I'm trying to achieve something basic, where you submit a form with a weight and it updates my database via ajax.
I've been looking through some of the answered questions for guidance but I just can't figure out why the below code doesn't work.
looking in chrome developer tools it look like it's not even submitting the form properly, so I don't think its the php script that's the issue (although it may have other issues once I fix the first problem).
Any help with fixing this would be much appreciated.
Here's the form and Ajax code
<script src="//ajax.googleapis.com/ajax/libs/jquery/1.10.2/jquery.min.js"></script>
<script type="text/javascript">
$("#weight_tracker_form").submit(function() {
$.ajax({
type: "POST",
url: "../weight_tracker_process.php",
data: {
weight: $("#weight").attr("value"),
},
success: function(){
alert("success");
},
error: function(){
alert("error");
}
});
return false;
});
</script>
<h2>Weight Tracker</h2>
<form id="weight_tracker_form" method="post">
Date: <input autofocus id="date" name="date" type="date"/>
Weight: <input id="weight" name="weight" type="text"/> Kg
<input type="submit" value="Submit Weight">
</form>
And here's the script weight_tracker_process.php
<?php
// configuration
require("includes/config.php");
if ($_POST["weight"] == NULL)
{
apologize("Please enter an email");
}
$weight = mysql_real_escape_string($_POST["weight"]);
$date = mysql_real_escape_string($_POST["date"]);
if (query("INSERT INTO weight (user_id, weight_measurement) VALUES (?, ?)", $_SESSION["id"], $weight); == false){
echo "Update Error";
}
else {
echo "Success";
}
?>
Thanks!
If this is your exact code, then what's probably happening is the handler isn't being attached to the form element. The JavaScript code is before the form, so when it runs the form doesn't exist yet. So this selector returns an empty array:
$("#weight_tracker_form")
You'll want to wait until the DOM is finished loading before assigning the event handler:
$(function () {
$("#weight_tracker_form").submit(function() {
$.ajax({
type: "POST",
url: "../weight_tracker_process.php",
data: {
weight: $("#weight").attr("value"),
},
success: function(){
alert("success");
},
error: function(){
alert("error");
}
});
return false;
});
});
Wrapping it in the jQuery function like this will cause it to wait until the document's ready event fires.
Try switch this:
weight: $("#weight").attr("value");
For this:
weight: $("#weight").val();
Also, you put the code on in document.ready. Like this:
$(document).ready(function({
$("#weight_tracker_form").submit(function() {
$.ajax({
type: "POST",
url: "../weight_tracker_process.php",
data: {
weight: $("#weight").attr("value"),
},
success: function(){
alert("success");
},
error: function(){
alert("error");
}
});
return false;
});
}));
Thanks guys, initial problem was as you suggested with me forgetting to wait for the dom to load before executing the script.
Second problem was some small bracket and syntax errors in the script.
Final code is below
HTML / Jquery
<script src="//ajax.googleapis.com/ajax/libs/jquery/1.10.2/jquery.min.js"></script>
<script type="text/javascript">
$(function () {
$("#weight_tracker_form").submit(function() {
$.ajax({
type: "POST",
url: "weight_tracker_process.php",
data: {
weight: $("#weight").val()
},
success: function(){
alert("success");
},
error: function(){
alert("error");
}
});
return false;
});
});
</script>
<h2>Weight Tracker</h2>
<form id="weight_tracker_form" method="post">
Date: <input autofocus id="date" name="date" type="date"/>
Weight: <input id="weight" name="weight" type="text"/> Kg
<input type="submit" value="Submit Weight">
</form>
Log Out
PHP
<?php
// configuration
require("includes/config.php");
// if form was submitted
if ($_SERVER["REQUEST_METHOD"] == "POST")
{
if ($_POST["weight"] == NULL)
{
echo "Error";
}
$weight = mysql_real_escape_string($_POST["weight"]);
if (query("INSERT INTO weight (user_id, weight_measurement) VALUES(?, ?)", $_SESSION["id"], $weight) == false){
echo "Update Error";
}
else {
echo "Success";
}
}
else
{
// else render form
printf("error");
}
?>
I also suggest to use jQuery.serialize() method to post all the fields from broser to the server.
<html>
<head>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.10.2/jquery.min.js"></script>
<script type="text/javascript">
$(document).ready(function() {
$("#weight_tracker_form").submit(function() {
$.ajax({
type: "POST",
url: "../weight_tracker_process.php",
data: $("#weight_tracker_form").serialize(),
success: function(){
alert("success");
},
error: function(){
alert("error");
}
});
debugger;
return false;
});
});
</script>
</head>
<body>
<h2>Weight Tracker</h2>
<form id="weight_tracker_form" method="post">
Date: <input autofocus id="date" name="date" type="date"/>
Weight: <input id="weight" name="weight" type="text"/> Kg
<input type="submit" value="Submit Weight">
</form>
</body>
</html>
Related
I have a record of carriers and clients. When selecting a carrier on the customer screen, I need it to be automatically filled out the carrier's e-mail and telephone. The PHP file is returning a JSON correctly, but it is dropping in the error of jquery and not in success. I checked in Firefox's Firebug and the HTML tab of the console, where the GET requisition is reset.
<?php
include "Config/config_sistema.php";
$res = mysql_query("SELECT * FROM transportadoras");
$menu_items = null;
while($ln = mysql_fetch_object($res)){
$menu_items[] = $ln;
}
json_encode($menu_items);
?>
<script>
$("body").on("change","#transportadoras",function(event){
event.preventDefault();
var trigger=$(this);
$.ajax ({
type: "POST",
url: "buscaDadosTransportadora.php",
dataType: 'json',
success: function (data) {
$("#telefone_transp").val(data.telefone);
$("#email_transp").val(data.email);
},
error: function (data) {
alert("Erro");
},
});
});
</script>
return in ajax
[{"ID":"5","Nome":"Vinicius","email":"viniciusbalbinot91#gmail.com","telefone":"32680018"},{"ID":"6","Nome":"teste","email":"teste#teste.com.br","telefone":"12345567"}]
You response is array .
[{"ID":"5","Nome":"Vinicius","email":"viniciusbalbinot91#gmail.com","telefone":"32680018"},....]
you should loop through data.
success: function (data) {
$.each(data,function(user){ /* code ...*/});
}
If you want some current row select one row from mysql .
hope it can help u
php.php
$inp=$_POST["data"];
$txt[0]=array("ID"=>"5","Nome"=>"Vinicius","email"=>"viniciusbalbinot91#gmail.com","telefone"=>"32680018");
$txt[1]=array("ID"=>"6","Nome"=>"teste","email"=>"teste#teste.com.br","telefone"=>"12345567");
for($c=0;$c<sizeof($txt);$c++)
{
if($txt[$c]["ID"]==$inp)
{echo json_encode($txt[$c]);}
}
index.php
ID:<input id="txt" name="txt" type="text" />
<br><br>
Name:<input id="name" name="txt0" type="text" disabled="disabled"/><br>
Email:<input id="email" name="txt0" type="text" disabled="disabled"/><br>
Tel:<input id="tel" name="txt0" type="text" disabled="disabled"/><br>
js
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<script>
$("document").ready(function()
{
$("#txt").keyup(function ()
{
$.ajax(
{
type:"POST",
dataType:"json",
url:"php.php",
data:{data : $("#txt").val()},
success: function(data)
{
$("#name").val(data.Nome);
$("#email").val(data.email);
$("#tel").val(data.telefone);
},
error: function ()
{
alert("Error!");
}
});
});
});
</script>
I have a basic signup/ login page that submits the data to the SQL database with php. However, I would like the page not to redirect on submission with help of jQuery AJAX (either successful or not).
This is what I currently have and it is not working. It doesn't show any error messages.
HTML - signup.html
<!DOCTYPE html>
<html lang="en">
<head>
<title>Signup</title>
<meta charset="utf-8">
</head>
<body>
<form>
<table>
<tbody>
<tr>
<td>
<input type="text" name="first" placeholder="First Name" id="first">
</td>
</tr>
<tr>
<td>
<input type="text" name="last" placeholder="Last Name" id="last">
</td>
</tr>
<tr>
<td>
<input type="submit" value="Signup" id="signup">
</td>
</tr>
</tbody>
</table>
</form>
</body>
</html>
JavaScript - signup.js
function submit() {
$("form").submit(function(e) {
e.preventDefault();
$.ajax({
type: 'POST',
url: 'signup.php',
data: $('form').serialize(),
success: function() {
console.log("Signup was successful");
},
error: function() {
console.log("Signup was unsuccessful");
}
});
});
}
$(document).ready(function() {
submit();
});
PHP - signup.php
<?php
include_once "db_connect.php";
$post_FirstName = $_POST['first'];
$post_LastName = $_POST['last'];
$addData = "INSERT INTO details (firstname, lastname) VALUES ('$post_FirstName', '$post_LastName')";
if ($conn->query($addData) === TRUE) {
echo "Working";
} else {
echo "Not working";
}
?>
Here is the JSFiddle.
I hope you guys can help. Thanks in advance :)
If you are using ajax no need to use input type as submit use button.
$(document).ready(function() {
$("#signup").click(function(e) {
e.preventDefault();
$.ajax({
type: 'POST',
url: 'signup.php',
data: $('form').serialize()
success: function() {
console.log("Signup was successful");
}
error: function() {
console.log("Signup was unsuccessful");
}
});
});
Also change here
$post_FirstName = $_POST['first']; // name is `first` not `firstname`
You have some brakes and parentheses not properly closed
function submit() {
$("form").submit(function(e) {
e.preventDefault();
$.ajax({
type: 'POST',
url: 'signup.php',
data: $('form').serialize(),
success: function() {
console.log("Signup was successful");
},//here
error: function() {
console.log("Signup was unsuccessful");
}
});});//here
}
$(document).ready(function() {
submit();
});
No need to call submit function. Just this will do, (you missed comma and closing tag):
<script>
$("form").submit(function(e) {
e.preventDefault();
$.ajax({
type: 'POST',
url: 'signup.php',
data: $('form').serialize(),
success: function() {
console.log("Signup was successful");
}, //You missed this
error: function() {
console.log("Signup was unsuccessful");
}
});
}); //You missed this
</script>
I am using HTML, PHP and AJAX to create a search field.
Here is my HTML Code:
<form action="search.php" id="search_form" method="post" >
<div class="search_bar">
<input type="text" name="search_text" id="search_text" placeholder="Search anything" >
</div>
<div class="search_button">
<button type="submit" id="search_button" name="search_submit" >Search</button>
</div>
</form>
This is my AJAX Code:
$('#search_button').click(function(event) {
var search_data = $('#search_text').val();
var postData ={
"content":search_data};
event.preventDefault();
$.ajax({
type: 'POST',
url: 'search.php',
data:{myData: postData},
error: function()
{
alert("Request Failed");
},
success: function(response)
{
alert("Success");
}
});
});
In PHP I tried the following:
$obj = $_POST['myData'];
echo $obj;
print_r($_POST);
All I am getting is:
Notice: Undefined index: myData in C:\xampp\htdocs\workspace\MakeMyApp\WebContent\search.php on line 9
Array ( )
I have also tried with:
file_get_contents('php //input')
but there also I am getting empty array. I don't know what exactly the problem is. Am I missing anything?
Sorry, I can't comment as I don't have enough 'reputation'.
I have tried to replicate your issue and it seems to work ok for me.
Here is the HTML page ...
<html>
<head>
<script src="//code.jquery.com/jquery-1.11.3.min.js"></script>
<script src="//code.jquery.com/jquery-migrate-1.2.1.min.js"></script>
<script type="text/javascript">
$(document).ready(function(){
$('#search_button').click(function(event) {
var search_data = $('#search_text').val();
var postData ={
"content":search_data};
event.preventDefault();
$.ajax({
type: 'POST',
url: 'search-submit.php',
data:{myData: postData},
error: function()
{
alert("Request Failed");
},
success: function(response)
{
alert(response);
}
});
});
});
</script>
</head>
<body>
<form action="search.php" id="search_form" method="post" >
<div class="search_bar">
<input type="text" name="search_text" id="search_text" placeholder="Search anything" >
</div>
<div class="search_button">
<button type="submit" id="search_button" name="search_submit" >Search</button>
</div>
</form>
</body>
</html>
And this is the receiving PHP page
<?php
echo '<pre>';
print_r($_POST);
echo '</pre>';
?>
In the ajax request, you can see I'm using alert to output the response in an alert but, and if all goes well it should output the content outputted by the receiving PHP page.
Also, it may not help much, but his is how I would have done the ajax request; it's slightly less code and you don't have to define each form field individually (if you have more than one field)
$(document).ready(function(){
$('#search_form').submit(function() {
var formData = $(this).serialize();
$.ajax({
type: 'POST',
url: 'search-submit.php',
data: formData,
error: function()
{
alert("Request Failed");
},
success: function(response)
{
alert(response);
}
});
return false;
});
});
I have a form in a modal window. When I submit the form through ajax I don't get the success message. My aim is to see the message created in the php file in the modal after submitting the form. Here is the code:
<p><a class='activate_modal' name='modal_window' href='#'>Sign Up</a></p>
<div id='mask' class='close_modal'></div>
<div id='modal_window' class='modal_window'>
<form name="field" method="post" id="form">
<label for="username">Username:</label><br>
<input name="username" id="username" type="text"/><span id="gif"><span>
<span id="user_error"></span><br><br>
<label for="email">Email:</label><br>
<input name="email" id="email" type="text"/><span id="gif3"></span>
<span id="email_error"></span><br><br>
<input name="submit" type="submit" value="Register" id="submit"/>
</form>
</div>
The modal.js
$('.activate_modal').click(function(){
var modal_id = $(this).attr('name');
show_modal(modal_id);
});
$('.close_modal').click(function(){
close_modal();
});
$(document).keydown(function(e){
if (e.keyCode == 27){
close_modal();
}
});
function close_modal(){
$('#mask').fadeOut(500);
$('.modal_window').fadeOut(500);
}
function show_modal(modal_id){
$('#mask').css({ 'display' : 'block', opacity : 0});
$('#mask').fadeTo(500,0.7);
$('#'+modal_id).fadeIn(500);
}
The test.js for the registration of the user
$(function() {
$('#form').submit(function() {
$.ajax({
type: "POST",
url: "test.php",
data: $("#form").serialize(),
success: function(data) {
$('#form').replaceWith(data);
}
});
});
});
And the PHP FILE
<?php
$mysqli = new mysqli('127.0.0.1', 'root', '', 'project');
$username = $_POST['username'];
$email = $_POST['email'];
$mysqli->query("INSERT INTO `project`.`registration` (`username`,`email`) VALUES ('$username','$email')");
$result = $mysqli->affected_rows;
if($result > 0) {
echo 'Welcome';
} else {
echo 'ERROR!';
}
?>
Try putting the returncode from your AJAX call into
$('#modal_window')
instead of in the form
$('#form')
BTW: Why not use the POST or GET method of jQuery? They're incredibly easy to use...
Try something like this.
First write ajax code using jquery.
<script type="text/javascript">
function submitForm()
{
var str = jQuery( "form" ).serialize();
jQuery.ajax({
type: "POST",
url: '<?php echo BaseUrl()."myurl/"; ?>',
data: str,
format: "json",
success: function(data) {
var obj = JSON.parse(data);
if( obj[0] === 'error')
{
jQuery("#error").html(obj[1]);
}else{
jQuery("#success").html(obj[1]);
setTimeout(function () {
jQuery.fancybox.close();
}, 2500);
}
}
});
}
</script>
while in php write code for error and success messages like this :
if(//condition true){
echo json_encode(array("success"," successfully Done.."));
}else{
echo json_encode(array("error","Some error.."));
}
Hopes this help you.
Been asking a lot of jquery questions lately, I'm trying my best to learn a lot about it.
Anyway, I am sending an Ajax HTTP request to a PHP page in order to make a login form without requiring a page refresh. Now since it may take some time to connect the database and get the login information etc..
Now I do have loading as a .html but how can I hide the loading data once data has loaded?
Tried to use a few functions but didn't seem to work.
Thanks so far, this site has helped me a lot through the learning process.
Here's the JavaScript:
$(document).ready(function() {
// Make a function that returns the data, then call it whenever you
// need the current values
function getData() {
return {
user_login: $('#user_login').val(),
pass_login: $('#pass_login').val()
}
}
function loading(e) {
$('#content').html('Loading Data');
}
function check(e) {
e.preventDefault();
$.ajax({
url: 'ajax/check.php',
type: 'post',
data: getData(), // get current values
success: function (data) {
$('#content').hide('slow');
alert(9);
}
});
}
// Don't repeat so much; use the same function for both handlers
$('#field').keyup(function(e) {
if (e.keyCode == 13) {
var username = $('#user_login').val();
loading(e);
check(e);
}
});
$('#submit').click(function(e) {
if (e.keyCode != 13) {
loading(e);
check(e);
}
});
});
Here is the HTML:
<script src="http://code.jquery.com/jquery-1.9.1.min.js"></script>
<script src="js/login.js"></script>
<div id="content"> Loading...</div>
<div id="field">
<input type='text' name='user_login' id='user_login' placeholder='eg: Mark#gmail.com'> <br>
<input type='password' name='pass_login' id='pass_login'> <br>
<input type="submit" name="submit" id="submit" value="Login">
</div>
function check(){
$.ajax({
url: 'ajax/check.php',
type: 'post',
error: function(){
alert('An error has occured.');
},
beforeSend: function(){
$('#content').show('slow').html('Loading');
//loading(e);
},
data: {user_login: $('#user_login').val(),pass_login: $('#pass_login').val()}, // get current values
success: function (data) {
$('#content').hide('slow');
alert(9);
}
});
}
$('#submit').click(function(){
check();
});
$('#field, #field input').keyup(function(e){
var username = $('#user_login').val();
if (e.keyCode == 13) {
check();
}
});
Markup
<div id="field">
<input type='text' name='user_login' id='user_login' placeholder='eg:Mark#gmail.com'> <br>
<input type='password' name='pass_login' id='pass_login'> <br>
<input type="button" name="submit" id="submit" value="Login">
</div>
Good luck!!!
First of all, i'm not sure if your code will return a success. This code will help you find out if the response is not successfully. If you get a browser alert. It means you have a server side error. Its either the url path is wrong or your server response statuscode is 500 (Internal error).
$.ajax({
url: 'ajax/check.php',
type: 'post',
error: function(){
alert('An error has occured.');
},
beforeSend: function(){
$('#content').show('slow').html('Loading');
//loading(e);
},
data: getData(), // get current values
success: function (data) {
$('#content').hide('slow');
alert(9);
}
});
Refactoring your code entirely will look like this. Choose first or second:
$.ajax({
url: 'ajax/check.php',
type: 'post',
error: function(){
alert('An error has occured.');
},
beforeSend: function(){
$('#content').show('slow').html('Loading');
//loading(e);
},
data: {user_login: $('#user_login').val(),pass_login: $('#pass_login').val()}, // get current values
success: function (data) {
$('#content').hide('slow');
alert(9);
}
});