Check Hours in a date format - php

Question

I have to do the following,
My date have two formats as Y-m-d H:i:s and Y-m-d
My requirement is,
if date contains Hours(H), need to convert to F j, Y, g:i a
else to F j, Y
Is there any method that I can check H in Y-m-d H:i:s
Thanks in advance

Answer 1

Y-m-d date format is 10 chars in length and Y-m-d H:i:s date format is 19 chars in length . Based on the length you can find if it has a date part . Even if it is 19 chars in length , the time part could be 0 in which case you would disregard the time part . Along this lines should work :
// $date = "2013-09-26";
// $date = "2013-09-26 00:00:00";
$date = "2013-09-26 00:00:01";
if( strlen( $date ) == 10 )
{
// Include code to convert the date to F j, Y
echo $date , ' Does not have time part .';
}
else
{
if( strlen( $date ) == 19 and substr( $date, 10, 8 ) <> '00:00:00' )
{
// Include code to convert the date to F j, Y, g:i a
echo $date , ' Has time part which is not 0 .';
}
else
{
// Include code to convert the date to F j, Y
echo $date , ' Has time part but is 0 .';
}
}

Answer 2

Try this...
if(strstr($date, ' ') !== FALSE) {
$date = date('F j, Y, g:i a', strtotime($date));
} else {
$date = date('F j, Y', strtotime($date));
}

Answer 3

something i use when getting a date from a db that may or may not come with the time. modify as needed.
IF(
TIME( {$val['field_name']} ) = '00:00:00',
DATE_FORMAT(DATE( {$val['field_name']} ),'%D %M %Y'),
DATE_FORMAT({$val['field_name']},'%l:%i%p, %D %M %Y')
)

Answer 4

Its a little verbose - as #Bamar said you can just check for spaces, but this will work even if there are leading or trailing spaces in the field:
$date_format = "\s*\d\d\d\d-\d\d-\d\d\s*";
$date_time_format = "\s*\d\d\d\d-\d\d-\d\d\s\d\d:\d\d:\d\d\s*";
if(preg_match($date_time_format, $subject)){
$subject = date('F j, Y, g:i a', strtotime($subject));
}
elseif(preg_match($date_format, $subject)){
$subject = date('F j, Y', strtotime($subject));
}
else{
//formatting error - you can decide how to format.
}