PHP pagination function - php

Question

public function paging($limit,$numRows,$page){
$allPages = ceil($numRows / $limit);
$start = ($page - 1) * $limit;
$querystring = "";
foreach ($_GET as $key => $value) {
if ($key != "page") $paginHTML .= "$key=$value&";
}
$paginHTML = "";
$paginHTML .= "Pages: ";
for ($i = 1; $i <= $allPages; $i++) {
$paginHTML .= "<a " . ($i == $page ? "class=\"selected\" " : "");
$paginHTML .= "href=\"?{$querystring}page=$i";
$paginHTML .= "\">$i</a> ";
}
return $paginHTML;
}
This is my pagination function for MVC pattern implementation.But this function has not displayed next and prev links.
I need to return HTML variable for pagination with previous and next link to controller.
I passed these variable to this function from controller.
$limit,$numRows,$page
How can I get next and prev links to above function.

Answer 1

I have added some conditions in the loop itself.
Hope they work.
Try the following:
<?php
public function paging($limit,$numRows,$page){
$allPages = ceil($numRows / $limit);
$start = ($page - 1) * $limit;
$querystring = "";
foreach ($_GET as $key => $value) {
if ($key != "page") $paginHTML .= "$key=$value&";
}
$paginHTML = "";
$paginHTML .= "Pages: ";
for ($i = 1; $i <= $allPages; $i++) {
if ($i>1) {
$prev = $i-1;
$paginHTML .= 'Previous';
}
$paginHTML .= "<a " . ($i == $page ? "class=\"selected\" " : "");
$paginHTML .= "href=\"?{$querystring}page=$i";
$paginHTML .= "\">$i</a> ";
if ($i<$allPages) {
$next = $i+1;
$paginHTML .= 'Next';
}
}
return $paginHTML;
}
?>

Answer 2

I'm using this pagination class like bellow inside my controller
case '' :
$page = isset ( $_REQUEST ['page'] ) ? $_REQUEST ['page'] : 1;
$limit = 5;
$allStudent = $student->getAllStudents();
$numRows = count($allStudent);
$start = ($page - 1) * $limit;
$students = $student->getStudentsWithLimit($start,$limit);
$paginHTML = $pagin->paging($limit,$numRows,$page);
$view->render('view/allStudent.php', array('allStudent' => $students,'pagin' => $paginHTML ));
break;
Get record function in Model class
public function getStudentsWithLimit($start,$limit){
$stmt = $this->db->con->query("SELECT * FROM student LIMIT $start, $limit");
$results = $stmt->fetchAll(PDO::FETCH_ASSOC);
return $results;
}

Answer 3

This should page with next and previous links with a max of 5 on either side of current page.
Pass in a function if you want the link formatted differently.
I've only given this very limited testing, and its been pulled out of a class, so you could replace some hard coded values in here with parameters of references to $this
function get_paging_links($result_count, callable $format_function=null)
{
if(!$format_function){
$format_function = function($url,$page,$qs){
$qs['page'] = $page;
return $url.'?'.http_build_query($qs);
};
}
$per_page = 5;
$total_pages = ceil($result_count / $per_page);
$return = [];
parse_str($_SERVER['QUERY_STRING'],$qs);
$url = $_SERVER['REQUEST_URI'];
//Remove existing query_string.
if($pos = strpos($url,'?')){
$url = substr($url,0,$pos);
}
$current_page = isset($qs['page']) ? $qs['page'] : 1;
$previous = $current_page -1;
if ($previous) {
$return['previous'] = $format_function($url,$previous,$qs);
}
for($i = max(1,$current_page-5); $i <= min($total_pages,$current_page+5); $i++) {
$return["$i"] = $format_function($url,$i,$qs);
}
$next_page = $current_page + 1;
if ($next_page < $total_pages){
$return['next'] = $format_function($url,$next_page,$qs);
}
return $return;
}