Yii passing data back into a model - php

Question

I have been working with Yii for the past few months, but I hit a bit of a block:
In my base controller I have a property public $currentUserOrganisations = NULL; which on load populates it with all the logged in users organizations.
Now I have a page where I get all of the organizations and the user can connect to them, but the ones I already have must say "Connected" rather then have the ability to add. I am using the bootstrap TbGridView widget and in my Organisation model created a function getConnectionAction which either returns the anchor OR a label depending if the organization is already connected to the user.
Here is my problem: I can't find a way to access the already loaded user organizations in the Organisation model, because it is a property on my model class.
See below for code:
Action in controller
public function actionNew()
{
$connectionModel = Connection::model();
$organizationModel = Organisation::model();
$this->selectedSubnav = "Add";
$this->render('new', array("connectionModel" => $connectionModel, "organizationModel" => $organizationModel));
}
Here is the TbGridView in the view:
<?php
$this->widget(
'bootstrap.widgets.TbGridView',
array(
'type'=>'striped',
'enableSorting'=>true,
'id' => 'connection-rest-data',
'dataProvider' => $organizationModel->getConnectionsByOrganization($this->currentOrganisation->id),
'ajaxUpdate' => true,
'template'=>"{pager}<br>\n{items}\n{pager}",
'rowHtmlOptionsExpression' => '',
'emptyText' => Yii::t("site", "no_restults_found") . '.',
"itemsCssClass" => "table table-first-column-number data-table display full dataTable transaction_tbl",
'columns' => array(
array(
'header' => Yii::t("site", "id"),
'value' => '$data->id',
'type' => 'raw',
'name' => 'id'
),
array(
'header' => Yii::t("site", "from_unit"),
'type' => 'raw',
'value' => '$data->fromUnit["name"]',
'name' => 'fromUnit'
),
array(
'header' => Yii::t("site", "to_unit"),
'type' => 'raw',
'value' => '$data->toUnit["name"]',
'name' => 'type'
),
array(
'header' => Yii::t("site", "connection_type"),
'type' => 'raw',
'value' => '$data->type["name"]',
'name' => 'type'
),
array(
'header' => Yii::t("site", "ended"),
'type' => 'raw',
'value' => '$data->ended',
'name' => 'ended'
),
array(
'header' => Yii::t("site", "fees"),
'type' => 'raw',
'value' => 'empty($data->fees) ? "none" : $data->fees["fee"]',
'name' => 'fees'
),
array(
'header' => Yii::t("site", "actions"),
'type' => 'raw',
'value' => 'Organisation::model()->getConnectionAction($data->id, \'' . serialize($this->currentUserOrganisations) . '\'")',
'name' => 'fees'
)
),
)
);
?>
And here is the function in the Organisations Model:
public function getConnectionAction ($connectionId)
{
$currentOrganizations = null; //This I need to get the public $currentUserOrganisations = NULL; value
foreach ($currentOrganizations as $org)
{
if($org->id == $connectionId)
{
return CHtml::label(Yii::t("site", "connected"), "", array("style" => "color:green;"));
}
}
return CHtml::link("Add", "/connection/manage/addConnection?id=$connectionId");
}
Much appreciated guys and give me a shout if anything is unclear!

Answer 1

Ok so I managed a work around which is very close to what Martin said.
In the view for the specific field I do:
'value' => 'Organisation::model()->getConnectionAction($data->id, ' . $this->currentOrganisation->id . ')',
The id is the id of the listed organization and the currentOrganization->id is the id of the users current organization.
Then in my model I get all the organizations for the user:
$currentOrganizations = $this->findAllForUserByOrganizationId($currentOrgId);
Foreach through them and check if they match, full function below.
public function getConnectionAction ($organizationId, $currentOrgId)
{
$currentOrganizations = $this->findAllForUserByOrganizationId($currentOrgId);
foreach ($currentOrganizations as $org)
{
if(in_array($organizationId, array($org->fromUnit['id'], $org->toUnit['id'])))
{
return CHtml::label(Yii::t("site", "connected"), "", array("style" => "color:green;"));
}
}
return CHtml::link(Yii::t("site", "add_connection"), "/connection/manage/addConnection?id=$connectionId", array("class" => "createConnection"));
}

Answer 2

I think you are going to want to avoid Active Record for this one. You can use a CSqlDataProvider to load your TbGridView. Use SQL that looks something like this
select
org.organization_name,
user.name
from organization org
left outer join connection x on org.id = x.organization_id
join user on user.id = x.user_id
where user.id = ? or user.id is null
That ? is a parameter marker to allow you to pass in a user_id in a parameter array rather than just concatenating it. Concatenation provides an opening for SQL injection.
Then in your column list for the gid view test the user.name for null and if null display the add button. If not null, display connected.