I'm trying to select values from row 85 in this while loop.
So all values that are selected in the database before row 85 should be excluded in the while loop, and everyone above 85 should be "Do Something" with.
Any suggestions how to achieve this?
$to_emails = mysql_query("SELECT * FROM ".$DBprefix."users WHERE workouts > 10");
while ($to_email = mysql_fetch_array($to_emails)) {
// Do Something
}
Look here:
To retrieve all rows from a certain offset up to the end of the
result set, you can use some large number for the second parameter.
This statement retrieves all rows from the 96th row to the last:
SELECT * FROM tbl LIMIT 95,18446744073709551615;
http://dev.mysql.com/doc/refman/5.0/en/select.html
So try something like this:
$to_emails = mysql_query("
SELECT * FROM ".$DBprefix."users
WHERE workouts > 10
LIMIT 85,18446744073709551615");
Try like
$to_emails = mysql_query("SELECT * FROM ".$DBprefix."users WHERE workouts > 10 LIMIT 85,200");
Or even try like(May be it works)
$to_emails = mysql_query("SELECT * FROM ".$DBprefix."users WHERE workouts > 10 LIMIT 85,(SELECT COUNT(*) FROM ".$DBprefix."users");
Related
This is my code.
$sqlcount = "SELECT count(*) AS C, Horse_ID FROM images WHERE Horse_ID = 24 GROUP BY Horse_ID HAVING COUNT(*) > 1 LIMIT 0, 30";
//echo $sqlcount;
$resultcount = $conn->query($sqlcount);
$rowcount = $result->fetch_assoc();
echo $rowcount['C'];
Why won't it echo the number 4, which is what shows when I test it in phpmyadmin? There are 4 duplicate values in that table hence the 4.
$rowcount = $result->fetch_assoc();
to
$rowcount = $resultcount->fetch_assoc();
If you want the number of duplicates in the database, why not write the query to get that value?
SELECT COUNT(*)
FROM (SELECT count(*) AS C, Horse_ID
FROM images
WHERE Horse_ID = 24
GROUP BY Horse_ID
HAVING COUNT(*) > 1
) i;
Then, you will only be returning one value from the database to the application (which is faster) and there is no need to artificially limit the count to 30.
When I run the following query in Phpmyadmin it returns 10 records, like it should
SELECT * FROM sku WHERE sku LIKE '142-401-117-282%'
But when I run the same query in my Php script, I get all the rows from the table
$sql = "SELECT * FROM sku WHERE sku LIKE '142-401-117-282%' ";
$result = $con->query($sql);
while($row = mysqli_fetch_array($result)){
echo $row['sku']."<br>";
}
I'm selecting all the SKU's that start with 142-401-117-282, after come a - plus the size of the item
How do I get the 10 rows that I need?
Try:
$sql = "SELECT * FROM sku WHERE sku LIKE '142-401-117-282%' LIMIT 0,10";
where 0 is starting row position and 10 is its length.
I've been looking for this for a while but with no success.
I am trying to implement a recomendation bar, for example like in youtube, when you are seeing a video it shows the list or recommended videos on the right.
At this moment I am using this method:
$offset_result = mysql_query( " SELECT FLOOR(RAND() * COUNT(*)) AS `offset` FROM `$tablename` ");
$offset_row = mysql_fetch_object($offset_result );
$offset = $offset_row->offset;
$result_rand = mysql_query( " SELECT * FROM `$tablename` LIMIT $offset, 9 " );
This works fine, but sometimes doesn't show any result, and the problem is also that its not completely random, because it shows for example the first ID as 200, so the next result will be id 201 and then 202 and so.
I would like to know if there is a way to show this 9 randon results, for example 1º result id 500, 2º result id 10, 3º result id 788, etc etc?
Thank you
Not entirely sure this answers what you are looking for, but try:
$result_rand = mysql_query("SELECT * FROM " . $tablename . " ORDER BY RAND() LIMIT 9");
You can use php rand() function to create 5 numbers and save them in an array:
http://php.net/manual/en/function.rand.php
<?php
$rand_array = array();
for($i=1;$i<5;$i++) {
$rand_array[$i] = rand(0,500);
}
?>
and after that create a query with every int with a foreach loop and work with your data.
<?php
foreach ($rand_array as $integer) {
$q = "SELECT * from $tablename WHERE id='$integer';";
}
?>
Does this helps?
First you should use mysqli_ functions instead of mysql_ because the latter is deprecated. Second use order by rand() to get random rows:
$rand_result = mysqli_query( "SELECT * FROM $tablename ORDER BY RAND() LIMIT 9;" );
UNTESTED:
SELECT id, #rownum:=#rownum+1 AS rownum, name
FROM users u,
(SELECT #rownum:=0) r
THis will give a unique number to each row in sequence. Now if you create a temp table with 9 random numbers between 1 and count(*) of your table and JOIN those two together...
Not sure about performance but seems like it might be faster than Rand and order by since I only need 9 random numbers
I have the selecting from the last ten entries working, but am unsure how to get the most popular from these ten entries? Also how would I count the number of the most popular entry & output it to a percentage?
<?php
$sql = "SELECT data FROM table_answers ORDER BY id DESC LIMIT 10";
$result = mysql_query ($sql, $db);
while ($row = mysql_fetch_array ($result))
{
echo "[".$row['data']."]";
}
?>
And I have tried to do the WHERE value as well but it doesn't return any result.
$sql = "SELECT data FROM table_answers WHERE id IN (SELECT id FROM table_answers
ORDER BY id DESC LIMIT 10) ORDER BY popularity DESC LIMIT 1";
$result = mysql_query ($sql, $db);
while ($row = mysql_fetch_array ($result))
{
echo " [".$row['data']."] ";
}
Anyone have any idea what I might be doing wrong here? please
This should solve the problem -
SELECT tableorder.*
FROM (SELECT *
FROM table
ORDER BY id DESC
LIMIT 10) tableorder
ORDER BY tableorder.popularity DESC
LIMIT 1
The inner query will sort on the basis on id and get the top 10. The outer will again sort the 10 rows on the basis of popularity and return the row with highest popularity.
SELECT data
FROM (
SELECT data
FROM table_answers
ORDER BY id DESC
LIMIT 10
) t
ORDER BY popularity
so I execute query:
SELECT SQL_CALC_FOUND_ROWS * FROM table l LIMIT 10, 20;
which returns 20 rows from table, and there are a total 553 rows in the table
Then i immediately execute SELECT FOUND_ROWS();
But this instead only returns the number 1, despite the fact that there are 553 rows in my table (it's supposed to return 553, am I correct?)
what did I do wrong?
I suspect you have a syntax error, as names in SQL are not supposed to contain spaces. Try adding square brackets around [table 1], if that is the name of your table.
Remove your limit, I think there it is not showing 20 rows; it is showing only 10 rows.
$sql = "SELECT SQL_CAL_FOUND_ROWS * FROM users "; //don;t write table then table name
$result = mysql_query($sql);
//Use these according to your requirements:
$sql = "SELECT SQL_CAL_FOUND_ROWS * FROM users ";
$result = mysql_query($sql);
$sql = "SELECT FOUND_ROWS() AS `found_rows`";
$rows = mysql_query($sql);
$rows = mysql_fetch_assoc($rows);
$total_rows = $rows['found_rows'];