PHP: Radiobutton will direct to another page without using a button/submit - php

Question

Scenario:
I have a radio button where when the user click the radio button it will redirect to another page....
So here's my code:
<?php
$radio = mysql_query("SELECT fldNetname FROM tbldata WHERE fldMonth = '$get_month' AND fldWeek = '$get_week' GROUP BY fldNetname ORDER BY fldNetname");
while ($row = mysql_fetch_array($radio)){
echo "<div><input type='radio' name='playRadio' class='chk_boxes1' value='" . $row['fldNetname']."' " .($_POST['playRadio'] == $row['fldNetname'] ? 'checked' : '') . " onClick=\'this.form.action='looptime_utilization_process.php'; this.form.submit()\' >";
echo $row['fldNetname'];"</div>";
}
?>
When I try to run it there is no error yet its not directing to the page I want.
IS there a way that the radio button will be also like a button that can be proceed to another form?
Thanks.

Answer 1

I have corrected all your HTML and PHP mistakes:
<?php
$radio = mysql_query("SELECT fldNetname FROM tbldata WHERE fldMonth = '" . mysql_real_escape_string($get_month) . "' AND fldWeek = '" . mysql_real_escape_string($get_week) . "' GROUP BY fldNetname ORDER BY fldNetname");
while ($row = mysql_fetch_array($radio)) {
?>
<div>
<input type="radio" name="playRadio" class="chk_boxes1" value="<?php echo $row['fldNetname']; ?>"<?php echo ($_POST['playRadio'] == $row['fldNetname'] ? 'checked=" checked"' : ''); ?> onclick="this.form.action='looptime_utilization_process.php'; this.form.submit();">
<?php echo $row['fldNetname']; ?>
</div>
<?php
}
What I changed:
added mysql_real_escape_string(); - better security if your variables are not already escaped
change echo string concatening to close / open <?php tags
changed onClick to onclick (all attributes should be written in lower case in most modern standarts)
changed checked to checked="checked"
corrected wrong quotes in onclick attribute

Answer 2

<form action='looptime_utilization_process.php'>
<input type='radio' name='playRadio' class='chk_boxes1' onClick='form.submit();' >
<form>

Answer 3

Use Javascript
if(document.getElementsByID("playradio").value==<ur value>)
{
param="<ur parameters>";
xmlhttp.open("GET", "looptime_utilization_process.php?".param ,false);
xmlhttp.send();
}

Answer 4

Try this
$trgt=$_POST['playRadio'];
$radio = mysql_query("SELECT fldNetname FROM tbldata WHERE fldMonth = '$get_month' AND fldWeek = '$get_week' GROUP BY fldNetname ORDER BY fldNetname");
while ($row = mysql_fetch_array($radio)){
$v=$row['fldNetname'];
echo "<div><input type='radio' name='playRadio' class='chk_boxes1' value='$v'"
.($trgt == $v ? 'checked' : '')
.' onclick="o=document.forms[0];o.action=\'looptime_utilization_process.php\'; o.submit()" >';
echo "$v</div>";
}
You had some issues with the quotes in your onClick section. Also this does not work there in the way you wanted. I replaced it by document.forms[0], assuming that it is the first form on that page you want to submit and of course, also assuming that the radio buttons are actually inside <form> tags! Change this as required ...
And, of course: placing the action=... context in the onclick section of the radio buttons really only makes sense if the original action of the form pointed to something else which needs to be there for other use cases. Otherwise follow Gary Hayes' advice and put the action attribute into the <form>...</form> tags.