Ok this is going to be weird but I need it
I am trying to get the character count for a huge line of code between some particular quotes ". Basically I need to be able to get everything between the 3rd quote in the beginning and the 5th quote at the end.
So here is an example
a:2:{s:10:"categories";s:5758:"...........";s:5:"posts";s:6:"a:0:{}";}
I need to know what the character count is of all the periods. There is actually code in place of those periods.
Since there are 11 periods then my character count will be 11. The only consistent thing is the quotes in this so I need to base off that.
Any help would be awesome.
Here is my code. I am basically creating the code and adding some custom labels. I tried serializing the code first before I unserialize it but that didn't seem to work.
<?
$thisisit .= 'a:2:{s:10:"categories";s:5481:"a:40:{';
include('connect.php');
$sql = "SELECT * FROM wp_terms ORDER BY term_id ASC LIMIT 40";
$result = mysql_query($sql);
$count = 0;
while($row = mysql_fetch_array($result)) {
$name = $row['name'];
$charactercount = strlen($name);
$term_id = $row['term_id'];
$thisisit .= 'i:'.$count.';a:2:{s:11:"filter_name";s:20:"add_keyword_category";s:11:"filter_args";a:7:{s:12:"filter_value";s:'.$charactercount.':"'.strtolower($name).'";s:19:"filter_search_title";s:1:"1";s:21:"filter_search_excerpt";i:0;s:21:"filter_search_content";s:1:"1";s:21:"faf_filter_categories";a:1:{i:4;s:3:"'.$term_id.'";}s:17:"filter_match_word";i:0;s:17:"filter_match_case";i:0;}}';
//echo "<br><br>";
$count++;
}
$thisisit .= '}";s:5:"posts";s:6:"a:0:{}";}';
$array = unserialize($thisisit);
echo strlen($array['categories']);
?>
Actually this data looks serialized. The correct solution would be to use php function unserialize.
Then, given your structure, to know the length of that element:
strlen(unserialize($data)['categories']);
If you run old php, you need to store the result in a temporary variable:
$array = unserialize($data);
echo strlen($array['categories']);
If your serialized data is corrupted (as in "not received from proper execution of serialize"), as it seems from your example, we can return to your original task:
get everything between the 3rd quote in the beginning and the 5th quote at the end
The simplest way to achieve that is:
implode("'", array_slice(explode("'", $data), 3, -5));
Related
I have a code in PHP like the next:
//$menutype is defined in this point, and no problem with it
$sql = "SELECT struct FROM menutype WHERE id=$menutype;";
$result = mysql_query($sql);
list($struct) = mysql_fetch_row($result);
$menu = explode("\n", $struct); //Explode to make an array with each line
foreach ($menu as $index => $value)
{
//$barid is defined in the top of the document and no issue with it
creatabla($barid, $value);
}
function creatabla($barid, $tipo)
{
$tipo = trim($tipo, ' '); //trim to delete unwanted spaces
$sql = "SELECT name FROM products WHERE tipo LIKE '%$tipo%' AND restaurante='$barid';";
$result = mysql_query($sql);
while(list($name) = mysql_fetch_row($result))
{
echo "$name";
}
}
Similar 'struct' row struct:
Line1
Line2
Line3
Line4AndLastLine
No car return after Last Line.
Well, the code usually works fine, but If I modify the 'Struct' row, some lines won't be read fine, so I usually need to edit the struct row in the advaced editor of the phpmyadmin.
What can I do to solve this issue? Can I try other kind of filter in the sql statement? What can I do to improve the trim or the explode function to solve this issue?
Thanks you to all in advance.
I think I'm starting to understand the issue and I'm guessing you're right - I'm guessing there is a \r character on the end.
Right now you are calling this:
trim($tipo, ' ');
That deletes ONLY spaces. If you change it to simply:
trim($tipo);
Then it will delete a lot more types of whitespace, including (but not limited to) the \r character.
See HERE for more information on the trim() function.
I've run into a problem that is making me go a bit crazy. I have imported some csv data into a table in my phpadmin database and am now using a php script with mysql_query() to run a simple select query on the database and convert the result into json format - e.g. SELECT clients FROM TABLE 29.
Basically, some of the columns in the table result in a json string after passing them through mysql_query() but others simply return a blank. I have fiddled for hours now and can't figure out why this is. The last bit of my code looks like this:
$myquery = "SELECT `clients` FROM `TABLE 29`";
$query = mysql_query($myquery) or die(mysql_error());
if ( ! $query ) {
echo mysql_error();
die;
}
$data = array();
for ($x = 0; $x < mysql_num_rows($query); $x++) {
$data[] = mysql_fetch_assoc($query);
}
echo json_encode($data);
mysql_close($server);
Any help would be greatly appreciated. Could it be something about the data in the table? I'm at a loss.
thank you!
UPDATE: the length of the strings in the column clients seems to be having an effect. When I replace all the text with something shorter (e.g. aaa instead of something like company name 111 - 045 - project name - currency - etc) it works. However, I need it to be able to handle long strings as I want it to just take whatever users happen to import into it... what am I doing wrong?
No, its not about the table, its about how you loop them. Example:
$data = array();
while($row = mysql_fetch_assoc($query)) { // While a row of data exists, put that row in $row as an associative array
$data[] = $row;
}
echo json_encode($data);
mysql_close($server);
exit;
Note: mysql is depreacted and no longer maintained. Use the improved version of the mysql extension which is mysqli or use PDO instead.
After checking all the rows of the data I discovered that the source of the problem was a 'é' - yes, an 'e' with an accent. Once I replaced it with a regular 'e' the problem went away. So much lost time for something so tiny :(
In the project that I am creating, I have a mysql column that is an array of different pieces of data from the database. These pieces of data have info that I want to display. In order to separate these items in the array I used,
$get_query = mysql_query('Select array FROM data');
while($dataRow = mysql_fetch_assoc($getfrnd_query)) {
$array = $dataRow['array'];
if($array != "") {
$data_from_array_column = explode("," $array);
$getdata = mysql_query("SELECT * FROM info WHERE item = $data_from_array_column");
//Then I used a mysql_fetch_assoc to get data based on the item.
}
}
When I run this code, I get an error "Array to string conversion on the line with $getdata".
Is there any way to get this to work?
Thank you.
The problem is that explode returns an array containing the strings in between the character(s) you used as a delimiter (, in your case), not a string.
PHP is getting mad because it doesn't know how to convert your array to a string automatically. So, you will need to convert it yourself. The options are:
You want to select the row where item is equal to the nth element in the array, $data_from_array_column. If this is the case, you need to insert the following line of code after your explode:
$data_from_array_column = $data_from_array_column[0];
If you want to select where it matches any of the elements in the $data_from_array_column array, it will get more complicated. You would need to add this line after the explode:
$data_from_array_column = implode("' OR item='",$data_from_array_column);
and change your query on the next line to:
$getdata = mysql_query("SELECT * FROM info WHERE item='$data_from_array_column'");
This will create a MySQL query that looks some thing like this:
SELECT * FROM info WHERE item='foo' OR item='bar' OR item='bla'
I am trying to get a count and I am getting 1 instead of 0 from it. I have looked thoroughly though the web and this site. I have even been trying to figure it out on my own for a long time. I keep coming empty handed here.
So Basically what I am trying to do is make a like system for my users. I can get everything to work correctly the count works except for one thing. When they have liked it it returns 1 not 0 which it should be.
Here is my code for the count. I am not posting all the coding for security reasons and it really doesn't need to since its about the counting part not the rest.
$sql_like = mysql_query("SELECT * FROM posts WHERE mem2_id='$id' ORDER BY post_date DESC LIMIT 40");
while($row = mysql_fetch_array($sql_like)){
$like1 = $row['like_array'];
$like3 = explode(",", $like1);
$likeCount = count($like3);
}
So here is the code that determines the number. Any ideas what is wrong with this? Why its returning 1 not 0 when the item is empty?
// you do escape your id right??? (sql injection prevention)
$sql_like = mysql_query("SELECT * FROM posts WHERE mem2_id='$id' ORDER BY post_date DESC LIMIT 40");
while($row = mysql_fetch_array($sql_like)){
$likeCount = 0;
$like1 = trim($row['like_array']);
if ($like1) {
$like3 = explode(",", $like1); // exploding emtpy string would result in array('')
$likeCount = count($like3);
}
}
Calling explode on an empty string gives an array containing the empty string. This is one element, not zero.
I would suggest that you change your database design if possible so that you don't store the values separated by commas. Use a separate table instead.
If you can't change the database design you can handle the empty string separately.
count() returns the number of indexes in an array or something in an object (PHP: count - Manual).
if a string var is used rather than an array or object it returns 1. it has to get a null value in order to return 0.
you can give it a go by trying:
print count("");
and
print count(null);
You'll have better luck if you use explode() to break the sql output into an array and then run a check with an if statement. Something like the following:
$like3 = explode(',',$like1);
if (count($like1)=1 && $like1[0] == '')
// etc ..
I hope this helps
i am working in php. I want to create xml of resul of query.
I my query result i am getting a number of URLs. When i want to create xml file of these urls a problem has occured due to spaces and some special characters in url.
If i try same thing for a url which does not has any space in url than no problem is occured.
This is my php program:-
$rs = mysql_query("SELECT urlofsong FROM music ORDER BY date DESC LIMIT 0,10") or die ("invalid query");
//count the no. of columns in the table
$fcount = mysql_num_fields($rs);
//you can choose any name for the starting tag
//echo "$pass";
echo ("<result>");
while($row = mysql_fetch_array( $rs ) )
{
echo ("<tablerow>");
for($i=0; $i< $fcount; $i++)
{
$tag = mysql_field_name( $rs, $i );
echo ("<$tag>". $row[$i]. "</$tag>");
}
echo ("</tablerow>");
}
echo ("</result>");
These type of entries in url creating problem :-"http://192.168.1.214/MusicApplication/Songs/RUFF BEAT - Baby_Justin Bieber_DJs Sunny & Puneet(VT).mp3"
Note:-please see the file name.
Please suggest me what should i do to solve this type of problem.
You should probably escape the file name by replacing spaces with %20. Or just use urlencode() on the file name.
Also, please escape row contents with htmlspecialchars or you may end up with invalid XML.
This is the solution for my problem...
echo ("".htmlentities($row[$i]). "");
means we should pass data from htmlentities() . by using this function we can convert special characters into html characters.
Thank you all.