again , sorry for asking so many questions.
I currently have this code:
foreach (glob("black/*") as $filename)
problem is that it doesnt include folders inside the folder "black".
Any way to work that out?
Full code:
foreach (glob("black/*") as $filename)
if(ftp_put($conn, $ftpFolder . basename($filename) , $filename, FTP_BINARY)) {
and then goes the response,
Thanks in advance :)
P.S
My goal is that I want the script to upload whole bunch of files,folders and sub folders.
You can try a recursive solution:
function print_files($dir){
foreach (glob("$dir/*.txt") as $filename) {
echo "$filename size " . filesize($filename) . "\n";
}
// call recursively for every sub directory
foreach (glob('$dir/*', GLOB_ONLYDIR) as $subdirs) {
print_files($subdirs);
}
}
print_files("black");
Disclaimer:
It was written with Notepad - I can't test it...
Related
I have been trying to reach some files thru glob with the extension .vic thru php file_get_contents.
The problem I ran into is that it does not work.
My code:
<?php
$fileList = glob('*.vic');
echo $_SERVER['DOCUMENT_ROOT'] .'/server/main/';
foreach($fileList as $filename) {
echo file_get_contents($_SERVER['DOCUMENT_ROOT'].'/server/main/' . $filename) . "\r\n";
}
When I run it echo's the folder I need but the file content doesn't show up.
There is a .vic file in the folder with file contents.
Did I do something wrong or is this not posible
PHP Output:
C:/xampp/htdocs/server/main/
Try:
$fileList = glob($_SERVER['DOCUMENT_ROOT'] .'/server/main/*.vic');
I´m building a php programm which uploads a zip file, extracts it and generates a link for a specific file in the extracted folder. Uploading and extracting the folder works fine. Now I´m a bit stuck what to do next. I have to adress the just extracted folder and find the (only) html file that is in it. Then a link to that file has to be generated.
Here is the code I´m using currently:
$zip = new ZipArchive();
if ($zip->open($_FILES['zip_to_upload']['name']) === TRUE)
{
$folderName = trim($zip->getNameIndex(0), '/');
$zip->extractTo(getcwd());
$zip->close();
}
else
{
echo 'Es gab einen Fehler beim Extrahieren der Datei';
}
$dir = getcwd();
$scandir = scandir($dir);
foreach ($scandir as $key => $value)
{
if (!in_array($value,array(".",".."))) //filter . and .. directory on linux-systems
{
if (is_dir($dir . DIRECTORY_SEPARATOR . $value) && $value == $folderName)
{
foreach (glob($value . "/*.html") as $filename) {
$htmlFiles[] = $filename; //this is for later use
echo "<a href='". SK_PICS_SRV . DIRECTORY_SEPARATOR . $filename . "'>" . SK_PICS_SRV . DIRECTORY_SEPARATOR . $filename . "</a>";
}
}
}
}
So this code seems to be working. I just noticed a rather strange problem. The $zip->getNameIndex[0] function behaves differently depending on the program that created the zip file. When I make a zip file with 7zip all seems to work without a problem. $folderName contains the right name of the main folder which I just extracted. For example "folder 01". But when I zip it with the normal windows zip programm the excat same folder (same structure and same containing files) the $zip->getNameIndex[0] contains the wrong value. For example something like "folder 01/images/" or "folder 01/example.html". So it seems to read the zip file differently/ in a wrong way. Do you guys know where that error comes from or how I can avoid it? This really seems strange to me.
Because you specify the extract-path by yourself you can try finding your file with php's function "glob"
have a look at the manual:
Glob
This function will return the name of the file matching the search pattern.
With your extract-path you now have your link to the file.
$dir = "../../suedkurier/werbung/"
$scandir = scandir($dir);
foreach ($scandir as $key => $value)
{
if (!in_array($value,array(".",".."))) //filter . and .. directory on linux-systems
{
if (is_dir($dir . DIRECTORY_SEPARATOR . $value))
{
foreach (glob($dir . DIRECTORY_SEPARATOR . $value . "/*.html") as $filename) {
$files[] = $value . DIRECTORY_SEPARATOR $filename;
}
}
}
}
The matched files will now be saved in the array $files (with the subfolder)
So you get your path like
foreach($files as $file){
echo $dir . DIRECTORY_SEPARATOR . $file;
}
$dir = "the/Directory/You/Extracted/To";
$files1 = scandir($dir);
foreach($files1 as $str)
{
if(strcmp(pathinfo($str, PATHINFO_EXTENSION),"html")===0||strcmp(pathinfo($str, PATHINFO_EXTENSION),"htm")===0)
{
echo $str;
}
}
Get an array of each file in the directory, check the extension of each one for htm/html, then echo the name if true.
Hi wonder if you can help,
I'm looking to do this in PHP if someone can help me. I have a number of files that look like this:
"2005532-JoePharnel.pdf"
and
"1205121-HarryCollins.pdf"
Basically I want to create a PHP code that when someone ftp uploads those files to the upload folder that it will 1) Create a directory if it doesn't exist using there name 2) Move the files to the correct directory (E.g. JoePharnel to the JoePharnel Directory ignoring the number at the beginning)
I have looked through alot of code and found this code and have adapted it:
<?php
$attachments = array();
preg_match_all('/([^\[]+)\[([^\]]+)\],?/', $attachments, $matches, PREG_SET_ORDER);
foreach ($matches as $file) {
$attachments[$file[1]] = $file[2];
}
foreach ($attachments as $file => $filename) {
$uploaddir = "upload" . $file;
$casenumdir = "upload/JoePharnel" . $CaseNumber;
$newfiledir = "upload/JoePharnel" . $CaseNumber .'/'. $file;
$each_file = $CaseNumber .'/'. $file;
if(is_dir($casenumdir)==false){
mkdir("$casenumdir", 0700); // Create directory if it does not exist
}
if(file_exists($casenumdir.'/'.$file)==false){
chmod ($uploaddir, 0777);
copy($uploaddir,$newfiledir);
}
$allfiles = $CaseNumber .'/'. $file . "[" . $filename . "]" . ",";
$filelistfinished = preg_replace("/,$/", "", $allfiles);
echo $filelistfinished;
// displays multiple file attachments on the page correctly as: casenumber/testfile1.pdf[testfile1.pdf],casenumber/testfile2.pdf[testfile2.pdf],
],
}
?>
Sorry for the lack of code but best i could find.
Any help is much appreciated.
Thanks.
I have folders that have one file in each.
I am trying to read the name of that file and pass to variable in php.
foreach(glob('photos/folder_name/thumbs') as $filename)
{echo $filename;}
Using the above script, no data is returned for $filename. Any thoughts?
Thanks.
You need to use wildcards in the string you give to glob.
<?php
foreach (glob("*.txt") as $filename) {
echo "$filename size " . filesize($filename) . "\n";
}
?>
Beginner : I cant seem to get my head around the logic of it. Have searched but seems to come up with listing files and folders from an actual directory ie. (opendir).
My problem is :
Im trying to work out (in PHP) how to list files and subfolders from a path stored in a database. (Without any access to the file or dir, so just from the path name)
For example database shows:
main/home/television.jpg
main/home/sofa.jpg
main/home/bedroom/bed.jpg
main/home/bedroom/lamp.jpg
So if i specify main/home - it shows: television.jpg, sofa.jpg and the name of the subfolder : bedroom.
scanFolder('main/home');
function scanFolder($dir) {
foreach (scandir($dir) as $file) {
if (!in_array($file, array('.', '..'))) {
if (is_dir($file)) {
scanFolder($dir . '/' . $file);
}
else {
echo $dir . '/' . $file . "\n";
}
}
}
}
You would probably want to check on each iteration if the filename is a directory or not. If it is, open it up and read its contents and output them. A recursive function would work best in this situation.
http://php.net/manual/en/function.is-dir.php