PHP Array during echo - php

Question

I have an assignment to do but am having trouble understanding the given psuedocode :/
<?php
$bucket = new array();
print $bucket->addrocks('Rock1')->addrocks('rock2')-
>addrocks('Rock3');
echo "<h1>My Bucket</h1>";
echo "<ul>";
foreach($bucket as $rock){
echo "<li>". $rock ."</li>";
}
echo "</ul>";
?>
Now my trouble starts with understanding how they want me to construct the array after the "print" call? i am not looking for a direct answer to this just maybe a tutorial link or a finger in the right direction
Thank you in advance

Answer 1

In PHP, new is only used for instantiating objects Furthermore, array is a reserved word in PHP, so name your class something else. To instantiate an array in PHP you do this:
$my_array = array();
Now to add items to the array you would do this:
$my_array[] = "Rock 1";
$my_array[] = "Rock 2";
$my_array[] = "Rock 3";
To traverse the array you can use any type of loop, but usually you would just use a foreach loop.
For example:
foreach($my_array as $key => $value) {
echo $value . "<br />";
}

Answer 2

The problem lies in the array construction. This is how one constructs an array in PHP:
one by one:
$bucket = array();
$bucket[] = "Rock1";
$bucket[] = "Rock2";
$bucket[] = "Rock3";
All at once:
$bucket = array("Rock1","Rock2","Rock3");
The documentation: http://php.net/manual/en/language.types.array.php

Answer 3

Well unlikely but may be the array is not an construct but an class in your pseudocode. My assumptions depend on the use of new keyword and the user of -> and addrocks which looks like a method.
So, create a class called array (stupid I know) and get going.
However the user of foreach($bucket) also shows that it expects $bucket to be array. So decide wisely :)
May be use a magic method called __toString() inside the class and return back the array.