Displaying content but not the latest one - php

Question

I have these codes to display content on my website.
Index.php
$rest = new rest;
$list = $rest->fetch_all();
<?php foreach ($rest->fetch_all() as $rest) { ?>
<br>
<a href="episode.php?id=<?php echo $rest['cast_id']; ?>">
#<?php echo $rest['cast_id']; ?>: <?php echo $rest['cast_title']; ?>
<br>
<font size="2" color="red">
<?php echo $rest['cast_about']; ?></font></a><br>
<br><div class="divider"> </div><br>
<?php } ?>
And include.php
class rest {
public function fetch_all(){
global $pdo;
$query = $pdo->prepare("SELECT * FROM podcast ORDER BY cast_id DESC");
$query->execute();
return $query->fetchAll();
} }
Please can someone tell me how I can get this to show results but not the latest result?
All fields are numbered using an ID tag in mysql.
On my site I have the latest entry listed above this list so I do not require the latest one appearing here.
Please help.
Thank you.

Answer 1

The easiest way to do this is to discard the row in the application. You can do it in SQL by using a calculated limit. Calculate it as (SELECT COUNT(*) FROM podcast) - 1.
Or:
SELECT *
FROM podcast
EXCEPT
SELECT TOP 1 *
FROM podcast
ORDER BY cast_id ASC
Excluding the last row.

Answer 2

You can either use array_shift or array_pop depending on your query sorting as shown bellow:
Assuming the latest result is the first raw on your query result.
$rest = new rest;
$list = $rest->fetch_all();
$latest = array_shift($list);
<?php foreach ($list as $rest) { ?>
<br>
<a href="episode.php?id=<?php echo $rest['cast_id']; ?>">
#<?php echo $rest['cast_id']; ?>: <?php echo $rest['cast_title']; ?>
<br>
<font size="2" color="red">
<?php echo $rest['cast_about']; ?></font></a><br>
<br><div class="divider"> </div><br>
<?php } ?>
If it's the last raw that you need to hide, then use array_pop