Select everything older than 48 hours - php

I am trying to display user comments from a database that are older than 2 days. This is so I can screen the comments before they appear on the site. The date is entered into the database using CURDATE()
I have tried multiple ways to get this to work, but no joy so far, here's my line of code that tries to compare the dates.
$comments = "SELECT comments, initial, surname, theDate " .
"FROM tbl " .
"WHERE comments IS NOT NULL AND " .
"theDate < (unix_timestamp(CURDATE() - interval 2 day)) " .
"ORDER BY theDate DESC";
Everything gets displayed using this method.

Try to use DATEDIFF() MySQL function:
SELECT
comments, initial, surname, theDate
FROM
tbl
WHERE
comments IS NOT NULL
AND
DATEDIFF(NOW(), theDate) > 2
ORDER BY theDate DESC

use:
NOT BETWEEN CURDATE() - INTERVAL 2 DAY AND CURDATE()
and that should get you everything that is older than 2 days

Related

select in(past 10 hours and 5 hours)

if the user in the 5 hours has more calls in the past 10 hours, then he should tell me as an example "true". If not, he should say false to me.
if($aufruf = $pdo->prepare("
SELECT
profil_aufrufe.id,
profil_aufrufe.user_id,
profil_aufrufe.aufrufer_id,
profil_aufrufe.date
FROM
profil_aufrufe
WHERE
profil_aufrufe.user_id = :user_id AND profil_aufrufe.date ..."
))
I thought for a long time, but found no way how I can write the SQL code.
Here is your code
if($aufruf = $pdo->prepare("
SELECT
profil_aufrufe.id,
profil_aufrufe.user_id,
profil_aufrufe.aufrufer_id,
profil_aufrufe.date
FROM
profil_aufrufe
WHERE
profil_aufrufe.user_id = :user_id AND profil_aufrufe.date ..."
))
first of all you can't take a column date in your mysql table its reserved keyword of mysql
date
and why are you using alias whenever you don't join any table, there is no need of alias i simplify it i change column date to cdate
if($aufruf = $pdo->prepare("
SELECT
id,
user_id,
aufrufer_id,
cdate
FROM
profil_aufrufe
WHERE
user_id = :user_id AND
cdate between DATE_SUB(NOW(),INTERVAL 5 HOUR) and DATE_SUB(NOW(), INTERVAL 10 HOUR) "));
I think this will work for you

Select date for today

Table: id, confess, user_ip, time, url, loves, hate
Time is like 1413040760
$q = mysql_query("SELECT * FROM confessions where time >= unix_timestamp(curdate() + interval 1 day)") or die(mysql_error());
I need the best confess of day order by loves limit 1. This show my only blank, no results.
You're querying records that happened later than one day from now - i.e., in the future. Presumably, you don't have any records like that. You can change the + interval 1 day to - interval 1 day in order to get records that occurred up to 1 day ago.
$q = mysql_query("SELECT * FROM confessions where time >= unix_timestamp(curdate() - interval 1 day)") or die(mysql_error());
EDIT:
To answer the question in the comment, yes, it's possible to sort by loves - hates - just slap on an order by clause:
$q = mysql_query("SELECT * " .
"FROM confessions " .
"WHERE time >= unix_timestamp(curdate() - interval 1 day) " .
"ORDER BY (loves - hates) DESC" ) or die(mysql_error());

Specify PHP code to select dates and records 3 days old

I am trying to call data from SQL table that is only 3 days old
My table has a lbs-date column in it and is date format. I have tried the following but get no result from the query at all
$result = mysql_query("SELECT *, DATE_FORMAT(datetime, '%y,%m,%d') FROM lbs_trace_etrack
WHERE lbs_date(datetime) = CURDATE() - INTERVAL 3 DAY
ORDER BY lbs_date DESC")
Is there any other way I can call only the last 3 days of information from the SQL my date format is Y/M/D
SELECT *, DATE_FORMAT(lbs_date, '%y,%m,%d')
FROM lbs_trace_etrack
WHERE lbs_date >= CURDATE() - INTERVAL 3 DAY
ORDER BY lbs_date DESC
check DATE_FORMAT. Its syntax is DATE_FORMAT(<date>,format) . Use like this :
SELECT *, DATE_FORMAT(lbs_date , '%y,%m,%d') FROM lbs_trace_etrack
WHERE lbs_date = CURDATE() - INTERVAL 3 DAY
ORDER BY lbs_date DESC

mysql query get today and tommrows date

SELECT
doctors. fullname,
dutyroster.date,
dutyroster.time
FROM
dutyroster
INNER JOIN doctors ON doctors.docid = dutyroster.docid
WHERE doctors.docid = $doc_id AND
dutyroster.date = DATE(NOW()) AND DATE(NOW())+ INTERVAL 1 DAY
ORDER BY dutyroster.`date` ASC";
this query is used to find specific doctors information from a table called dutyroster. i want to get the docs shedule information for current day and tommrow only.. but this doesnt work.
and i made a second one which is also not working since it returns current one and all the next dates also
SELECT
doctors. fullname,
dutyroster.date,
dutyroster.time
FROM
dutyroster
INNER JOIN doctors ON doctors.docid = dutyroster.docid
WHERE doctors.docid = $doc_id AND
DATE_SUB(CURDATE(),INTERVAL 2 DAY) <= dutyroster.date
ORDER BY dutyroster.`date` ASC"
Instead of
... AND dutyroster.date = DATE(NOW()) AND DATE(NOW())+ INTERVAL 1 DAY
try
... AND (dutyroster.date = CURDATE() OR
dutyroster.date = CURDATE() + INTERVAL 1 DAY))
or in more concise way, as #MarcM suggested
... AND dutyroster.date IN (CURDATE(), CURDATE() + INTERVAL 1 day)
From your first attempt it almost looks like you are trying to program COBOL!
Also, for future reference "this doesn't work" is not a helpful comment. You should say what actually happens.
Anyway, try changing your where clause to either:
WHERE doctors.docid = $doc_id AND
(dutyroster.date = CURRENT_DATE OR dutyroster.date = CURRENT_DATE + INTERVAL 1 DAY)
or:
WHERE doctors.docid = $doc_id AND
dutyroster.date IN (CURRENT_DATE, CURRENT_DATE + INTERVAL 1 DAY))

SQL Query to show number of stories created in last 24 hours?

I'm trying to create a custom query that will show the number of stories that have been posted in the last 24 hours on a Drupal 6 site.
Stories are stored in the "node" table. each record has a "created" row that records the UNIX timestamp when the story was posted.
Here's the query I'm trying so far:
$sq = 'SELECT COUNT(*) cnt '
. 'FROM {node} c WHERE created >= dateadd(hour,-24,getdate())';
This doesn't appear to be working though. What am I doing wrong?
EDIT: Here's the overall code I'm trying to use right now:
$sq = 'SELECT COUNT(*) AS cnt FROM {NODE} n WHERE FROM_UNIXTIME(n.created) >= DATE_SUB(NOW(), INTERVAL 1 DAY)';
$q = db_query($sq);
while ($o = db_fetch_object($q)) {
print_r($o);
}
That print_r isn't returning anything. Where's my error?
For MySQL, use:
SELECT COUNT(*) AS cnt
FROM NODE n
WHERE FROM_UNIXTIME(n.created) >= DATE_SUB(NOW(), INTERVAL 1 DAY)
Mind that NOW() includes the time when the statement is run. If you want to count records, starting from midnight of the previous day, use:
SELECT COUNT(*) AS cnt
FROM NODE n
WHERE FROM_UNIXTIME(n.created) >= DATE_SUB(CURRENT_DATE, INTERVAL 1 DAY)
Reference:
FROM_UNIXTIME
DATE_SUB
Since you are doing this in PHP, you can just use $_SERVER['REQUEST_TIME']. My guess is that it will be faster than doing date manipulations with SQL:
$count = db_result(db_query("SELECT COUNT(nid) FROM {node}
WHERE created >= %d;", $_SERVER['REQUEST_TIME'] - 86400));
Alternative you could use time to get the current timestamp, but that will be a tiny bit slower than using the $_SERVER['REQUEST_TIME'] variable.

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