PHP link to include header - php

I have php reading a text file that contains all the names of images in a directory, it then strips the file extension and displays the file name without the .jpg extension as a link to let the user click on then name, what I am looking for is a easy way to have the link that is clicked be transferred to a variable or find a easier solution so the link once it is clicks opens a page that contains the default header and the image they selected without making hundreds of HTML files for each image in the directory.
my code is below I am a newbie at PHP so forgive my lack of knowledge.
thank you in advance. also I would like a apple device to read this so I want to say away from java script.
<html>
<head>
<title>Pictures</title>
</head>
<body>
<p>
<?php
// create an array to set page-level variables
$page = array();
$page['title'] = ' PHP';
/* once the file is imported, the variables set above will become available to it */
// include the page header
include('header.php');
?>
<center>
<?php
// loads page links
$x="0";
// readfile
// set file to read
$file = '\filelist.txt' or die('Could not open file!');
// read file into array
$data = file($file) or die('Could not read file!');
// loop through array and print each line
foreach ($data as $line) {
$page[$x]=$line;
$x++;
}
$x--;
for ($i = 0; $i <= $x; $i++)
{
$str=strlen($page[$i]);
$str=bcsub($str,6);
$strr=substr($page[$i],0,$str);
$link[$i]= "<a href=".$page[$i]."jpg>".$strr."</a>";
echo "<td>".$link[$i]."<br/";
}
?>
</P></center>
<?php
// include the page footer
include('/footer.php');
?>
</body>
</html>

add the filename to the url that you want to use as a landing page, and catch it using $_GET to build the link.
<a href='landingpage.php?file=<?php echo $filename; ?>'><?php echo $filename; ?></a>
Then for the image link on the landing page
<img src='path/to/file/<?php echo $_GET['file'] ?>.jpg' />

Related

Set backgroung image in .php file

I downloaded this code:
$image = ImageClass::getImage('bg.jpeg','myTitle');
$bg_img = explode(" ",$image);
$src = substr(strpos('"',$bg_img),strlen($bg_image)-1);
echo "<div style='background-image: url(".$src.");' ></div>
<?php
/*
*** OPTIONS ***/
// TITLE OF PAGE
$title = "ARQUIVOS PROPAR";
// STYLING (light or dark)
$color = "dark";
// ADD SPECIFIC FILES YOU WANT TO IGNORE HERE
$ignore_file_list = array( ".htaccess", "Thumbs.db", ".DS_Store", "index.php", "flat.png", "error_log" );
// ADD SPECIFIC FILE EXTENSIONS YOU WANT TO IGNORE HERE, EXAMPLE: array('psd','jpg','jpeg')
$ignore_ext_list = array( );
// SORT BY
$sort_by = "name_asc"; // options: name_asc, name_desc, date_asc, date_desc
// ICON URL
//$icon_url = "https://www.dropbox.com/s/lzxi5abx2gaj84q/flat.png?dl=0"; // DIRECT LINK
$icon_url = "data:image/png;base64,iVBORw0KGgoAAAANSUhEUgAAA+gAAAAyCAYAAADP7vEwAAAgAElEQVR4nOy9d5hdV3nv";
// TOGGLE SUB FOLDERS, SET TO false IF YOU WANT OFF
$toggle_sub_folders = true;
// FORCE DOWNLOAD ATTRIBUTE
$force_download = true;
// IGNORE EMPTY FOLDERS
$ignore_empty_folders = false;
// SET TITLE BASED ON FOLDER NAME, IF NOT SET ABOVE
if( !$title ) { $title = clean_title(basename(dirname(__FILE__))); }
?>
Th full code can be download here: https://github.com/halgatewood/file-directory-list/blob/master/index.php
I'm having problem with the start:
$image = ImageClass::getImage('bg.jpeg','myTitle');
$bg_img = explode(" ",$image);
$src = substr(strpos('"',$bg_img),strlen($bg_image)-1);
echo "<div style='background-image: url(".$src.");' ></div>
I want to put a picture as background, but it isn't happening. What's wrong?
Changed with the answer:
<?php
echo "<div style='background-image: url('/bg.jpeg');' ></div>";
?>
<?php
/*
*** OPTIONS ***/
// TITLE OF PAGE
$title = "ARQUIVOS PROPAR";
// STYLING (light or dark)
$color = "dark";
etc..
No need for all that,
What you desire to achieve is much simpler.
Assuming this code is inside index.php and your server's directory structure:
/some-folder/
/index.php
/bg.jpeg
Simply link it as its done in plain html —
<?php
echo "<div style=\"background-image: url('/bg.jpeg');\" ></div>";
?>
If you wan't it do be dynamic, i.e, image files's name is inside a variable then,
<?php
$my_image = 'bg.jpeg';
echo "<div style='background-image: url($my_image);' ></div>";
?>
Update:
Important Tip: All programming languages are executed line-by-line, this tip applies not only to PHP, but also HTML Learn More
Assume for example, your page's html structure returned to the browser is as provide below and you want to apply background to body tag
<html>
<head><head>
<body>
<nav>Some dummy navigation</nav>
<div>welcome to my website</div>
<footer>Copyright</footer>
</body>
</html>
Simply copying and pasting my code to the top of page will result in
<div style="background-image: url('bg.jpeg');" ></div>
<html>
<head><head>
<body>
<nav>Some dummy navigation</nav>
<div>welcome to my website</div>
<footer>Copyright</footer>
</body>
</html>
But that created a empty div tag at the top of html output, i wanted it to apply background to by body tag instead !!!?
— This happened because echo is used to send output to the browser as soon as it is executed. So since you copied my code to the top of your script the html output is also at the top.
But why did it echo <div style="background-image: url('bg.jpeg');" ></div> when i wanted it to apply to my page's body?
— Because the echo statements reads "<div style=\"background-image: url('bg.jpeg');\" ></div>"; as its output.
Ok, but how to apply the background-image to body then??
As mentioned earlier code is executed line-by-line, so in order to apply the style to pages's body tag you'll need to call it near your body tag and also modify it to not output the div it currently does.
So assuming your index.php is:
<?php
$my_image = 'bg.jpeg';
echo "<div style='background-image: url($my_image);' ></div>";
?>
<html>
<head><head>
<body>
<nav>Some dummy navigation</nav>
<div>welcome to my website</div>
<footer>Copyright</footer>
</body>
</html>
You'll need to change it to —
<?php
$my_image = 'bg.jpeg';
// don't echo any thing here
?>
<html>
<head><head>
<body style="background-image: url('<?php echo $my_image; ?>')">
<!-- apply the style to body -->
<nav>Some dummy navigation</nav>
<div>welcome to my website</div>
<footer>Copyright</footer>
</body>
</html>
Hopefully i explained it well :)

Php code to randomly pick links And Open

Im new to Php. I kinda need code to open Links in browser when script is loaded.
heres my code below.
<?php
$links = array_open("https://stackoverflow.com/",
"https://outlook.office.com/",
"https://www.protectedtext.com/",
"https://www.adobe.com/",
"https://www.linkedin.com");
echo $links[array_rand($links)];
?>
Hi change array_open to array
<?php
$links = array("https://stackoverflow.com/", "https://outlook.office.com/", "https://www.protectedtext.com/", "https://www.adobe.com/", "https://www.linkedin.com");
echo $links[array_rand($links)];
?>
And if you want to send the browser to the link you would send a location header like so...
<?php
$links = array("https://stackoverflow.com/", "https://outlook.office.com/", "https://www.protectedtext.com/", "https://www.adobe.com/", "https://www.linkedin.com");
header('Location: ' . $links[array_rand($links)]);
exit;
?>

php dynamically creating a file on form submit

would any one know how to automatically create a file through PHP so when the tag is clicked it also have the file right now it's only a path which is displayed through a loop. but when you click it there is no file, of course, long story short how can I also create a file too with a loop so all links have files created through fopen or something, just like all of them have paths generated.
<?php
function display_user_docs($doc_array) {
// set global variable, to test later if this is on the page
global $doc_table;
$doc_table = true;
?>
<br>
<form name="doc_table" action="delete_doc.php" method="post">
<table width="300" cellpadding="2" cellspacing="0">
<?php
$color = "#cccccc";
echo "<tr bgcolor=\"".$color."\"><td><strong>Documentations</strong></td>";
echo "<td><strong>Delete?</strong></td></tr>";
if ((is_array($doc_array)) && (count($doc_array) > 0)) {
foreach ($doc_array as $doc) {
if ($color == "#cccccc") {
$color = "#ffffff";
} else {
$color = "#cccccc";
}
echo "<tr bgcolor=\"".$color."\"><td><a class=\"all-doc-link\" href=\"".$doc.".php\">".htmlspecialchars($doc)."</a></td>
<td><input type=\"checkbox\" name=\"del_me[]\"
value=\"".$doc."\"></td>
</tr>";
}
} else {
echo "<tr><td>No documentation on record</td></tr>";
}
?>
</table>
</form>
<?php
}
?>
You can use file_put_contents to create a file in PHP.
It takes two parameters, the first of which is the name of the file to create, and the second of which is the contents to put inside of the file.
For example, if I wanted to make a file called 123.txt which contains hello world, I would do the following:
file_put_contents("123.txt", "hello world");
The filename can contain slashes /, so that you can specify which folder to create the file in. Thus, if I wanted to make my 123.txt file in the folder abc, I can put abc/123.txt as the filename (as long as abc is in the same folder as the PHP script).
You can find more about file_put_contents in the PHP manual.

PHP replacing 'editable' areas in html files

I'm working on a tool to replace tagged areas in a html document. I've had a look at a few php template systems, but they are not really what I am looking for, so here is what I am after as the "engine" of the system. The template itself has no php and I'm searching the file for the keyword 'editable' to set the areas that are updatable. I don't want to use a database to store anything, instead read everything from the html file itself.
It still has a few areas to fix, but most importantly, I need the part where it iterates over the array of 'editable' regions and updates the template file.
Here is test.html (template file for testing purposes):
<html>
<font class="editable">
This is editable section 1
</font>
<br><br><hr><br>
<font class="editable">
This is editable section 2
</font>
</html>
I'd like to be able the update the 'editable' sections via a set of form textareas. This still needs a bit of work, but here is as far as I've got:
<?php
function g($string,$start,$end){
preg_match_all('/' . preg_quote($start, '/') . '(.*?)'. preg_quote($end, '/').'/i', $string, $m);
$out = array();
foreach($m[1] as $key => $value){
$type = explode('::',$value);
if(sizeof($type)>1){
if(!is_array($out[$type[0]]))
$out[$type[0]] = array();
$out[$type[0]][] = $type[1];
} else {
$out[] = $value;
}
}
return $out;
};
// GET FILES IN DIR
$directory="Templates/";
// create a handler to the directory
$dirhandler = opendir($directory);
// read all the files from directory
$i=0;
while ($file = readdir($dirhandler)) {
// if $file isn't this directory or its parent
//add to the $files array
if ($file != '.' && $file != '..')
{
$files[$i]=$file;
//echo $files[$i]."<br>";
$i++;
}
};
//echo $files[0];
?>
<div style="float:left; width:300px; height:100%; background-color:#252525; color:#cccccc;">
<form method="post" id="Form">
Choose a template:
<select>
<?php
// Dropdown of files in directory
foreach ($files as $file) {
echo "<option>".$file."</option>"; // do somemething to make this $file on selection. Refresh page and populate fields below with the editable areas of the $file html
};
?>
</select>
<br>
<hr>
Update these editable areas:<br>
<?php
$file = 'test.html'; // make this fed from form dropdown (list of files in $folder directory)
$html = file_get_contents($file);
$start = 'class="editable">';
$end = '<';
$oldText = g($html,$start,$end);
$i = 0;
foreach($oldText as $value){
echo '<textarea value="" style="width: 60px; height:20px;">'.$oldText[$i].'</textarea>'; // create a <textarea> that will update the editable area with changes
// something here
$i++;
};
// On submit, update all $oldText values in test.html with new values.
?>
<br><hr>
<input type="submit" name="save" value="Save"/>
</div>
<div style="float:left; width:300px;">
<?php include $file; // preview the file from dropdown. The editable areas should update when <textareas> are updated ?>
</div>
<div style="clear:both;"></div>
I know this answer is a little more involved, but I'd really appreciate any help.
Not sure if i correctly understand what you want to achieve. But it seems I would do that in jquery.
You can get all html elements that has the "editable" class like this :
$(".editable")
You can iterate on them with :
$(".editable").each(function(index){
alert($(this).text()); // or .html()
// etc... do your stuff
});
If you have all your data in a php array. You just need to pass it to the client using json. Use php print inside a javascript tag.
<?php
print "var phparray = " . json_encode($myphparray);
?>
I think it would be better to put the work on the client side (javascript). It will lower the server work load (PHP).
But as I said, I don't think I've grasped everything you wanted to achive.

Secure images failing - Codeigniter

My script pretty much works, however when I run a for loop it fails, in the view:
<?php foreach($pics as $index=>$pic){?>
<td class='Pictures'>
<center>
<?php
$piece = explode('/',$pic["ThumbImg"]);
$string = $piece[5];
?>
<img src='<?php echo base_url(); ?>index.php/Controller/getImage/<?php echo $string; ?>/1' width="100px">
</a>
Controller class - Get image function:
//function to protect images from being accessed directly by obfuscating the URL
function getImage($img_id,$type){
if($this->members->logged_in()){
//code to authenticate user goes here then...
//code to decide which type of file it is/thumb/full size image
if($type==1)
{
$url = $this->data['base_url'].'system/application/images/pic/thumbs/';
}else if($type==0){
$url = $this->data['base_url'].'system/application/images/pic/';
}
$filepath = $url.$img_id;
//send image to web browser.
header("Content-type: image/jpeg");
//get path
$img_handle = imagecreatefromjpeg($filepath) or die("");
//create and send
ImageJpeg($img_handle);
}
I suspect that this could be due to the headers being resent, if so how can I resolve this.
Cheers
Fixed the problem - used "Hotlinking"
You will basically only need to set the header information header("Content-type: image/jpeg") if you're loading the image from the database. But since you're loading it from a folder you might want to skip the php file and immediately fetch the image from the folder:
<img src='<?php echo base_url(); ?>img_folder/<?php echo $string; ?>/1'
width="100px">

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