Google Analytics API: How to get all Report ID - php

Question

I want to select all the Report ID of all the added URLs in the Google Analytics account.
How can I do something like this?
SELECT report_id FROM google_analytics_account
Example URLs in the Google Analytics account:
https://www.google.com/analytics/web/?hl=en#home/a3456789w2345678p1234567/
https://www.google.com/analytics/web/?hl=en#home/a3456789w2345678p9876543/
Where the Report IDs there are 1234567 and 9876543.
Can I do that using the GAPI class only? How?
I have a gapi class.
<!-- language: lang-php -->
require_once 'gapi.class.php';
$ga = new gapi('my_test_email#gmail.com', 'my_test_email_password');
$report_id = 1234567;
$dimensions = array('browser', 'browserVersion');
$metrics = array('pageviews', 'visits');
$sort_metric = null;
$filter = null;
$start_date = null;
$end_date = null;
$start_index = 1;
$max_results = 30;
$ga->requestReportData(
$report_id,
$dimensions,
$metrics,
$sort_metric,
$filter,
$start_date,
$end_date,
$start_index,
$max_results
);
foreach ($ga->getResults() as $result) {
echo '<strong>'.$result.'</strong><br />';
echo 'Pageviews: ' . $result->getPageviews() . ' ';
echo 'Visits: ' . $result->getVisits() . '<br />';
}
echo '<p>Total pageviews: ' . $ga->getPageviews() . ' total visits: ' . $ga->getVisits() . '</p>';
echo '<font color="blue"><pre>',print_r($ga->getResults()),'</pre></font>';
echo '<hr />';
Thanks! :)

Answer 1

You can add a filter to your request. something like this should do
ga:landingPagePath%3D#ReportID=1234567,ga:pagePath%3D#ReportID=9876543
I'm not sure if its ga:pagePath or ga:landingPagePath that you will need to use check your google analytic's see which page it is you where looking at. Its probably ga:landingPagePath you want.
Also the , is an OR seproator so if you want to add more of them just add another with a ,.