Create and Update a table from database using php - php

Question

I have a database with the following fields:
eventname (the name of the event - text)
datestart (the start date of the event - e.g. ../../..)
dateend (the end date of the event - e.g. ../../..)
I need to create a table with 3 columns, and however many rows depending on how many events there are.
Here is the code I'm using at them moment to store the database data in an array:
$allevents = mysql_query("SELECT * FROM Events ORDER BY datestart ASC");
while($event = mysql_fetch_array($allevents)){
As I said, I then need to to display the data in a table.
I'd really appreciate some help as to how to achieve this, as I'm very new to PHP.

Answer 1

You will want to use a foreach loop to cycle through your array and echo your html content.

Answer 2

you can try this :
First : Create the function for convert dates, here this code :
function convDate($str_date, $format = "d-m-Y")
{
// Ubah string ke date
$date = new DateTime($str_date);
// Kembalikan niilai dengan date_format
return $date->format($format);
}
Finaly.. you can retrieve the query with dates formatted
while($event = mysql_fetch_array($allevents)){
echo $event['eventname'] . '-' . convDate($event['datestart'], 'd/m/Y') . '-' .
convDate($event['dateend'], 'd/m/Y');
}

Answer 3

Are you familiar with Alex Garret's FREE ten-minute tutorials on TheNewBoston or (his own site) phpAcademy.org?
These may help you greatly:
200 PHP videos at TheNewBoston.com
PHP tutorials at phpAcademy.org
Basically:
$allevents = mysql_query("SELECT * FROM Events ORDER BY datestart ASC");
$out = '<table><tr><td>Name</td><td>Address</td></tr>';
while($event = mysql_fetch_array($allevents)){
$name = $event['name'];
$addr = $event['addr'];
$out .= '<tr>';
$out .= '<td>' .$name. '</td>';
$out .= '<td>' .$addr. '</td>';
$out .= '</tr>';
}
$out .= '</table>';
echo $out;