php - display csv data in tabular format - php

Question

I am new to PHP and I am trying to display the CSV data in my web page with pagination option.This is the code I have so far.
<?php
$names = file('demo.csv');
$page = $_GET['page'];
//constructor takes three parameters
//1. array to be paged
//2. number of results per page (optional parameter. Default is 10)
//3. the current page (optional parameter. Default is 1)
$pagedResults = new Paginated($names, 20, $page);
echo "<ul>";
while($row = $pagedResults->fetchPagedRow()) {
//when $row is false loop terminates
$row1 = str_replace( ',', "\t", $row );
echo "<li>{$row1}</li>";
}
echo "</ul>";
//important to set the strategy to be used before a call to fetchPagedNavigation
$pagedResults->setLayout(new DoubleBarLayout());
echo $pagedResults->fetchPagedNavigation();
?>
I was having issues with commas getting displayed in my output. However, I have resolved using the str_replace function. Now, I wish to show the data elegantly in a tabular format. I tried the below code that I saw in another link.
while($row = $pagedResults->fetchPagedRow()) {
//when $row is false loop terminates
<table>
<tr>
$row1 = str_replace( ',', "\t", $row );
<td><?php echo "<li>{$row1}</li>";?></td>
</tr>
</table>
}
echo "</ul>";
However, I am not getting output in my screen. Can someone please guide me in the right direction?

Answer 1

<?php
$names = file('demo.csv');
$page = $_GET['page'];
//constructor takes three parameters
//1. array to be paged
//2. number of results per page (optional parameter. Default is 10)
//3. the current page (optional parameter. Default is 1)
$pagedResults = new Paginated($names, 20, $page);
echo "<table border=\"1\">";
//use the following line to manually display column names,
//if they're not in the 1st row of the CSV file
echo "<tr><td>Column 1 name</td><td>Column 2 name</td><td>Column 3 name</td></tr>";
while($row = $pagedResults->fetchPagedRow()) {
//when $row is false loop terminates
echo "<tr><td>";
$row1 = str_replace( ',', "</td><td>", $row );
echo $row1;
echo "</td></tr>";
}
echo "</table>";
//important to set the strategy to be used before a call to fetchPagedNavigation
$pagedResults->setLayout(new DoubleBarLayout());
echo $pagedResults->fetchPagedNavigation();
?>

Answer 2

You are mixing HTML and PHP a little to loosely. Fix like this:
while($row = $pagedResults->fetchPagedRow()) {
//when $row is false loop terminates
echo "<table>";
echo "<tr>";
$row1 = str_replace( ',', "\t", $row );
echo "<td>";
echo "<li>{$row1}</li>";
echo "</td>";
echo "</tr>";
echo "</table>";
}
echo "</ul>";
or like this:
while($row = $pagedResults->fetchPagedRow()) {
//when $row is false loop terminates
?>
<table>
<tr>
<?php $row1 = str_replace( ',', "\t", $row ); ?>
<td><?php echo "<li>{$row1}</li>";?></td>
</tr>
</table><?php
}
echo "</ul>";
The first one obviously having the preference, as it as much more readable.

Answer 3

Your tables are not placed correctly in the loop.
Please refer the following code:
<table><?php
while($row = $pagedResults->fetchPagedRow()) {
//when $row is false loop terminates
?>
<tr>
<?php
$row1 = str_replace( ',', "\t", $row );
?>
<td><?php echo $row1;?></td>
</tr>
<?php
}
?></table>