Passing each row of a mysql query to a php array - php

Question

i am running a mysql query to return all rows from a temp database, i then need to ammend some of the attributes in those rows so i am trying to return each row to an array so i can then reference the array and amend specific attributes of each row
im just stuck on how to get each row into its own array, im guessing i will need to use a 2d array for this however cannot figure out how to populate it from the mysql query into the 2d array. Im guessing it is something like i have tried below?
$result_array = array();
while ($row = mysql_fetch_assoc($res2)) {
$result_array[] = $var;
foreach($row as $key => $var) {
// Insert into array
echo $var;
}
however when trying this i am getting a notice saying:
Notice: Array to string conversion
any help pointing me in the right direction for this would be great

Answer 1

If I understand what you're asking for, you literally want each row from the SQL query to be a single index in the $result_array array?
If that's the case, you're already getting it with $row - you can add that directly to the array:
$result_array = array();
while ($row = mysql_fetch_assoc($res2)) {
$result_array[] = $row;
}
You can modify the values inside the array either when you're adding them to the global array, or after:
foreach ($result_array as $index => $row) {
$result_array[$index]['some_key'] = $row['some_key'] . ' [modified]';
}
Side-note (not answer specific)
I would recommend against using the old, deprecated mysql_ functions and instead favor MySQLi or PDO. Both of these are easy to use, more secure than the older methods and offer a large range of features such as prepared statements.
The above can be written with mysqli like:
if ($result = mysqli_query($connection, $query)) {
$results = array();
while ($row = mysqli_fetch_assoc($result)) {
$results = $row;
}
mysqli_free_result($result);
}