How to get video.mp4 from vine url?
Example:
from https://vine.co/v/hnVVW2uQ1Z9
I need http://.../*.mp4 and http://.../*.jpg
Script what I need use this page vinebed.com
(In PHP)
Thanks much.
It's very simple. if you check the source of a vine video from vine.co you'll see the meta tags. and you should see twitter:player:stream. By using php you can extract that information specifically and use it like a variable.
<?php
function vine( $id )
{
$vine = file_get_contents("http://vine.co/v/{$id}");
preg_match('/property="twitter:player:stream" content="(.*?)"/', $vine, $matches);
$url = $_SERVER['REQUEST_URI'];
return ($matches[1]) ? $matches[1] : false;
}
?>
And to set an $id you will need to create a function that will either A) Automatically read a vine video id by url and you can display it like this <?php echo vine('bv5ZeQjY35'); ?> or B) Just set a vine video id and display as is.
Hope this helps as it's worked for me just fine.
Related
I have a website that hosts videos from a client. On the website the files load externally via m3u8 link.
The client would now like to have those videos on a Roku channel.
If I simply use the m3u8 link from the site it gives an error because the url generated is sent with a cookie and so a client must click and the link to generate a new code for them.
I would like if possible (and I have not seen this here) is to scrape the html page and just return the link via PHP script on the website from the Roku.
I know how to get titles and such using pure php but am having problems returning the m3u8 link..
I do have code to show I am not looking for handouts and actually am trying.
This is what I have used for getting the title name for example.
Note: I would like to know if it is possible to have one php that autofills the html page per url so I do not have to use a different php for each video with the url pretyped in.
<?php
$html = file_get_contents('http://example.com'); //get the html returned from the following url
$movie_doc = new DOMDocument();
libxml_use_internal_errors(TRUE); //disable libxml errors
if(!empty($html)){ //if any html is actually returned
$movie_doc->loadHTML($html);
libxml_clear_errors(); //remove errors for yucky html
$movie_xpath = new DOMXPath($movie_doc);
//get all the titles
$movie_row = $movie_xpath->query('//title');
if($movie_row->length > 0){
foreach($movie_row as $row){
echo $row->nodeValue . "<br/>";
}
}
}
?>
There is a simple approach for this, which involves using regex.
In this example let's say the video M3u8 file is located at: http://example.com/theVideoPage
You would point the video URL Source in your XML to your PHP file.
http://thisPhpFileLocation.com
<?php
$html = file_get_contents("http://example.com/theVideoPage");
preg_match_all(
'/(http.*m3u8)/',
$html,
$posts, // will contain the article data
PREG_SET_ORDER // formats data into an array of posts
);
foreach ($posts as $post) {
$link = $post[0];
header("Location: $link");
}
?>
Now if you want to use a URL that you can append a URL link at the end it could look something like this and you would use an address as such for a Video Url located at
http://thisPhpFileLocation.com?id=theVideoPage
<?php
$id = $_GET['id'];
$html = file_get_contents("http://example.com".$id);
preg_match_all(
'/(http.*m3u8)/',
$html,
$things, // will contain the article data
PREG_SET_ORDER // formats data into an array of posts
);
foreach ($things as $thing) {
$link = $thing[1];
// clear out the output buffer
while (ob_get_status())
{
ob_end_clean();
}
// no redirect
header("Location: $link");
}
?>
I want to get thumbnail of facebook videos from a given video ID .
I use the preg_match function to get facebook video ID from a given url retrieved from database
preg_match("~/videos/(?:t\.\d+/)?(\d+)~i", $value->url, $matches);
$video_id = $matches[1];
echo ' <div class="fb-video" data-href="https://www.facebook.com/facebook/videos/'.$video_id.'/"></div>';
I want to posted on website with something like this:
<img src="VIDEO_IMAGE.<?php echo $video_id ?>.jpg">
I don't know if it' posssible? !
Your image source is wrong try using
<img src="https://graph.facebook.com/VIDEO_ID/picture" />
Example : https://graph.facebook.com/10153231379946729/picture
This is my code :
$patt = "#href=\"(.*?)\"#";
preg_match($patt,$data,$match);
echo $match[1];`
i.e. theres a URL in the HTML code of the page $data
<a href="http://aba.ai/iEU9x">
I want to grab this link above. Thanks
I'm trying to do a PHP page to shows an album cover via Last.FM API. However, the Artist Name and the Title of the music are provided by a XML file that a software updates via FTP.
Here is the code of Last.FM api:
<?php
$img = simplexml_load_file('http://ws.audioscrobbler.com/2.0/?method=track.getInfo&api_key=<APIKEY>&artist=cher&track=believe');
echo '<img src="';
echo $img->track[0]->album[0]->image[3];
echo '">';
?>
Now the link of my XML file is: http://summerblast.pt/avaplayer/rds.xml
The info I need to the Last.FM API is in 'OnAir/CurMusic'.
Well, what I am trying to do is change "Cher" and "Believe" (the artist's name and the Title's name) in the link of the "simplexml_load_file" (in the php code) with the info that my XML file provides.
Can you please help me doing this?
Thank you all in advance.
Sorry was confused to what you were asking from before. I have gone ahead and corrected to do what you wanted.
You can get the Artist and the Title from rds.xml and just pass it to the URL like the following listed below (note it is important to run urlencode on them since they can have spaces and other things to break the URL):
Updated to do error checking
$xml = simplexml_load_file('http://summerblast.pt/avaplayer/rds.xml');
$artist = urlencode($xml->OnAir->CurMusic->Artist);
$track = urlencode($xml->OnAir->CurMusic->Title);
$url = 'http://ws.audioscrobbler.com/2.0/?method=track.getInfo&api_key=XXXXXXXXXXXXXXXXXXXXXXXXXXX&artist='.$artist.'&track='.$track;
$xml2 = #simplexml_load_file($url);
if ($xml2 === false)
{
echo("Url failed"); // do whatever you want to do
}
else
{
if($xml2->track->album->image[3])
{
echo '<img src="';
echo((string) $xml2->track->album->image[3]);
echo '">';
}
else
{
echo("artist does not have a image"); // do whatever you want to do
}
}
How can I get the title of an HTML page using php? I've made a php web crawler and I want to implement this feature into my crawler so that it will have the name of the page and the url. Thanks in advance. Possibly using preg_match.
Would this help?
$myURL = 'http://www.google.com';
if (preg_match(
'/<title>(.+)<\/title>/',
file_get_contents($myURL),$matches)
&& isset($matches[1] )
$title = $matches[1];
else
$title = "Not Found";