PHP: If-statement, need value of condition that triggered - php

Question

I'm sorry for the vaguely described title. This is what I want:
if($a[$f] === false || $a[$g] === false || $a[$h] === false || $a[$i] === false || $a[$j] === false)
{
// do something
}
I want to do something with the condition that actually triggered the statement (if a[$f] = true and a[$g] = false, I want to do something with $g).
I know that in this case, the first statement that went true (i.e. $a[$g] == false) triggers. But is there any way to do something with $g? I've never seen this in my programming life before and can't seem to find anything about it.
Thanks in advance.
--- Edit ---
I forgot to mention: I'm using a function on all the array data. So, shortened, I get this:
if(valid($a[$f]) === false || valid($a[$g]) === false)
{
// do something
}
--- Edit 2 ---
This piece of OOP-based PHP, where I'm in a class, is my code.
if($this->validatedText($product[$iName]) == false ||
$this->validatedUrl($product[$iUrl]) == false ||
$this->validatedNumber($product[$iTax]) == false ||
$this->validatedValuta($product[$iPrice]) == false ||
$this->validatedText($product[$iArticleNumber]) == false ||
$this->validatedText($product[$iDescription]) == false ||
$this->validatedText($product[$iMetaDescription]) == false ||
$this->validatedText($product[$iTitle]) == false)
{
// do something with the first iVariable
}

Answer 1

Simplest solution will be
if(false!==($sIndex = array_search(false, $a, 1)))
{
//your $sIndex is first index with false value
}
if you want all keys, you may use array_filter(), like this:
$rgFalse = array_keys(array_filter($a, function($x)
{
//here valid is your function
return false===valid($x);
}));