i have a table user(id,name) and a table payments(date,amount,user_id)
I need a query to display for each user the total sum of payments and the payments in last month.
User - totalpayments - monthlypayments
something like this
SELECT id, name from user;
SELECT COUNT(amount) FROM payments WHERE user_id=user.id;
SELECT COUNT(amount) FROM payments WHERE user_id=user.id AND (data<=$timestamptoday AND data>=$timestamp1stday)
is it possible to do that without doing many queries?
Sure you can do it within one query.
SELECT
u.ID,
u.Name,
SUM(p.amount),
SUM(CASE
WHEN p.date <= '2013-02-01' AND p.date >= '2013-01-01' THEN p.amount
ELSE 0
END)
FROM
Users u
JOIN
Payments p ON u.ID = p.UserID
GROUP BY
u.ID,
u.Name
Working DEMO
Absolutely you can do this as a single query:
SELECT user.name, SUM(amount) AS totalpayments, SUM(IF(date <= '$enddate' AND date >= '$startdate'),amount,0) AS monthlypayments
FROM user LEFT JOIN payments ON user.id = payments.user_id
GROUP BY user.id
ORDER BY user.name ASC
Note that I'm using SUM rather than COUNT on the assumption that you're looking for the total amounts of the payments, rather than the number of payments there were.
Related
I have a big data problem with MySQL.
I have:
a users table with 59033 rows, and
a user_notes table with 8753 rows.
But when I search which users have user note in some dates.
My query like this :
SELECT u.*, rep.name as rep_name FROM users as u
LEFT JOIN users as rep on rep.id = u.add_user
LEFT JOIN authorization on authorization.id = u.authorization
LEFT JOIN user_situation_list on user_situation_list.user_situation_id = u.user_situation
WHERE
EXISTS(
select * from user_notes
where user_notes.note_user_id = u.id AND user_notes.create_date
BETWEEN "2017-10-20" AND "2017-10-22"
)
ORDER BY u.lp_modify_date DESC, u.id DESC
Turn it around -- find the ids first; deal with the joins later.
SELECT u.*,
( SELECT rep.name
FROM users AS rep
WHERE rep.id = u.add_user ) AS rep_name
FROM (
SELECT DISTINCT note_user_id
FROM user_notes
WHERE create_date >= "2017-10-20"
AND create_date < "2017-10-20" + INTERVAL 3 DAY
) AS un
JOIN users AS u ON u.id = un.note_user_id
ORDER BY lp_modify_date DESC, id DESC
Notes
No GROUP BY needed;
2 tables seem to be unused; I removed them;
I changed the date range;
User notes needs INDEX(create_date, note_user_id);
Notice how I turned a LEFT JOIN into a subquery in the SELECT list.
If there can be multiple rep_names, then the original query is "wrong" in that the GROUP BY will pick a random name. My Answer can be 'fixed' by changing rep.name to one of these:
MAX(rep.name) -- deliver only one; arbitrarily the max
GROUP_CONCAT(rep.name) -- deliver a commalist of names
Rewriting your query to use a JOIN rather than an EXISTS check in the where should speed it up. If you then group the results by the user.id it should give you the same result:
SELECT u.*, rep.name as rep_name FROM users as u
LEFT JOIN users as rep on rep.id = u.add_user
LEFT JOIN authorization on authorization.id = u.authorization
LEFT JOIN user_situation_list on user_situation_list.user_situation_id = u.user_situation
JOIN user_notes AS un
ON un.note_user_id
AND un.create_date BETWEEN "2017-10-20" AND "2017-10-22"
GROUP BY u.id
ORDER BY u.lp_modify_date DESC, u.id DESC
I am trying to do a MYSQL query where I get the most recent purchase for a user and then see if falls within certain criteria. Here is the query I put together:
select
users_purch.purch_date as purchase_date,
users_purch.total_amount as purchase_amount,
users.*
from
users
left join
(
select
max(date) as purch_date,
user_id,
total_amount
from
users_purchases
group by
user_id
) as users_purch
on users_purch.user_id = users.id
where
users_purch.purch_date < '2016-11-01'
and users_purch.total_cost < 112.49
order by
users_purch.purch_date desc
It seems that the query works but fails in certain aspects. For example, if a user has more than one purchase entry it is getting the max date but the amount as total_cost that the query retrieves is not from the same row as the max date. How can I rewrite this query to give me the most recent purchase record in its entirety?
Thanks!
You have to join once more to user_purchases table in order to get the information about the date:
select
users_purch.purch_date as purchase_date,
users_purch.total_amount as purchase_amount,
users.*
from
users
left join
(
select
max(date) as purch_date,
user_id
from
users_purchases
group by
user_id
) as users_purch
on users_purch.user_id = users.id
left join
(
select
user_id,
date,
total_amount
from
users_purchases
) as users_purch2 on users_purch.user_id = users_purch2.user_id and
users_purch2.date = users_purch.purch_date
where
users_purch.purch_date < '2016-11-01'
and users_purch.total_cost < 112.49
order by
users_purch.purch_date desc
due the group by you have in this select
if you need the amount of the max(date) rewrite extecting the proper amount
select
users_purch.purch_date as purchase_date,
users_purch.total_amount as purchase_amount,
users.*
from
users
left join
(
select t1.purch_date, t1.user_id, t2.total_amount from (
select
max(date) as purch_date,
user_id
from users_purchases
group by user_id ) t1
inner join (
date,
user_id,
total_amount
from users_purchases
) t2 on t1.user_id= t2.user_id, t1.purch_date = t2.date
) as users_purch
on users_purch.user_id = users.id
where
users_purch.purch_date < '2016-11-01'
and users_purch.total_cost < 112.49
order by
users_purch.purch_date desc
You can try this one, mate:
SELECT
up.date AS 'purchase_date',
up.total_amount AS 'purchase_amount',
u.*
FROM
users u
INNER JOIN users_purchases up ON up.user_id = u.user_id
INNER JOIN (
# get max date per user_id
SELECT user_id, max(date) AS 'purch_date'
FROM users_purchases
GROUP BY user_id
) max_up ON
max_up.user_id
# join that date to get the correct total_amount
AND max_up.`purch_date` = up.`date`
WHERE
up.`date` < '2016-11-01'
AND up.total_amount < 112.49
GROUP BY u.user_id
ORDER BY up.`date` DESC;
Note
Max Date per user_id
Value of total_amount per Max Date
Grouped per user_id
Ordered descending using users_purchases.date
In my query I am listing all of the theater ticket sales and movie ticket sales of different customers. The issue I'm running into is that all of the '0' ticket sales, so those users who haven't boughten a theater ticket or movie ticket is not showing up.
Here's a picture for a visual aspect: table
I believe I need to be doing a union to return the users who haven't boughten any tickets. I just can't seem to figure this out.
Thanks in advance.
Here's my code so far:
select customer.hippcode, customer.LastName, customer.Firstname, customer.Email,
count(ticketdetails.eventtype) as 'Theater Tickets',
0 as 'Movie Tickets'
from customer
inner join ticketdetails on ticketdetails.hippcode = customer.hippcode
where ticketdetails.hippcode is not null
and ticketdetails.eventType ='T'
Group by Customer.hippcode
union
select customer.hippcode, customer.LastName, customer.Firstname, customer.Email,
0 as 'Theater Tickets', count(ticketdetails.eventtype) as 'Movie Tickets'
from customer
inner join ticketdetails on ticketdetails.hippcode = customer.hippcode
where ticketdetails.hippcode is not null
and ticketdetails.eventType ='M'
Group by Customer.hippcode
order by `theater tickets` + `movie tickets` desc;
select
customer.hippcode, customer.LastName, customer.Firstname, customer.Email,
sum(case when ticketdetails.eventtype = 'T' then 1 else 0 end) as TheaterTickets,
sum(case when ticketdetails.eventtype = 'M' then 1 else 0 end) as MovieTickets
from customer
inner join ticketdetails on ticketdetails.hippcode = customer.hippcode
where ticketdetails.hippcode is not null
and ticketdetails.eventType in ('T', 'M')
Group by customer.hippcode, customer.LastName, customer.Firstname, customer.Email
Order by 'TheaterTickets' + 'MovieTickets' desc
inner join => bring the line only if you got a record on both table.
I think you should use a LEFT JOIN somewhere to chose the master table
http://dev.mysql.com/doc/refman/5.7/en/join.html and
http://dev.mysql.com/doc/refman/5.7/en/left-join-optimization.html
I think the last query is the only one you want. A left join is appropriate, but you need to be careful about the where clause:
select c.hippcode, c.LastName, c.Firstname, c.Email,
sum(td.eventtype) as TheaterTickets,
sum(td.eventtype) as MovieTickets
from customer c left join
ticketdetails td
on td.hippcode = c.hippcode and
td.eventType in ('T', 'M')
Group by c.hippcode, c.LastName, c.Firstname, c.Email
Order by count(t.hippcode) desc;
Notes:
Table aliases make the query easier to read and write.
Conditions on ticketdetails go in the on clause, not the where clause.
The condition on td.hippcode is not null is unnecessary, because NULL will not match in the join (note: you might want to check for the customer column).
case is the standard way to do the conditional sum (and hence correct). However, MySQL offers a much simpler and intuitive syntax.
Your order by was doing nothing, because it was adding two strings (hence equivalent to order by 0. Don't use single quotes ever for column names, and you won't have a problem like that.
I have 4 tables called shops, users, review and rating.
I want to get all reviews for the corresponding shop with reviewed user details and also overall rating for that shop.
I have done almost with the single query. But the problem is if the shop has same rating for multiple times by same user its consider as single rating. But that rating count was correct.
i.e
from this table user_id 3 was rated shop_id 1 as 4 times. So the count is 4 and total_rating is 17.
My query is
select review.comments, users.username, count(distinct rating.id) as rating_count,
sum(distinct rating.rating) as total_rating from users
left join review on users.id = review.user_id and review.shop_id='1'
left join rating on users.id = rating.user_id and rating.shop_id='1'
where review.shop_id='1' or rating.shop_id='1'
group by users.id, review.user_id, rating.user_id, review.id
When I run this query I got
But I need total_rating 17 for user_id 3..
Check this fiddle
You put DISTINCT IN sum( rating.rating) as total_rating, thats why the result(12=17-5), since it will include 5 only once while computing sum.
select review.comments, review.user_id, count(distinct rating.id) as rating_count,
sum( rating.rating) as total_rating from users
left join review on users.id = review.user_id and review.shop_id='1'
left join rating on users.id = rating.user_id and rating.shop_id='1'
where review.shop_id='1' or rating.shop_id='1'
group by users.id, review.user_id, rating.user_id, review.id
Here is SQLFiddle
Sample Output :
Hope this helps
Try this - Remove the distinct from sum(rating.rating). Since you gave sum(distinct rating.rating), it is ignoring one 5 that user 3 gave to store 1.
select review.comments, users.username, count(distinct rating.id) as rating_count,
sum(rating.rating) as total_rating from users
left join review on users.id = review.user_id and review.shop_id='1'
left join rating on users.id = rating.user_id and rating.shop_id='1'
where review.shop_id='1' or rating.shop_id='1'
group by users.id, review.user_id, rating.user_id, review.id
First of all: It makes no sense to outer-join records from a table and then remove them in the WHERE clause. With left join review ... you say: find a matching record in table review, and if you don't find any, then add nulls, so we keep the users record. Then with where review.shop_id='1' you say: keep only records where you actually found a record in review. So you are dismissing the records that you just took the pain to keep. Your WHERE clause renders your LEFT OUTER JOINS mere INNER JOINS.
As to your actual problem: That stems from joining all tables first and only then trying to get aggregates from the resulting records. Aggregate before joining instead:
select
rev.comments,
usr.username,
coalesce(rat.rating_count, 0) as rating_count,
rat.total_rating
from review rev
join users usr on users.id = review.user_id
left join
(
select user_id, shop_id, count(*) as rating_count, sum(rating) as total_rating
from rating
group by user_id, shop_id
) rat on rat.user_id = usr.id and rat.shop_id = rev.shop_id
where rev.shop_id = 1
group by rev.id;
I have a projects table and a tasks table I want to do a query that gets all projects and the sum of the time_spent columns grouped by project id. So essentially list all projects and get the total of all the time_spent columns in the tasks table belonging to that project.
With the query posted below I get the latest added time_spent column and not the sum of all the columns.. :S
Below is the query I have at the moment:
SELECT `projects`.`id`, `projects`.`description`, `projects`.`created`,
`users`.`title`, `users`.`firstname`, `users`.`lastname`, `users2`.`title`
as assignee_title, `users2`.`firstname` as assignee_firstname,
`users2`.`lastname` as assignee_lastname,
(select sum(tasks2.time_spent)
from tasks tasks2
where tasks2.id = tasks.id)
as project_duration
FROM (`projects`)
LEFT JOIN `users`
ON `users`.`id` = `projects`.`user_id`
LEFT JOIN `users` as users2
ON `users2`.`id` = `projects`.`assignee_id`
LEFT JOIN `tasks` ON `tasks`.`project_id` = `projects`.`id`
GROUP BY `projects`.`id`
ORDER BY `projects`.`created` DESC
Below is my projects table:
Below is my tasks table:
Thanks in advance!
Usually this query will help you.
SELECT p.*, (SELECT SUM(t.time_spent) FROM tasks as t WHERE t.project_id = p.id) as project_fulltime FROM projects as p
In your question, you don't say about users. Do you need users?
You are on right way, maybe your JOINs can't fetch all data.
This query should do it for you.
Note, whenever you do a group by you must include every column that you select from or order by. Some MySql installations don't prevent you from doing this, but in the end it results in an incorrect result set.
As well you should never do a query as part of your SELECT statement, known as a sub-query, as it will result in an equal amount of additional queries in relation to the number of rows returned. So if you got 1,000 rows back, it would result in 1,001 queries instead of 1 query.
SELECT
p.id,
p.description,
p.created,
u.title,
u.firstname,
u.lastname,
a.title assignee_title,
a.firstname assignee_firstname,
a.lastname assignee_lastname,
SUM(t.time_spent) project_duration
FROM
projects p
LEFT JOIN
users u ON
u.id = p.user_id
LEFT JOIN
users a ON
a.id = u.assignee_id
LEFT JOIN
tasks t ON
t.project_id = p.id
GROUP BY
p.id,
p.description,
p.created,
u.title,
u.firstname,
u.lastname,
a.title,
a.firstname,
a.lastname
ORDER BY
p.created DESC