opening two folders and displaying images php - php

Question

I've got the problem of trying to display two albums of photos from a db using php. Currently the following code works but for just one album. Basically I need it to display photos from 'mount-everest-part-2' aswell.
<?php
$path = "images/galleries/";
$album = 'mount-everest-part-1';
if ($handle = opendir($path.$album.'/thumbs/')) {
while (false !== ($file = readdir($handle))) {
if ($file != "." && $file != ".." && substr($file, 0, 2) != '._') {
$files[] = $file;
}
}
closedir($handle);
}
asort($files);
foreach($files as $file) {
echo '<li><img src="../' . $path . $album . '/thumbs/' . $file . '" /></li>';
}
?>
How can I use this code to open two files and spit the files out using the same foreach loop?

Answer 1

This sounds like one of those things that OOP would suit nicely. Here's an example:
<?php
class Album_Picture_File {
private $fileName;
private $path;
private $album;
public function __construct($fileName, $path, $album) {
$this->fileName = $fileName;
$this->path = $path;
$this->album = $album;
}
private function getAlbumPath() {
return '../' . $this->path . $this->album;
}
public function getPicturePath() {
return $this->getAlbumPath() . '/images/' . $this->fileName;
}
public function getThumbnailPath() {
return $this->getAlbumPath() . '/thumbs/' . $this->fileName;
}
}
function fetchFiles($path, $album) {
$files = array();
if ($handle = opendir($path.$album.'/thumbs/')) {
while (false !== ($file = readdir($handle))) {
if ($file != "." && $file != ".." && substr($file, 0, 2) != '._') {
$fullPath = $path . $album . '/thumbs/' . $file;
$files[$fullPath] = new Album_Picture_File($file, $path, $album);
}
}
closedir($handle);
}
ksort($files); //sort after key (out file path)
return $files;
}
$files = array_merge(
fetchFiles('images/galleries/', 'mount-everest-part-1'),
fetchFiles('images/galleries/', 'mount-everest-part-2')
);
foreach($files as $file) {
echo '<li><img src="' . $file->getThumbnailPath() . '" /></li>';
}
?>
Note that instead of pushing $files with strings, we push it with Album_Picture_File objects.

Answer 2

Create a global array :
$all = array();
Then, make 2 loops and push the global array (create a function that reads the directory for example)
$files_dir_one = getFiles("your_dir");
$files_dir_two = getFiles("your_dir2");
$all = array_merge($files_dir_one, $files_dir_two);
function getFiles($directory) {
$files = array();
if ($handle = opendir($directory)) {
while (false !== ($file = readdir($handle))) {
if ($file != "." && $file != ".." && substr($file, 0, 2) != '._') {
$files[] = $file;
}
}
closedir($handle);
}
//asort($files);
return $files;
}
And then, the last step : populate the view

Answer 3

How can I use this code to open two files and spit the files out using the same foreach loop?
Taking your question literally it works like this. First of all extract a function with the two input variables:
/**
* #param string $path
* #param string $album
*/
function list_images($path, $album) {
$files = [];
if ($handle = opendir($path . $album . '/thumbs/'))
{
while (false !== ($file = readdir($handle)))
{
if ($file != "." && $file != ".." && substr($file, 0, 2) != '._')
{
$files[] = $file;
}
}
closedir($handle);
}
asort($files);
foreach ($files as $file)
{
echo '<li><img src="../' . $path . $album . '/thumbs/' . $file . '" /></li>';
}
}
Then you can just iterate over your two albums and output both:
$path = "images/galleries/";
$albums = ['mount-everest-part-1', 'mount-everest-part-2'];
foreach ($albums as $album)
{
list_images($path, $album);
}