archive php sql date() - php

Question

I've started something I don't know how to finish. I've built a table called 'blog'. In the blog table there is a column, date. I use the date() function to retrieve this column:
"1360225336".
I want Archives by year followed by month:
-2013
9.September
.
.
.
3.March
2.February
1.January
-2012
12.December
.
.
.
3.March
2.February
1.January
<?php
$query_o = mysql_query("SELECT * FROM `blog`")or die(mysql_error());
while($row_o = mysql_fetch_assoc($query_o)){
$new_date_y = date("Y", $row_o[date]);
$new_date_m = date("n", $row_o[date]);
$query_h = mysql_query("SELECT * FROM `blog` where date = $new_date_y ")or die(mysql_error());
while($row_h = mysql_fetch_assoc($query_h)){
$new_date_m1 = date("n", $row_o[date]);
echo'<ul>$new_date_y</ul>';
echo'<li>$new_date_m1</il>';
}
}
?>

Answer 1

Try this
$result = mysql_query("select distinct YEAR(date) as year from blog ") or die(mysql_error());
$years = array();
while($row = mysql_fetch_assoc($result))
$years[] = $row['year'];
$one_year_posts = array();
foreach($years as $year){
echo $year."<br/>";
//echo "select * from blog where YEAR(date) = '$year'";
$result1 = mysql_query("select * from blog where YEAR(date) = '$year'") or die(mysql_error());
while($row1 = mysql_fetch_assoc($result1))
$one_year_posts[] = $row1;
foreach($one_year_posts as $post){
//echo $post['date']."<br>";
$months.= date('m F',strtotime($post['date'])).", ";
}
echo $months = rtrim($months," ,");
}

Answer 2

Try this query:
SELECT * FROM `blog` GROUP BY YEAR(`Date`), MONTH(`Date`);
If you also need day, just add , DAY(`Date`) at the end.

Answer 3

$result = mysql_query("select distinct FROM_UNIXTIME(date,'%Y') as year from blog ") or die(mysql_error());
$years = array();
while($row = mysql_fetch_assoc($result))
$years[] = $row['year'];
$one_year_posts = array();
foreach($years as $year){
echo "<br/>-".$year."<br/>";
$result = mysql_query("select * from blog where FROM_UNIXTIME(date,'%Y') = '$year'") or die(mysql_error());
while($row = mysql_fetch_assoc($result))
$one_year_posts[] = $row;
foreach($one_year_posts as $post){
echo strftime('%d %B',$post['date']).", ";
}
}
Note: Use mysqli_ instead of mysql_ functions. The latter is deprecated and no longer maintained.

Answer 4

after trying a lot of new thing finally i succeed
<?php
$result = mysql_query("select distinct FROM_UNIXTIME(date,'%Y') as year from blog ") or die(mysql_error());
$years = array();
while($row = mysql_fetch_assoc($result))
$years[] = $row['year'];
$one_year_posts = array();
foreach($years as $year){
$result1 = mysql_query("select distinct FROM_UNIXTIME(date,'%M') as m from blog where FROM_UNIXTIME(date,'%Y') = '$year'") or die(mysql_error());
$ms = array();
while($row1 = mysql_fetch_assoc($result1))
$ms[] = $row1['m'];
$one_year_posts = array();
foreach($ms as $m){
$date= $year;
$date.= " ";
$date.= $m;
echo <<<PRINT
<li><a href='search.php?archie=$date'>$date</a></li>
PRINT;
}
}
?>