im doing some stuff with mktime, i need to add the next date with 30 days more but its returning me 1970-01-30 date, what im doing wrong ?
$strtime=strtotime("2013-10-04");
$fecha=date("Y-m-d",$strtime);
echo $fecha."<br />";
$nueva_fecha=mktime(0,0,0,date("n",$fecha),date("j",$fecha)+30,date("Y",$fecha));
echo date("Y-m-d",$nueva_fecha)."<br />";
Result:
2013-10-04
1970-01-30
Date is looking for a timestamp as it's 2nd parameter, not a string value representing this. Updated to pass it $strtime instead.
$strtime=strtotime("2013-10-04");
$fecha=date("Y-m-d",$strtime); // <-- Unnecessary unless you want to echo the value.
echo $fecha."<br />";
$nueva_fecha=mktime(0,0,0,date("n",$strtime),date("j",$strtime)+30,date("Y",$strtime));
echo date("Y-m-d",$nueva_fecha)."<br />";
Output:
2013-10-04
2013-11-03
You can just use the following function to add 30 days to the date you put in:
$date = strtotime("2013-10-04");
$new_date = strtotime("+30 days", $date);
or simply to the current date:
$new_date = strototime("+30 days", time());
If you already have strtotime, why plus on date ? Instead you could've used + (30 days in seconds) OR simply the feature they offer you + 1 day check answer: adding one day to a date
strtotime('2013-10-04 + 30 days');
This will print 2013-11-03:
date('Y-m-d', strtotime('2013-10-04 + 30 days'))
you can try this:
echo strtotime("+1 day"), "\n";
echo strtotime("+30 day",strtotime(date('D, d M Y'))), "\n";
this will add 30 days to the current date.
Also strtotime is very usefull you can use it for weekly,monthly and yearly.
You can use this also
<?php
$date = date("Y/m/d"); // example date in yyyy/mm/dd format
$unix_time = strtotime( $date ); // covert date to unix time
$sec_in_30_days = 60 * 60 * 24 * 30; // 60 seconds * 60 minutes * 24 hours * 30 days
$new_unix_time = $unix_time + $sec_in_30_days; // add 30 days to unix time
$date_in_30_days = date( 'Y/m/d', $new_unix_time ); // convert new unix time to date
// Output results:
echo 'original current date: ' . $date . '<br />';
echo '<br />';
echo 'new date: ' . $date_in_30_days . '<br />';
?>
Output will be
original current date: 2013/10/04
new date: 2013/11/03
Related
i want to find out the date after days from the given time.
for example. we have date 29 may 2015
and i want to cqlculate the date after 2 days of 25 may 2015
$Timestamp = 1432857600 (unix time of 29-05-2015)
i have tried to do it with following code but it is not working
$TotalTimeStamp = strtotime('2 days', $TimeStamp);
Missed the + - strtotime('2 days', $TimeStamp); .
Add the + to + 2 days.
Use date & strtotime for this - You can try this -
echo date('d-m-Y',strtotime(' + 2 day', strtotime('2015-05-16')));
$Timestamp & $TimeStamp are not same(may be typo). For your code -
$Timestamp = strtotime(date('Y-m-d'));
$TotalTimeStamp = strtotime('+ 2 days', $Timestamp);
echo date('d-m-Y', $TotalTimeStamp);
Php does have a pretty OOP Api to deal with date and time.
This will create a \DateTime instance using as reference the 25 May 2015 and then you can call the modify method on that instance to add 2 days.
$date = new \DateTime('2015-05-25');
$date->modify('+2 day');
echo $date->format('Y-m-d');
You may find this resource useful:
http://code.tutsplus.com/tutorials/dates-and-time-the-oop-way--net-35395
You can also just add seconds to your timestamp if you have a timestamp ready:
$NewDateStamp = $Timestamp + (60*60*24 * 2);
In the above, sec * min * hours = day -- or 86400 seconds. * 2 = 2 days.
In PHP 5 you can also use D
<?php
$date = date_create('2015-05-16');
date_add($date, date_interval_create_from_date_string('2 days'));
echo date_format($date, 'Y-m-d');
?>
OR
<?php
$date = new DateTime('2015-05-16');
$date->add(new DateInterval('2 days'));
echo $date->format('Y-m-d') . "\n";
?>
$today = gmdate("M-j-Y-H-i");
$date = gmdate('M-j-Y-H-i', strtotime($today . ' + 3 hours'));
echo $today ."<br/>";
echo $date;
and its result
Feb-24-2014-11-29
Feb-24-2014-14-00
it will add 3 hours but it also set Minutes is zero i want to add only 3 hours in current GMT time
This is happening because you are using $today variable to make + 3 hours, simply remove that and you are ready to go
$today = gmdate("M-j-Y-H-i");
$date = gmdate('M-j-Y-H-i', strtotime('+ 3 hours'));
echo $today ."\n";
echo $date;
//output Feb-24-2014-12-18
// Feb-24-2014-15-18
Live Sample Here
Those who are interested in a simpler version
$gmdate = gmdate(DATE_ATOM);
$loc_time = gmdate(DATE_ATOM, strtotime('+ 3 hours'));
DATA_ATOM and other formats which is basically same format used by MySQL 2018-10-28 13:14:18
If I have a random unix timestamp, how can I round it down to today's midnight or the midnight selected by the user. The reason for this is that I want to add hours and minutes after a certain day's midnight.
For example if the timestamp is 1324189035 then how can I remove the hours, minutes, and seconds to put the timestamp at midnight for that day.
echo date('d-m-Y H:i:s', strtotime('today', 1324189035));
Because of how you're using it, I wouldn't calculate midnight at all: it is far easier to simply convert what you're adding to the timestamp into 24 hour time and then use strtotime:
echo strtotime("0:00",1324189035); // 1324184400
echo strtotime("17:50",1324189035); // 1324248600
And if you want to have that in human readable, use date and m/d/Y H:i:s:
echo date('m/d/Y H:i:s', strtotime('17:50',1324189035)); // 12/18/2011 17:50:00
Simply Use
strtotime('today midnight');
Just do
date('d-m-Y',strtotime('today'));
Easy!
An easy solution would be to use the modulo expression to remove the exceeded seconds from a round day timestamp.
<?php
date_default_timezone_set('UTC');
$timestamp = time();
echo "timestamp : " . $timestamp . PHP_EOL;
echo "timestamp formatted : " . date('Y-m-d H:i:s', $timestamp) . PHP_EOL;
$diff = $timestamp % (60 * 60 * 24);
echo "diff : " . $diff . PHP_EOL;
$midnight = $timestamp - $diff;
echo "midnight : " . $midnight . PHP_EOL;
echo "midnight formatted : " . date('Y-m-d H:i:s', $midnight) . PHP_EOL;
This would output the following result.
timestamp : 1575451074
timestamp formatted : 2019-12-04 09:17:54
diff midnight : 1575417600
midnight formatted : 2019-12-04 00:00:00
And here is a one liner function to get your midnight from any timestamp.
function getMidnight ($timestamp) { return $timestamp - ($timestamp % 86400); }
http://sandbox.onlinephpfunctions.com/code/1d85c935e71fcf011284ae33658e0c68dd8d8c28
How about just:
date -d $(date +%F) +%s
I have a date returned as part of a MySQL query in the form 2010-09-17.
I would like to set the variables $Date2 to $Date5 as follows:
$Date2 = $Date + 1
$Date3 = $Date + 2
etc., so that it returns 2010-09-18, 2010-09-19, etc.
I have tried
date('Y-m-d', strtotime($Date. ' + 1 day'))
but this gives me the date before $Date.
What is the correct way to get my Dates in the format form 'Y-m-d' so that they may be used in another query?
All you have to do is use days instead of day like this:
<?php
$Date = "2010-09-17";
echo date('Y-m-d', strtotime($Date. ' + 1 days'));
echo date('Y-m-d', strtotime($Date. ' + 2 days'));
?>
And it outputs correctly:
2010-09-18
2010-09-19
If you're using PHP 5.3, you can use a DateTime object and its add method:
$Date1 = '2010-09-17';
$date = new DateTime($Date1);
$date->add(new DateInterval('P1D')); // P1D means a period of 1 day
$Date2 = $date->format('Y-m-d');
Take a look at the DateInterval constructor manual page to see how to construct other periods to add to your date (2 days would be 'P2D', 3 would be 'P3D', and so on).
Without PHP 5.3, you should be able to use strtotime the way you did it (I've tested it and it works in both 5.1.6 and 5.2.10):
$Date1 = '2010-09-17';
$Date2 = date('Y-m-d', strtotime($Date1 . " + 1 day"));
// var_dump($Date2) returns "2010-09-18"
From PHP 5.2 on you can use modify with a DateTime object:
http://php.net/manual/en/datetime.modify.php
$Date1 = '2010-09-17';
$date = new DateTime($Date1);
$date->modify('+1 day');
$Date2 = $date->format('Y-m-d');
Be careful when adding months... (and to a lesser extent, years)
Here is a small snippet to demonstrate the date modifications:
$date = date("Y-m-d");
//increment 2 days
$mod_date = strtotime($date."+ 2 days");
echo date("Y-m-d",$mod_date) . "\n";
//decrement 2 days
$mod_date = strtotime($date."- 2 days");
echo date("Y-m-d",$mod_date) . "\n";
//increment 1 month
$mod_date = strtotime($date."+ 1 months");
echo date("Y-m-d",$mod_date) . "\n";
//increment 1 year
$mod_date = strtotime($date."+ 1 years");
echo date("Y-m-d",$mod_date) . "\n";
You can also use the following format
strtotime("-3 days", time());
strtotime("+1 day", strtotime($date));
You can stack changes this way:
strtotime("+1 day", strtotime("+1 year", strtotime($date)));
Note the difference between this approach and the one in other answers: instead of concatenating the values +1 day and <timestamp>, you can just pass in the timestamp as the second parameter of strtotime.
Here has an easy way to solve this.
<?php
$date = "2015-11-17";
echo date('Y-m-d', strtotime($date. ' + 5 days'));
?>
Output will be:
2015-11-22
Solution has found from here - How to Add Days to Date in PHP
Using a variable for Number of days
$myDate = "2014-01-16";
$nDays = 16;
$newDate = strtotime($myDate . '+ '.$nDays.' days');
echo new Date('d/m/Y', $newDate); //format new date
Here is the simplest solution to your query
$date=date_create("2013-03-15"); // or your date string
date_add($date,date_interval_create_from_date_string("40 days"));// add number of days
echo date_format($date,"Y-m-d"); //set date format of the result
This works. You can use it for days, months, seconds and reformat the date as you require
public function reformatDate($date, $difference_str, $return_format)
{
return date($return_format, strtotime($date. ' ' . $difference_str));
}
Examples
echo $this->reformatDate('2021-10-8', '+ 15 minutes', 'Y-m-d H:i:s');
echo $this->reformatDate('2021-10-8', '+ 1 hour', 'Y-m-d H:i:s');
echo $this->reformatDate('2021-10-8', '+ 1 day', 'Y-m-d H:i:s');
To add a certain number of days to a date, use the following function.
function add_days_to_date($date1,$number_of_days){
/*
//$date1 is a string representing a date such as '2021-04-17 14:34:05'
//$date1 =date('Y-m-d H:i:s');
// function date without a secrod argument returns the current datetime as a string in the specified format
*/
$str =' + '. $number_of_days. ' days';
$date2= date('Y-m-d H:i:s', strtotime($date1. $str));
return $date2; //$date2 is a string
}//[end function]
All have to use bellow code:
$nday = time() + ( 24 * 60 * 60);
echo 'Now: '. date('Y-m-d') ."\n";
echo 'Next Day: '. date('Y-m-d', $nday) ."\n";
Another option is to convert your date string into a timestamp and then add the appropriate number of seconds to it.
$datetime_string = '2022-05-12 12:56:45';
$days_to_add = 1;
$new_timestamp = strtotime($datetime_string) + ($days_to_add * 60 * 60 * 24);
After which, you can use one of PHP's various date functions to turn the timestamp into a date object or format it into a human-readable string.
$new_datetime_string = date('Y-m-d H:i:s', $new_timestamp);
I need to calculate the timestamp of exactly 7 days ago using PHP, so if it's currently March 25th at 7:30pm, it would return the timestamp for March 18th at 7:30pm.
Should I just subtract 604800 seconds from the current timestamp, or is there a better method?
strtotime("-1 week")
strtotime is your friend
echo strtotime("-1 week");
http://php.net/strtotime
echo strtotime("-1 week");
There is the following example on PHP.net
<?php
$nextWeek = time() + (7 * 24 * 60 * 60);
// 7 days; 24 hours; 60 mins; 60secs
echo 'Now: '. date('Y-m-d') ."\n";
echo 'Next Week: '. date('Y-m-d', $nextWeek) ."\n";
// or using strtotime():
echo 'Next Week: '. date('Y-m-d', strtotime('+1 week')) ."\n";
?>
Changing + to - on the first (or last) line will get what you want.
From PHP 5.2 you can use DateTime:
$timestring="2015-03-25";
$datetime=new DateTime($timestring);
$datetime->modify('-7 day');
echo $datetime->format("Y-m-d"); //2015-03-18
Instead of creating DateTime with string, you can setTimestamp directly on object:
$timestamp=1427241600;//2015-03-25
$datetime=new DateTime();
$datetime->setTimestamp($timestamp);
$datetime->modify('-7 day');
echo $datetime->format("Y-m-d"); //2015-03-18
<?php
$before_seven_day = $date_timestamp - (7 * 24 * 60 * 60)
// $date_timestamp is the date from where you found to find out the timestamp.
?>
you can also use the string to time function for converting the date to timestamp. like
strtotime(23-09-2013);