stylesheet' type='text/css'>
<link rel='shortcut icon' href='http://icons.iconarchive.com/icons/visualpharm/icons8-metro-style/256/Music-Note-icon.png'>
<script src='../jquery.js'></script>
<script type='text/javascript' src='../script.js'></script>
</head>
<body>
<?php
$ids = array(1,2,3); // IDs of the posts you want
$result = mysql_query("SELECT * FROM all_posts WHERE ID IN($ids)");
while ($data = mysql_fetch_array($result)){
?>
<div class='post' style='width:470px'>
<h3><?php echo $data['Title']; ?></h3>
<div class='date'><?php echo $data['DateTime']; ?></div>
<iframe width='470' height='300' src='http://www.youtube.com/embed/WF34N4gJAKE' frameborder='0' allowfullscreen></iframe>
<p><?php echo $data['Body']; ?></p>
<div class='postmeta1'>
<p><a href='<?php echo $data['DownloadLink']; ?>' target='_blank'>DOWNLOAD</a></p>
</div>
<div class='verticalLine' style='height:39px'></div>
<div class='postmeta2'>
<p class='uparrow' data-id="<?php echo $data['id']; ?>">▲</p>
<div class='votes'>3</div>
<p class='downarrow'>▼</p>
</div>
<div class='verticalLine' style='height:39px'></div>
<div class='postmeta3'>
<div class='tags'>
<p><?php echo $data['Tags']; ?></p>
</div>
</div>
</div>
<?php } ?>
<script>
var request;
$('.uparrow').click(function(){
request = $.ajax({
url: 'votesHandler.php',
type: 'post',
data: { add : '1', ID : $(this).attr('data-id') }
});
request.done(function (response, textStatus, jqXHR){
alert('Voted!');
});
request.fail(function (jqXHR, textStatus, errorThrown){
alert(
'Oops, something went wrong'
);
});
request.always(function () {
alert('Done.');
});
});
</script>
</body>
</html>
I have not been able to use JQuery/Ajax to load the content of my PHP file into a div tag.
Here is my page that is loading the file:
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.3/jquery.min.js"></script>
<script>
function init() {
reloadChat();
setInterval (reloadChat, 5000);
}
function reloadChat() {
$.ajax({
url: "chat.php",
cache: false,
success: function(){
$("#chatmenu").load("chat.php");
},
});
}
</script>
<body onLoad='init()'></body>
<div id='chatmenu'></div>
The PHP file I am loading (chat.php) is in the same folder, and is just an echo statement:
<?php echo "test"; ?>
To make sure it was not a problem with my Javascript functions, I added an alert under the success function, and it did alert me every 5 seconds, so I think it is something with the load statement.
Use .load() straight away, no need to make an Ajax request first:
function reloadChat() {
$("#chatmenu").load("chat.php");
}
Update:
I notice that in your example code, you close your body-tag before your div element.
<body onLoad='init()'></body> <!-- This ain't right -->
<div id='chatmenu'></div>
Try this instead:
<body onLoad='init()'>
<div id='chatmenu'></div>
</body>
Try this:
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.3/jquery.min.js"></script>
<script>
function init() {
reloadChat();
setInterval (reloadChat, 5000);
}
function reloadChat() {
$.ajax({
url: "chat.php",
cache: false,
success: function(response){
$("#chatmenu").text(response);
},
});
}
</script>
<body onLoad='init()'></body>
<div id='chatmenu'>
</div>
Also, for the love of god, please use an up-to-date version of jQuery
It looks your first request from $.ajax will return 'test', and then you're using that as the URL for $("#chatmenu").load.
Try this:
function reloadChat() {
$.ajax({
url: "chat.php",
cache: false,
success: function(data){
$("#chatmenu").append(data);
},
});
}
Or, if you want to replace the contents of #chatmenu the method posted by Christofer Eliasson where you just call $("#chatmenu").load("chat.php") in reloadChat will work.
Putting it all together:
<!DOCTYPE html>
<html>
<head></head>
<body>
<div id="chatmenu"></div>
<script type="text/javascript" src="http://code.jquery.com/jquery-1.7.2.min.js"></script>
<script type="text/javascript">
$(function() {
setInterval (function() {
$("#chatmenu").load("chat.php");
}, 5000);
});
</script>
</body>
</html>
this is what i have in the head tags of my html page to load the facebox plugin:
<!-- This is for the facebox plugin to work -->
<link href="<?php echo base_url();?>styles/facebox/src/facebox.css" media="screen" rel="stylesheet" type="text/css" />
<script src="<?php echo base_url();?>styles/facebox/lib/jquery.js" type="text/javascript"> </script>
<script src="<?php echo base_url();?>styles/facebox/src/facebox.js" type="text/javascript"></script>
<script type="text/javascript">
jQuery(document).ready(function($) {
$('a[rel*=facebox]').facebox({
loadingImage : "<?php echo base_url();?>styles/facebox/src/loading.gif",
closeImage : "<?php echo base_url();?>styles/facebox/src/closelabel.png"
})
})
</script>
this is the code for my div
<?php if(isset($$j)) : foreach($$j as $row) : ?>
<div class="single-result" id="single-result">
<div class="name"><?php echo $row->Name; ?></div>
<div class="description"><?php echo $row->Description; ?></div>
</div>
<?php endforeach; ?>
<?php else : ?>
error here
<?php endif; ?>
what i am wanting, is some ajax code that calls a function when the user clicks on the div id="single-result" so that it makes an ajax call to a php controller that gets the data from the database and then loads the view into a facebox modal window.
The part i am unsure about is how to make it load into a facebox modal window, l know how to use ajax calls to make it send data to a file and then load a view into a certain div on the page, l just want it to load it into the modal window instead of a certain div on the page.
Is this possible at all? (also i am using codeigniter for the php framework)
here is my ajax code which would load the ajax request results into the content-right div when the user clicks on div.
<script type="text/javascript">
$("#single-result").click(function() {
var form_data = {
ajax: '1',
itemcode: "<?php echo $row->id; ?>"
};
$.ajax({
url: "<?php echo site_url('ajax/item_info_right'); ?>",
type: 'POST',
data: form_data,
success: function(msg) {
$('#content-right').html(msg);
}
});
return false;
});
</script>
<!-- END -->
how do i modify this code above to make it work with going into a facebox modal window? I know facebox provides this code below, but i have no idea what to do with it?
jQuery.facebox(function() {
jQuery.get('code.js', function(data) {
jQuery.facebox('<textarea>' + data + '</textarea>')
})
})
It's not really clear what you're after...
If what you want is to have the data returned from the ajax POST to be populated into a facebox, simply call facebox on the success callback of the ajax post:
$("#single-result").click(function() {
var form_data = {
ajax: '1',
itemcode: "<?php echo $row->id; ?>"
};
$.ajax({
url: "<?php echo site_url('ajax/item_info_right'); ?>",
type: 'POST',
data: form_data,
success: function(msg) {
jQuery.facebox(msg);
})
});
alternatively, it looks like if you want the facebox loading graphics while the post is processed, you can wrap the ajax POST in facebox function:
$("#single-result").click(function() {
jQuery.facebox(function() {
var form_data = {
ajax: '1',
itemcode: "<?php echo $row->id; ?>"
};
$.ajax({
url: "<?php echo site_url('ajax/item_info_right'); ?>",
type: 'POST',
data: form_data,
success: function(msg) {
jQuery.facebox(msg);
})
});
})
})
I am very new to Jquery and ajax so please be kind.
i am making a request to the server using jquery $.ajax, the ajax pulls the image from the image id stored on the server/database when the user clicks on a thumbnail of which there are loads. All works fine except with the following code i can only click on any of the thumbnails once to load the big picture from the database, after that no other thumbnail works.
Can anyone help?
<script type="text/javascript" src="jquery-1.5.2.min.js"></script>
<script type="text/javascript">
function getimage(data){
var img = new Image();
$(img).load(function(){
$(img).hide();
$.ajax({
type: "GET",
url: "name.php?",
data: "name=" + data,
success: function(){
$("#loader").removeClass("loading").append(img);
$(img).fadeIn("slow");
}
});
}).attr("src", data +".jpg");
}
</script>
</head>
<body>
<h1>Image Loading</h1>
<div id="loader" class="loading">
</div>
<a href="name.php?name=image1" id="image1" onclick="getimage('image1'); return false;"/><img src="image1_th.jpg" /></a>
<a href="name.php?name=image2" id="image2" onclick="getimage('image2'); return false;" /><img src="image2_th.jpg" /></a>
<a href="name.php?name=image3" id="image3" onclick="getimage('image3'); return false;"/><img src="image3_th.jpg" /></a>
try this:
function getimage(data){
var img = new Image();
$(img).load(function(){
$(img).hide();
$.ajax({
type: "GET",
url: "name.php?",
data: "name=" + data,
success: function(){
$("#loader").html(''); // you need to remove the old image
$("#loader").removeClass("loading").append(img);
$(img).fadeIn("slow");
}
});
}).attr("src", data +".jpg");
I'm trying to load a StatCounter tracking script after the form has been successfully sent. Here's the code:
$.ajax({
type: "POST",
url: "css/sendmail.php",
data: dataString,
success: function(data) {
$('#script').load('css/script.html', function() ({
$('#overlay').css('visibility','hidden');
clearForm();
$('#alert').slideDown().delay(5000).slideUp();
});
}
});
This is the tracking script:
<!-- Start of StatCounter Code -->
<script type="text/javascript">
var sc_project=3886809;
var sc_invisible=1;
var sc_security="05496a3d";
</script>
<script type="text/javascript" src="http://www.statcounter.com/counter/counter.js"></script><noscript><div class="statcounter">
<a title="visit tracker on tumblr" href="http://www.statcounter.com/tumblr/" target="_blank">
<img class="statcounter" src="http://c.statcounter.com/3886809/0/05496a3d/1/" alt="visit tracker on tumblr" ></a></div></noscript>
<!-- End of StatCounter Code -->
I checked my stats and it works. The only problem is that the code is being executed twice. The first one shows up as "http://example.com/index.html" and the second one as "http://example.com/index.html#".
Couldnt it be just as simple doing it like
<div style="display:none" id="tracker">
<!-- PUT STATCOUNTERHERE -->
</div>
and in the success function do the following
$('#tracker').show();
The other way would to store the code as a var
var statcode = "<script> blahblahblah.....";
and then on success
$('#whereuwanttoshowit').html(statcode);