Assign image to PHP variable - php

Question

I would like to assign an image to a variable in a PHP script so that I can make the image appear when I want to it to, by declaring the variable.
$FoodList = array_unique($FoodList);
if (!empty($FoodList)) {
foreach ($FoodList as $key => $value) {
// The variable would go here, so that image would appear
//next to each variable
echo "<li>" . $value . "<li>";
}
echo "</ul>";
}

Answer 1

Either you assign
$var = "img src="'your/pathto/image.ext'";
$var = "your/pathto/image.ext";
and echo it in html img code
The second method is more preferred

Answer 2

$FoodList = array_unique($FoodList);
if(!empty($FoodList)) {
foreach ($FoodList as $key => $value) {
//The variable would go here, so that image would appear
//next to each variable
$value = "<li>";
//Maybe you'll only display an image is a certain condition is met? If so, then...
if($condition == "parameter") {
$value .= "<img src='path/to/img' alt='img' />";
}
$value .= "</li>";
echo $value;
unset($value);
}
echo "</ul>";
}

Answer 3

$FoodList=array_unique($FoodList);
$img_path = 'images/example.jpg';
if(!empty($FoodList))
{
foreach ($FoodList as $key => $value)
{
echo "<img src='$img_path' />";
echo "<li>".$value."<li>";
}
echo "</ul>";
}

Answer 4

Use this:
echo "<li><img src='path_of_image/".$value."'/><li>";
Supposing that $value has the name of your image with extension of image.

Answer 5

<?php
$name="Adil";
echo $name;
$path="FB_IMG_1465102989930.jpg";
for($i=0;$i<44;$i++)
{
echo($i.'<br>') ;
if($i==10)
{
echo ".$path.";
echo "<img src ='".$path."'>";
}
}
?>

Answer 6

please insert a space before your image name :-
Example:-
$image_name="myphoto.jpg";
$image_path="./upload/ ".$image_name;
here I add a space after "./upload/(space)"
Store the image path into your MySql database.
call it from your HTML page as:-
<img src= '<?php echo $image_path;?>'width="200" height="200" alt=""/>