PHP for each argument passed to function - php

Question

I am passing in anywhere between 1-10 arguments to a function, I would then like the function to run itself for each argument but returning the previous data plus the new data.
So I have a function like follows:
function scrape_google_result_source($link,$link2) //$link is "test" $link2 is "test2"
{
$html = $link;
$cache = $html; //this is my first return
$html = $link2;
$cache = $cache . $html; //this is my first and second return
return $cache; //now I am returning it so it will be "testtest2"
}
this works if I manually pass in $link1 and $link2 then code it to work with them, I would like it to run itself for each argument passed in then set `$cache .= new result" so I am then returning the result for all the arguments past in together.
Sadly I have no code other than this as I am not to sure where to start with this, I did find the func_num_args(); php function that could possibly work? Any help greatly appreciated.
Thanks,
Simon

Answer 1

try this;
function scrape_google_result_source($link,$link2)
{
$numargs = func_num_args();
foreach($numargs as $n){
$link = func_get_arg($n);
$userAgent = 'Googlebot/2.1 (http://www.googlebot.com/bot.html)';
$url = $link;
$ch = curl_init();
curl_setopt($ch, CURLOPT_TIMEOUT, 100);
$html = curl_exec($ch);
$cache .= $html; //this is my first return
curl_close($ch);
}
return $cache; //now I am returning it
}
func_get_arg manual

Answer 2

Personally I find parsing arrays and looping through easier:
function scrape_google_result_source($links)
{
$cache = '';
if( !is_array( $links ) )
{
return 'not array';
}
foreach( $links as $key=>$link )
{
$userAgent = 'Googlebot/2.1 (http://www.googlebot.com/bot.html)';
$url = $link;
$ch = curl_init();
curl_setopt($ch, CURLOPT_TIMEOUT, 100);
$html = curl_exec($ch);
$cache .= $html;
curl_close($ch);
}
return $cache; //now I am returning it
}
$links_array = array( 'http..','http...');
$html = scrape_google_result_source( $links_array );