I'm trying to select a date within the time period of one day. A simple query like this will do the trick:
SELECT *
FROM table_name
WHERE table_name.the_date > DATE_SUB(CURDATE(), INTERVAL 1 DAY)
My problem is I am using prepared statements with pg_execute/PDO(the problem is the same in both). For example:
$query = "SELECT *
FROM table_name
WHERE table_name.the_date > $1";
$params = array('DATE_SUB(CURDATE(), INTERVAL 1 DAY)')
$results = pg_prepare($dbconn, '' , $query );
$results = pg_execute($dbconn, '', $params);
The result is that it always errors out with:
pg_execute(): Query failed: ERROR: invalid input syntax for type timestamp:
Now I now there is special postgres functions that can be used as indicated in this link: http://www.postgresql.org/docs/9.0/static/datatype-datetime.html#AEN5582 . Now I've replaced NOW() with the special input 'now' , but there is still an error with the 'INTERVAL 1 DAY' .
How can I get around this?
I don't get why you'd want to use bind variables here.
You can simply do:
$query = "SELECT *
FROM table_name
WHERE table_name.the_date > DATE_SUB(CURDATE(), INTERVAL 1 DAY)";
$params = array();
$results = pg_prepare($dbconn, '' , $query);
$results = pg_execute($dbconn, '', $params);
If you want the ability to change the interval, you must still hard-code any syntax elements, although you should be able to dynamically configure the size of the interval.
$query = "SELECT *
FROM table_name
WHERE table_name.the_date > DATE_SUB(CURDATE(), INTERVAL $1 DAY)";
$params = array('1');
$results = pg_prepare($dbconn, '' , $query);
$results = pg_execute($dbconn, '', $params);
Related
i'd like to have a result on PHP/MYSQL
I have a table ps_orders with price on total_paid
I need to ask total for all price in current date, i have dificult ti insert correct date. I'm stopping here, and do not works... thnaks
....
$date = date("Y-m-d");
$query = "SELECT SUM(total_paid) FROM ps_orders WHERE delivery_date = '%$date%'";
$result = mysql_query($query) or die(mysql_error());
$row = mysql_fetch_assoc($result);
echo mysql_result($result, 0);
Try
$query = "SELECT SUM(total_paid) FROM ps_orders WHERE delivery_date = '$date'";
or
$query = "SELECT SUM(total_paid) FROM ps_orders WHERE delivery_date LIKE '%$date%'";
depending on how your delivery_date field is setup as well as what you are using in your $date variable (time stamp vs just m-d-y), your query up to the where clause looks okay, but you could also try:
SELECT SUM(total_paid)
FROM ps_orders
WHERE delivery_date = $date;
if you are using a datetime field for delevery_date, you'll have to go more in depth and use a range:
SELECT SUM(total_paid)
FROM ps_orders
where (delivery_date > $date
and deliver_date < $date +interval 1 day)
This link should also help you out quite a bit when working with date: http://dev.mysql.com/doc/refman/5.5/en/date-and-time-functions.html#function_date-add
You can use one of the following:
DATE function in mysql converts 2013-11-20 10:54:12 to 2013-11-20, i.e. truncated a time in date
$query = "SELECT SUM(total_paid) FROM ps_orders WHERE DATE(delivery_date) = '$date'";
or you use only one '%' after $date with using LIKE, so this value will be matched for dates like 2013-11-20 10:12:13 :
$query = "SELECT SUM(total_paid) FROM ps_orders WHERE delivery_date like '$date%'";
or use string mysql function SUBSTRING
$query = "SELECT SUM(total_paid) FROM ps_orders WHERE SUBSTRING(delivery_date1, 1, 10) = '$date'";
use datetime with time and BETWEEN mysql comparison operator:
$query = "SELECT SUM(total_paid) FROM ps_orders WHERE delivery_date1 between '$date 00:00:00' and '$date 23:59:59'
Im trying to do a mysql check if a record from $uid exist from today based on $timestamp and if it doesnt then do an INSERT.
//EXAMPLE RECORD FROM TABLE VOTE
--- #vote_fb_uid# --- #vote_time#
665414807 1369219044
tjt
//STEP 1 - do a look up on $uid and check with timestamp $today
$timestamp = $this->time;
$date = date('Y-m-d', $timestamp);
$today = date('Y-m-d');
$sql = "
SELECT * FROM vote WHERE
vote_fb_uid = '$this->fb_uid',
WHERE vote_time = '$CHECK_IF_THERE_IS_AN_ENTRY_FROM_TODAY'";
$res = mysql_query($sql) or die( mysql_error());
//STEP 2 - If no records are found for today - then we do an INSERT
if($no_record_for_today) {
$sql = sprintf("
INSERT INTO vote(
vote_fb_uid,
vote_time)
VALUES ('%s','%s')",
mysql_real_escape_string($this->fb_uid),
mysql_real_escape_string($this->time));
$res = mysql_query($sql) or die( mysql_error());
}
Obviously im strugling with the SQL part for the look up - im wondering if there isnt some in-built SQL function to do this or similar?
to check if you had a vote in the last 24 hours :
SELECT *
FROM vote
WHERE vote_fb_uid = '$this->fb_uid'
AND FROM_UNIXTIME(vote_time) >= DATE_SUB(NOW(), INTERVAL 1 DAY)
if you want to limit to the same day (mean you are allowed to post at 2013.05.21 23:55 and 2013.05.22 00:05)
SELECT *
FROM vote
WHERE vote_fb_uid = '$this->fb_uid'
AND DATE(FROM_UNIXTIME(vote_time)) = DATE(NOW())
CURDATE()
Returns the current date as a value in 'YYYY-MM-DD' or YYYYMMDD format, depending on whether the function is used in a string or numeric context.
mysql> SELECT CURDATE();
-> '2008-06-13'
mysql> SELECT CURDATE() + 0;
-> 20080613
Try this:
$today = date('Y-m-d'); //change it to timestamp if you want in timestamp
$sql = "
SELECT count(*) as total FROM vote WHERE
vote_fb_uid = '$this->fb_uid' and
vote_time = '$today'";
$res = mysql_query($sql) or die( mysql_error());
if($res[0]['total'] < 1){
$sql = sprintf("
INSERT INTO vote(
vote_fb_uid,
vote_time)
VALUES ('%s','%s')",
mysql_real_escape_string($this->fb_uid),
mysql_real_escape_string($this->time));
$res = mysql_query($sql) or die( mysql_error());
} else{
//return error("custom","","Already Inserted.");
echo "already inserted";
}
Your $sql query have a syntax error, you have used two times clause WHERE the correct syntax to use two or more clauses in where is using AND to join them, to get only record wich don't have an entry for today you can use DATE_SUB with 1 day interval
SELECT *
FROM vote
WHERE vote_fb_uid = '$this->fb_uid',
AND vote_time <= DATE_SUB(vote_time, INTERVAL 1 DAY)
This question already exists:
SQL order by date, time [duplicate]
Closed 9 years ago.
I have table named notify with (seeker, donor, date) columns
the date column of type (datetime) and it stores the following format YYYY-MM-DD HH:MM:SS I'm trying to SELECT 1 record with the latest date from notify table and then compare the date with the current date and calculate the number of days between tow dates..
<?php
session_start();
$email = $_GET['email'];
date_default_timezone_set('Asia/Riyadh');
$time = date("Y-m-d H:i:s");
$note = "SELECT * FROM notify WHERE seeker='".$_SESSION['email']."'AND donor='".$email."' ORDER_BY `date` DESC LIMIT 1";
$st = $conn->prepare($note);
$st->execute();
if($found = $st->fetch(PDO::FETCH_ASSOC)){
$now = $time;
$old_date = strtotime($found['date']);
$dateif = $now - $old_date;
if(floor($dateif/(60*60*24)) >= 7){
echo "the difference between tow dates is 7 days or more";
} else { echo "difference between tow dates is less than 7 days";}
}
?>
the code is not working ! i have only one record in my notify table with this value in date 2013-04-22 09:15:47
First of all, you should use prepared statements like this:
$note = "SELECT *
FROM notify
WHERE seeker=:seeker AND donor=:donor
ORDER BY `date` DESC
LIMIT 1";
$st = $conn->prepare($note);
$st->execute(array(
':seeker' => $_SESSION['email'],
':donor' => $email,
);
Without the place holders you're still open to SQL injection.
Second, you can't compare a string with an integer in this way:
$now = $time; // string
$old_date = strtotime($found['date']); // integer
$dateif = $now - $old_date; // dunno?
You should compare apples with apples:
$seven_days_ago = strtotime('-7 days');
$old_date = strtotime($found['date']);
if ($old_date > $seven_days_ago) {
echo "difference between tow dates is less than 7 days";
} else {
echo "the difference between tow dates is 7 days or more";
}
Since your date column doesn't exist, there's no point in ordering by it. Also, you're exposed to SQL injection in the case where $_SESSION['email'] is not secured.
So, the correct form would be to use prepared statements, as well as order by the right column. (assuming PDO, you can use mysqli as well):
/** #var PDO $pdo - Assuming a PDO connection. */
$query = "SELECT * FROM `user` WHERE `ID` = :email ORDER BY `time` DESC";
$stmt = $pdo->prepare($query);
$stmt->execute(array($_SESSION['email']));
$result = $stmt->fetchAll(PDO::FETCH_ASSOC); //Get all results in an associated array form.
Jack's answer shows you how to use prepared statements correctly. Here is the code to simplify the date calculation using DATEDIFF().
$note = "SELECT *, DATEDIFF(NOW(), `date`) AS date_diff
FROM notify
WHERE seeker=:seeker AND donor=:donor
ORDER_BY `date` DESC
LIMIT 1";
$st = $conn->prepare($note);
$st->execute(array(
':seeker' => $_SESSION['email'],
':donor' => $email,
);
$row = $st->fetch(PDO::FETCH_ASSOC);
// do something with $row
If you are attching any variables to string then you need to concatinate them using dot and oder by will come after where condition and inside $_SESSION you missed quotes
$query = "SELECT * FROM user WHERE ID='".$_SESSION['email']."' ORDER_BY date, time";
For retrieving latest date from database please try executing following sql query
$query="SELECT * FROM user WHERE ID='".mysql_real_escape_string($_SESSION[email])."' ORDER_BY date,time desc limit 1";
In order to retrieve latest date you need to sort field for date in descending order
$note = "SELECT * FROM notify WHERE seeker=' ".$_SESSION['email']. " ' AND donor=' ".$email." ' ORDER_BY date DESC LIMIT 1";
have you try to order by desc? as shown bellow:
$note = "SELECT * FROM notify
WHERE
seeker=' ".$_SESSION['email']. " '
AND
donor=' ".$email." ' ORDER_BY date DESC LIMIT 1";
you forgot ` here around date. date is reserved word in mysql,
if you want to use it as column name place ` around it.
EDIT also you have extra space remove it
$note = "SELECT * FROM notify WHERE seeker='".$_SESSION['email']. "'
AND donor='".$email."' ORDER_BY `date` LIMIT 1";
I have this table :
I would like to delete same rows. For example first five rows are the same, my table should have only one row that includes this data : 40.792274 29.412994 2011-12-21 17:19:52.
So I used the following code :
$query = "SELECT * FROM table GROUP BY date";
$result = mysql_query($query);
while($row = mysql_fetch_array($result)){
$date = $row['date'];
$lat = $row['latitude'];
$lon = $row['longitude'];
$query = "SELECT * FROM table WHERE date='$date' AND latitude='$lat' AND longitude='$lon'";
$re = mysql_query($query);
$number = mysql_num_rows($re);
$number--;
$query = "DELETE * FROM table WHERE date='$date' AND latitude='$lat' AND longitude='$lon' LIMIT $number";
mysql_query($query);
}
But this code doesn't work.. What should I do ?
Edited :
I solved my question :
$query = "SELECT * FROM table GROUP BY date";
$result = mysql_query($query);
while($row = mysql_fetch_array($result)){
$date = $row['date'];
$lat = $row['latitude'];
$lon = $row['longitude'];
$query = "SELECT * FROM table WHERE date='$date' AND latitude=$lat AND longitude=$lon";
$re = mysql_query($query);
$number = mysql_num_rows($re);
$number--;
$query = "DELETE FROM table WHERE date='$date' AND latitude=$lat AND longitude=$lon LIMIT $number";
mysql_query($query);
}
Query lines were incorrect in my first question.
To remove the duplicate elements, you would use something like this:
$q = "SELECT date FROM table GROUP BY date"
$r = mysql_query($r);
$date = '';
while($row = mysql_fetch_array($r)){
$date = $row['date'];
$q = "SELECT date FROM mytable WHERE date='$date'";
$re = mysql_query($q);
$num = mysql_num_rows($re);
$num--;
$q = "DROP FROM mytable WHERE date='$date' LIMIT $num";
mysql_query($q);
}
Should do the trick. More specifically, when creating your $date value, you have to provide PHP with a time to use. date() defaults to using the current time, but you can provide it with a custom time as the second argument.
I suggest you take a look at the strtotime() manual at php.net as well (To translate times in your db to timestamps that can be used with date() ).
EDIT: The Answer above has been edited to remove all duplicate entries.
Try changing $dateOfNewData = date('Y-m-d H:i:s');
to
$dateOfNewData = date('Y-m-d 00:00:00'); //or change the first 00 to H if you need it to match by hour, second 00 to i if you need to match minutes and the same with seconds.
or $dateOfNewData = date('Y-m-d') which is pretty much the same and works with datetime field types
And you also need to modify your query to something like this unless you need an exact time:
"SELECT * FROM mytable WHERE date = '$dateOfNewData'" // you might also want the end date if you're working with the past in your database.
Well you can try like "Ignas" suggest but you cal also try this:
First just get the date (year, month, day) without hour, minutes and seconds. If you use full date format then you need to match exactly the same time. (to second the same) which is not really what you are looking for i guess. So you can use this:
$dateOfNewData = date('Y-m-d'); //just get year, month, day in right format (2011-12-20)
Then run a query. Here you have more options but i think the easier is something like that:
"SELECT * FROM mytable WHERE date_col LIKE '$dateOfNewData%' GROUP BY date_col"
This will group the same dates together and will display just once and will match all the rows where 'date_col starts with example: 2011-12-20% (thats why i use LIKE and $dateOfNewData%)
$dateOfNewData contains current date in this format:year-month-day (2011-12-20) and in Mysql query dont forget to use % at the end of the date. It's like * in windows for example.
'mytable' replace with your table name and 'date_col' with date column.
date() you have used will give current date time , so try to use mktime() to get extact date time you want.
you have to change your query little bit, I have modified query below,
$query = mysql_query("SELECT * FROM mytable WHERE date='$dateOfNewData'");
In mysql Date or datetime coulmn should be within ''.
I'm using the following code to sort MySQL queries into time/date:
mysql_select_db("user_live_now", $con);
$result = mysql_query("SELECT * FROM users_newest_post ORDER BY users_date_post DESC");
while($row = mysql_fetch_array($result))
{
print($row['user']);
}
instead of having the PHP run through and show all the values in the table can I have it show the values from an array?
So, you want to find specific users in the SQL query to return? Build your query programmatically:
$users = array('User1','John','Pete Allport','etc');
$sql = "SELECT * FROM `users_newest_post` WHERE ";
$i = 1;
foreach($users as $user)
{
$sql .= "`username` = '$user'";
if($i != count($users))
{
$sql .= " OR ";
}
$i++;
}
$sql .= " ORDER BY `users_date_post` DESC";
$result = mysql_query($sql);
Which would get you a query like:
SELECT * FROM `users_newest_post`
WHERE `username` = 'User1'
OR `username` = 'John'
OR `username` = 'Pete Allport'
OR `username` = 'etc'
ORDER BY `users_date_post`
DESC
So, you want to find all posts for a certain date or between two dates, kinda hard to do it without knowing the table structure, but you'd do it with something like this:
//Here's how to find all posts for a single date for all users
$date = date('Y-m-d',$timestamp);
//You'd pull the timestamp/date in from a form on another page or where ever
//Like a calendar with links on the days which have posts and pass the day
//selected through $_GET like page.php?date=1302115769
//timestamps are in UNIX timestamp format, such as you'd get from time() or strtotime()
//Note that, without a timestamp parameter passed to date() it uses the current time() instead
$sql = "SELECT * FROM `posts` WHERE `users_date_post` = '$date'"
$results = mysql_query($sql);
while($row = mysql_fetch_assoc($results))
{
echo $row['post_name'] . $row['users_date_post']; //output something from the posts
}
//Here's how to find all posts for a range of dates
$startdate = date('Y-m-d',$starttimestamp);
$enddate = date('Y-m-d',$endtimestamp);
//Yet again, date ranges need to be pulled in from somewhere, like $_GET or a POSTed form.
//Can also just pull in a formatted date rather than a timestamp and use it straight up instead, rather than going through date()
$sql = "SELECT * FROM `posts` WHERE `users_date_post` BETWEEN '$startdate' AND '$enddate'";
//could also do:
//"SELECT * FROM `posts` WHERE `users_date_post` > '$startdate' AND `users_date_post` < '$endate'"
$results = mysql_query($sql);
while($row = mysql_fetch_assoc($results))
{
//output data
}
To find posts for a specific user you would modify the statement to be something like:
$userid = 5; //Pulled in from form or $_GET or whatever
"SELECT * FROM `posts` WHERE `users_date_post` > '$startdate' AND `users_date_post` < '$enddate' AND `userid` = $userid"
To dump the result into an array do the following:
mysql_select_db("user_live_now", $con);
$result = mysql_query("SELECT * FROM users_newest_post ORDER BY users_date_post DESC");
while($row=mysql_fetch_assoc($result))
{
$newarray[]=$row
}
What you probably want to do is this:
$users = array("Pete", "Jon", "Steffi");
$users = array_map("mysql_real_escape_string", $users);
$users = implode(",", $users);
..("SELECT * FROM users_newest_post WHERE FIND_IN_SET(user, '$users')");
The FIND_IN_SET function is a but inefficient for this purpose. But you could transition to an IN clause with a bit more typing if there's a real need.
$sql = 'SELECT * FROM `users_newest_post` WHERE username IN (' . implode(',', $users) . ')';