How to store data in db in array form - php

i want to store my PHP values in db(mysql) in the form of array...
for example
$a=array{10,20,30,40};
i want to store this variable $a in to db in the array form like how it's storing in array using index.
why i want to do this because in future i may have to perform update or delete operation on the array values..
i know that it's possible to do this thing... but i don't know how to implement this..
i searched about this topic but i didn't get proper answer....
Please suggest me how to do this things...

Why don't use json_encode in PHP and store it on your database. It's the best way.
The array will be converted to a string and will be stored.
Retrieve the data and make use of json_decode and then start working as per your needs.
Example:
<?php
$arr = array('a' => 1, 'b' => 2, 'c' => 3, 'd' => 4, 'e' => 5);
echo json_encode($arr);
?>
OUTPUT: {"a":1,"b":2,"c":3,"d":4,"e":5}

You should create a distinct TABLE to store this kind of data.
Consists of 2 columns, corresponding record ID and the actual data.
So, your record will be looks like
rid value
1 10
1 20
1 30
1 40
2 10
2 40
...
this way you will be able to perform update or delete operation on the array values using conventional SQL routines, as well as selecting data based on the array values.
This is how the things done oin the real world, not in PHP sandbox.
All othe answers here are plainly wrong

I would use serialize/unserialize for this. You can use it like this:
Send to MySQL
<?php
$a = array{10,20,30,40};
$a = serialize($a);
// your code here to send it to the mysql
?>
Get from MySQL
<?php
// your code here to collect it from mysql
$a = unserialize($mysql->str);
?>
The field in the MySQL should be TEXT or VARCHAR.
Regards
BlackBonjour

You can always serialize your array then store the result in a VARCHAR or TEXT field and after fetching you can unserialize the field.

Related

JSON data handling with mySQL and php

For the past 2 days I have been looking over the internet on how to handle data stored as json in mySQL database.All I found was a single article in here which I followed with no luck.So here is my question
This is my table called additional with 2 columns only...jobid and costs. jobid is an int of length 5 and obviously the primary key, costs is simply stored as text. Reason I combined all the costs under one column is because the user in my application can put whatever he/she wants in there, so to me the costs is/are unknown. For example one entry could be
24321 , {"telephone" : "$20"}
or
24322 , {"telephone" : "$20", "hotel" : "$400"}
and so on and so forth but I hope you get the point.
Now given this example I need to know how to handle data in and out from the database stored as json using php. So insert, select and update but I think with one given example I can do the rest If someone can help me understand how to handle json data in and out from a database.
Oh and one last thing. Not only I need to know how to fetch the data I need to be able to separate it too e.g:
$cost1 = {"telephone" : "$20"};
$cost2 = {"hotel" : "$400"};
I really hope someone can help with this because like I said above I spent 2 days trying to get my head around this but either no articles on this matter(except the one from this site) or completely irrelevant to my example
You tagged it as PHP so you can use php functions: json_encode and json_decode.
For example when you read (SELECT) and got this cost value in string corresponding to the primary key 24322:
//after you query db and got the cost in string...
$sql = "SELECT * FROM additional";
$result = mysqli_query($conn,$sql); $row = mysqli_fetch_array($result);
//from your comment below.... just changed to $cost so I don't have to change everything here...
$cost = $row['costs'];
//$cost = '{"telephone" : "$20", "hotel" : "$400"}'
//you just have to:
$cost = json_decode($cost);
// result in an object which you can manipulate such as:
print_r($cost->telephone);
// $20 or:
print_r($cost->hotel);
//$400;
//or if you want to go through all of the costs... you change that to array:
$cost = (array)$cost; //or on your json_decode you add a TRUE param... ie(json_decode($cost, TRUE))...
print_r($cost);
//will produce an associative array: ['telephone'=>'$20', 'hotel'=>'$400']
//for which you can do a foreach if you want to go through each value...
On the other hand when you save to db with an object:
$cost = (object)['hotel'=>'$300', 'taxi'=>'$14'];
//you json_encode this so you can write to db:
$cost = json_encode($cost);
//a string... you can then use $cost to write to db with (insert, update, etc)
Note: json_decode needs the input string to be UTF-8 encoded. So you might need to force your mysql server to provide UTF-8. Some reading: https://www.toptal.com/php/a-utf-8-primer-for-php-and-mysql
Hope this helps...
You can use json_encode() and json_decode() throughout your update or insert process.
Basically
json_encode() takes Array and returns JSON as String
json_decode() takes JSON as String and returns Array
http://php.net/manual/en/function.json-encode.php
So in your case whenever you want to update 24321 , {"telephone" : "$20"}
you got to decode like
$array = json_decode($row['jsonDataOrWhateverTheColumnNameIs'],true);
$array['telephone'] = "40$";
...
...
$jsonString = json_encode($array); // Use this string with your update query.

Is it possible to hide the real column name from a table during json_encode time?

I am encoding a php array into json format which have data from a table.
My json_encode produces result with real column name of that table.I want to use the real column name in php side and after it encode to json format I will like to use some other custom name so, that if some user checks in .js file it won't be any problem for me.Below code is the result of json_encode.
What is now :-
{"result":[{"pals_id":"20","from_user":"hancy061","to_user":"hari061","username":"hancy061"}
What I want :-
{"result":[{"pid":"20","fu":"hancy061","tu":"hari061","un":"hancy061"}
Ya, there isn't any need to show user column name and it seems unsecure too.You guys can see what i want have the json_encode format which I want it to be.Is it possible from php side?I mean in php side before encoding the array into json format can we first make custom name of those columns?
You cannot safely replace these columns on the client-side, because it will be available to a user somehow. If you want a user to never learn how your columns are actually named, you should do this at the server-side.
The most common way is to use SQL aliases.
In your PHP change your SQL query to the following:
SELECT pals_id AS pid, from_user AS fu, to_user AS tu, username AS un FROM YourTable ...
However, that's a security through obscurity and doesn't provide any safety.
If you have an SQL-injection vulnerability, then a hacker will be able to query your data structure from system tables or simply SELECT *.
You could also manually set the array keys in the format you want before encoding, like:
foreach ($result as $ind => $r) {
$result[$ind] = [ // For PHP Versions < 5.4 use 'array('
"pid" => $r['pals_id'],
"fu" => $r['from_user'],
"tu" => $r['to_user'],
"un" => $r['username'],
]; // For PHP Version < 5.4 use ');'
}
However you would then have to reverse this if data were to be sent back to the server from the client for updates or something.
If that is needed, then you could set up a map to switch between the two.

Merging several MySQL results into a single JSON encode (PHP)

Here is code as exists now:
while($row=mysql_fetch_assoc($count_query_result))
$output[]=$row;
while($row=mysql_fetch_assoc($average_query_result))
$output2[]=$row;
while($row=mysql_fetch_assoc($items_query_result))
$output3[]=$row;
print(json_encode(array($output,$output2,$output3)));
mysql_close();
My question:
How do I take a single column from each of the three query results, and make a JSON array out of it, like so:
[{ 'att1' : 'data'}, { 'att2' : 'data'}, { 'att3' : 'data'}]
ASSUMING:
att1 came from the $count_query_result/$output
att2 came from the $average_query_result/$output2
att3 came from the $items_query_result/$output3
Therefore, encoding only one variable, not 3.
Well I answered my own issue. I had to get to the very root of the problem. The MySQL queries. I have joined them all so now there is just one. This creates a single JSON array for what I need. I believe there is something to be said about just doing it ... right .. the first time.
$result = array('att1' => $row['data'],
'att2' => $row['data']
echo json_encode($result)
where $row['data'] is the information that you want returned from each of your queries

Save array in mysql database

I want to save extra information before sending the total order to Paypal. For each item I have created a single column in my MySQL database where I want to store it. Now I was thinking to save it as an array which I can read later for creating a PHP page. Extra fields are taken from input form fields.
By using an array can I be sure not to mixup information?
You can store the array using serialize/unserialize. With that solution they cannot easily be used from other programming languages, so you may consider using json_encode/json_decode instead (which gives you a widely supported format). Avoid using implode/explode for this since you'll probably end up with bugs or security flaws.
Note that this makes your table non-normalized, which may be a bad idea since you cannot easily query the data. Therefore consider this carefully before going forward. May you need to query the data for statistics or otherwise? Are there other reasons to normalize the data?
Also, don't save the raw $_POST array. Someone can easily make their own web form and post data to your site, thereby sending a really large form which takes up lots of space. Save those fields you want and make sure to validate the data before saving it (so you won't get invalid values).
The way things like that are done is with serializing the array, which means "making a string out of it". To better understand this, have a look on this:
$array = array("my", "litte", "array", 2);
$serialized_array = serialize($array);
$unserialized_array = unserialize($serialized_array);
var_dump($serialized_array); // gives back a string, perfectly for db saving!
var_dump($unserialized_array); // gives back the array again
Use the PHP function serialize() to convert arrays to strings. These strings can easily be stored in MySQL database. Using unserialize() they can be converted to arrays again if needed.
To convert any array (or any object) into a string using PHP, call the serialize():
$array = array( 1, 2, 3 );
$string = serialize( $array );
echo $string;
$string will now hold a string version of the array. The output of the above code is as follows:
a:3:{i:0;i:1;i:1;i:2;i:2;i:3;}
To convert back from the string to the array, use unserialize():
// $array will contain ( 1, 2, 3 )
$array = unserialize( $string );
<?php
$myArray = new array('1', '2');
$seralizedArray = serialize($myArray);
?>
Store it in multi valued column with a comma separator in an RDBMs table.
You can use MySQL JSON datatype to store the array
mysql> CREATE TABLE t1 (jdoc JSON);
Query OK, 0 rows affected (0.20 sec)
mysql> INSERT INTO t1 VALUES('{"key1": "value1", "key2": "value2"}');
Query OK, 1 row affected (0.01 sec)
To get the above object in PHP
json_encode(["key1"=> "value1", "key2"=> "value2"]);
More in https://dev.mysql.com/doc/refman/8.0/en/json.html

Format data being read in by CakePHP read() function

I am using CakePHP to display an input field that has a "price" variable in it upon editing. Coming from the database this number has a 5 decimal points (for complex calculations).
Without setting the column in the database to be set to only float to 2 points, how would I go about converting this variable to float to only 2 points?
<?php echo $form->input('price'); ?>
Please let me know if you need any further information from me.
Did you specify a model when you did your $form->create('Model');
You should be able to manipulate the $this->data by specifying the Model and field.
<?php echo $form->text('price',
array('value' => round($this->data['Model']['price'], 2)));

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