$i = 1;
$sql = "
SELECT
heroes.char_id, characters.char_name, heroes.class_id, heroes.count,
heroes.played, heroes.active FROM heroes, characters
WHERE characters.obj_Id = heroes.char_id AND heroes.played = 1
";
$query = mysql_query($sql);
while($row = mysql_fetch_array($query))
{
echo "
<tr>
<td><span id='lefttop'><b><font color='#007aa2'>".$i++." </font></td><td><b><font color='#f6ff00'>".$row['char_name']."</font></td></span><div style='float:right;'><td><b> ".$row['count']."</td></div> <br />
</tr>
";
}
echo "";
?>
Anyone can help? im trying to make a hero status script on a java server, and i need to connect into 2 tables which is "heroes"(this is where i get the hero) and "character" (this is where i get the hero names)
Try this Temple:
<?php
$sql1 = "SELECT * your table1";
$query1 = mysql_query($sql);
while($row1 = mysql_fetch_array($query1))
{
echo "<tr>";
$sql2 = "SELECT * your table2";
$query2 = mysql_query($sql2);
while($row2 = mysql_fetch_array($query2))
{
echo "<td>[yor Vars here]</td>";
}
echo "</tr>";
}
?>
Related
I'm trying to make a code that permits the user to show any table in my database in a php page.
I tried with that code:
<?php
include('connection_db.php');
$table = $_POST['table'];
$sql1 = "SELECT * FROM $table";
$sql2 = "SELECT count(*)
FROM information_schema.columns
WHERE table_name = '$table'";
$sql3 = "SELECT COLUMN_NAME
FROM INFORMATION_SCHEMA.COLUMNS
WHERE TABLE_NAME = N'$table'";
$result = mysql_query($sql1);
$column = mysql_query($sql2);
$ncolumn= mysql_query($sql3);
echo "<table width='100%' border='1'>";
while ($row = mysql_fetch_array($result))
{
echo "<tr>";
for ($i = 0; $i <= $column; $i++) {
echo "<td>". $row['$ncolumn'] ."</td>";
}
echo "</tr>";
echo "<br/>";
}
echo "</table>";
?>
It should show the entire table with his records, but it shows only a lot of empty lines
$table = $_POST['table'];
$mysqli = new mysqli(_DB_SERVER_,_DB_USER_,_DB_PASSWD_,_DB_NAME_);
$mysqli->set_charset("utf8");
if (mysqli_connect_errno()) {
$Message = "Connect failed: %s\n" . $mysqli->connect_error;
exit();
}
if ($result = $mysqli->query("SHOW TABLES LIKE '".$table."'")) {
if($result->num_rows == 1) {
$Tableexists = "yes";
} else {
$Tableexists = "no";
}
} else {
$Tableexists = 0;
}
echo $Tableexists;
Code will not display topics from database. I just get a blank pages.
Any solutions?
The pages loads but it will not display any thing. They want me to add more context but it breaks it so here you go.
<?php
//Database stuff.
include_once("connect.php");
if ($conn->connect_error) {
trigger_error('Database connection failed: ' . $conn->connect_error, E_USER_ERROR);
}else{
mysqli_select_db($conn,"2159928_db");
}
$tid = '';
$cid = $_GET['cid'];
$tid = $_GET['tid'];
$sql = "SELECT * FROM topics WHERE category_id='".$cid."' AND id='".$tid."' LIMIT 1";
$result = mysqli_query($conn, $sql);
if (mysqli_num_rows($result) == 1){
echo "<table width ='75%'>";
if (isset($_SESSION['uid'])) {
//echo "<form action ='post_reply.php?cid=".$cid." &tid =".$tid. "' method = 'post'>
//<input type = 'submit' name = 'submit' value = 'Reply'/>";
//echo "<tr><td colspan ='2'><center><input type='submit' value='Reply' onClick = 'window.open = 'post_reply.php?cid=".$cid." &tid =".$tid."' />";
echo "<tr><td colspan ='2'><center><input type='submit' value='Reply' onClick='window.open(\"post_reply.php?cid=$cid&tid=$tid\")' />";
} else {
echo "<tr><td colspan = '2'><p><center> Please login to reply to topics.</p></td></tr>";
}
//Trying to display this. Doesn't even display border box.
while ($row = mysqli_fetch_assoc($result)) {
$sql2 = "SELECT * FROM posts WHERE category_id='".$cid."' AND topic_id='".$tid. "'";
$result2 = mysqli_query($conn, $sql2);
while ($row2 = mysqli_fetch_assoc($result2)){
echo "<tr><td valign ='top' style = 'border: 5px solid #ffffff;'><div style = 'min-height: 125px;'>".$row['topic_title']."<br/>
by ".$row2['post_username']. " - " .$row2['post_date']. "<hr/>".$row2['post_content']."</div></td>";
}
//This part not relevant.
$old_views = $row['topic_views'];
$new_views = $old_views + 1;
$sql3 = "UPDATE topics SET topic_views='".$new_views."' WHERE category_id='".$cid."' AND id ='".$tid."' LIMIT 1";
$result3 = mysqli_query($conn, $sql3);
}
echo "</table>";
} else {
echo "<p>This topic does not exist.</p>";
}
?>
Try echo-ing out your $sql to see if the query is correct.
If query is correct. Try var_dump to see if there are any results.
The Results of <span>$invoicepartpaid1</span> and <span>$invoicepartpaid2</span> are blank. There should be sums. Any suggestions?
$query="SELECT Distinct company, car_moto, packet FROM companies where userid='$userid' ORDER BY company, car_moto, packet";
$result=mysql_query($query);
$num=mysql_numrows($result);
$i=0;
while ($i < $num) {
$f0=mysql_result($result,$i,"company");
$f1=mysql_result($result,$i,"car_moto");
$f2=mysql_result($result,$i,"packet");
$sql_1 = "SELECT SUM(price_protect) as partpaid1 FROM companies where company='$f0' and car_moto='$f1' and packet='$f2' and userid='$userid'";
$sql_2 = "SELECT SUM(clear_protect) as partpaid2 FROM companies where company='$f0' and car_moto='$f1' and packet='$f2' and userid='$userid'";
$result_1=mysql_query($sql_1) or die('Error query failed');
$result_2=mysql_query($sql_2) or die('Error query failed');
while ($row_1 = mysql_fetch_array($result_1)) {
$invoicepartpaid1 = $row_1['partpaid1'];
}
while ($row_2 = mysql_fetch_array($result_2)) {
$invoicepartpaid2 = $row_2['partpaid2'];
}
echo "<tr><td align='center'><span>$f0</span></td><td align='center'><span>$f1</span></td><td align='center'><span>$f2</span></td>";
echo "<td align='center'><span>$invoicepartpaid1</span></td><td align='center'><span>$invoicepartpaid2</span></td></tr>";
$i++;
}
Replace the line
$num=mysql_numrows($result);
By
$num=mysql_num_rows($result);
Full Code
<?php
$query="SELECT Distinct company, car_moto, packet FROM companies where userid='$userid' ORDER BY company, car_moto, packet";
$result=mysql_query($query);
$num=mysql_num_rows($result);
$i=0;
while ($row=mysql_fetch_array($result)) {// loop for all results replacing $i < $num
$f0=$row["company"];
$f1=$row["car_moto"];
$f2=$row["packet"];
$sql_1 = "SELECT SUM(price_protect) as partpaid1 FROM companies where company='$f0' and car_moto='$f1' and packet='$f2' and userid='$userid'";
$sql_2 = "SELECT SUM(clear_protect) as partpaid2 FROM companies where company='$f0' and car_moto='$f1' and packet='$f2' and userid='$userid'";
$result_1=mysql_query($sql_1) or die('Error query failed');
$result_2=mysql_query($sql_2) or die('Error query failed');
$invoicepartpaid1=0;$invoicepartpaid2=0;
while ($row_1 = mysql_fetch_array($result_1)) {
$invoicepartpaid1 = $row_1['partpaid1'];
}
while ($row_2 = mysql_fetch_array($result_2)) {
$invoicepartpaid2 = $row_2['partpaid2'];
}
echo "<tr><td align='center'><span>$f0</span></td><td align='center'><span>$f1</span></td><td align='center'><span>$f2</span></td>";
echo "<td align='center'><span>$invoicepartpaid1</span></td><td align='center'><span>$invoicepartpaid2</span></td></tr>";
$i++;
}
?>
I just can't figure out why i get the error message, I have tried removing the'' and the()
I have run the script in phpmyadmin and it says the problem with my syntax is at $result = ("SELECT * FROM 'test_prefixCatagory' ORDER by 'Cat'");
$result = ("SELECT * FROM 'test_prefixCatagory' ORDER by 'Cat'");
while($row = mysql_fetch_array($result))
$sCat = ($row['Cat']);
$sCatID = ($row['CatID']);
{
echo "<table>";
echo "<tr valign='top'><td><b><a href='#".$sCat."'>".$sCat."</a></b><br>";
// column 1 categories
$result2 = ("SELECT * FROM `test_prefixSubCat` WHERE `CatID`=$sCatID");
// sub-cats
while($row2 = mysql_fetch_array($result2))
{
$sSub = ($row2['CatID']);
$sSubID = ($row2['SubID']);
echo "<dd><a href='#'>".$sSub."</a><br>";
}
echo "<br></td></tr>";
echo "</table>";
}
Do anyone have an idea?
Try this :
<?php
$result = mysql_query("SELECT * FROM `test_prefixCatagory ORDER by `Cat`");
while ($row = mysql_fetch_array($result)) {
$sCat = $row['Cat'];
$sCatID = $row['CatID'];
echo "<table>";
echo "<tr valign='top'><td><b><a href='#" . $sCat . "'>" . $sCat . "</a></b><br>";
// column 1 categories
$result2 = mysql_query("SELECT * FROM `test_prefixSubCat` WHERE `CatID`='".$sCatID. "'");
// sub-cats
while ($row2 = mysql_fetch_array($result2)) {
$sSub = $row2['CatID'];
$sSubID = $row2['SubID'];
echo "<dd><a href='#'>" . $sSub . "</a><br>";
}
echo "<br></td></tr>";
echo "</table>";
}
?>
$result = ("SELECT * FROM `test_prefixCatagory` ORDER by `Cat`");
Not only do you need to add mysql_query but you also need to remove the single quotes from the table name and field name. You can use backticks if you wish but not single quotes around table names.
$result = mysql_query("SELECT * FROM `test_prefixCatagory` ORDER by `Cat`");
// other query:
$result2 = mysql_query("SELECT * FROM `test_prefixSubCat` WHERE `CatID`=$sCatID");
When debugging MySQL problems, use mysql_error() to see a description of the problem.
As of now I have no errors in my program, but I need the primary key for one of the tables for a relation for the following Query. but instead of getting a actual number the value the query is sending back is Resource id #4
Here is my Code: (The query that I'm having issues with is the $sql_branch, is there a function to change the result from "Resource id #4" to just 4?
$sql_branch = "SELECT BranchNum
FROM Branch
WHERE BranchName = '$_POST[branch]'";
$sql_result = "SELECT AuthorFirst, AuthorLast, OnHand, Title
FROM Inventory i, Wrote w, Author a, Book b
WHERE i.BookCode = b.BookCode AND i.BookCode = w.BookCode
AND a.AuthorNum = w.AuthorNum AND i.BranchNum = 1";
$connect = mysql_connect('students', 'xxxx', 'xxxx') or exit(mysql_error());
mysql_select_db('henrybooks', $connect);
if(mysql_query($sql_branch, $connect)) {
$branch = mysql_query($sql_branch, $connect);
}
else {
echo mysql_error();
}
if(mysql_query($sql_result, $connect)) {
$result = mysql_query($sql_result, $connect);
}
else {
echo mysql_error();
}
echo $branch."<br>";
echo $sql_branch."<br>";
echo "<table>
<tr>
<td>Author</td>
<td>Title</td>
<td>Number Available</td>
</tr>";
while( $row = mysql_fetch_array($result)) {
echo "<tr>";
echo "<td>".$row['AuthorFirst'].$row['AuthorLast']."</td>";
echo "<td>".$row['Title']."</td>";
echo "<td>".$row['OnHand']."</td>";
echo "</tr>";
}
echo "</table>";
?>
Thanks!
You are not pulling results from the mysql_query. Try this:
if($branch_result = mysql_query($sql_branch, $connect)) {
$branch = mysql_fetch_array($branch_result);
}