I am attempting to get a JSON feed output from attributes of an XML feed. I can get the data out of the XML, however, I am unable to get it to format correctly. The error seems to be with the json_encode not adding the curly braces to the outputted date. This is the code I have so far:
<?php
$url = 'http://cloud.tfl.gov.uk/TrackerNet/LineStatus';
if(!$xml = simplexml_load_file($url))
{
die("No xml for you");
}
$linestatus = array();
foreach ($xml->LineStatus as $line)
{
echo $line->Line['Name'];
echo $line->Status['Description'];
}
header('Content-Type: application/json');
print_r(json_encode($linestatus));
?>
The problem is that you're not storing the name and description into the array.
Try this:
foreach ($xml->LineStatus as $line)
{
$linestatus[] = array('name' => $line->Line['Name']);
$linestatus[] = array('description' => $line->Line['Description']);
}
Demo!
The echos are screwing everything up. I think you intend to append to linestatus which remains empty per your code.
$linestatus[] = array(
"name" => $line->Line['Name'],
"description" => $line->Status['Description']
);
You also need to use echo instead of print_r to actually emit the JSON.
You are declaring $linestatus as an array, then never put anything in it before finally encoding it and trying to output it. Of course it won't work as expected! Instead, you should be populating it with values:
$linestatus = array();
foreach ($xml->LineStatus as $line)
{
$linestatus[] = $line->Line;
}
header('Content-Type: application/json');
print_r(json_encode($linestatus));
Related
If you open the URL, you'll see that it's a very long string of sub objects. I want to extract the values for the 70 position. So far I've been able to extract the first tree without a problem ... But if you go deeper then I don’t get any feedback at all. Please check the code below and tell me, what am I doing wrong?
$url= "https://bwt.cbp.gov/api/waittimes";
$port = file_get_contents($url); // put the contents of the file into a variable
$data = json_decode($port); // decode the JSON feed
echo $data[69]->port_name.'<br>';
echo $data[69]->port_status.'<br>';
echo $data[69]->passenger_vehicle_lanes->maximum_lanes.'<br>';
echo $data[69]->passenger_vehicle_lanes->standard_lanes->lanes_open.'<br>';
The following is working for me:
$url= "https://bwt.cbp.gov/api/waittimes";
$port = file_get_contents($url); // put the contents of the file into a variable
$data = json_decode($port, true); // decode the JSON feed
echo "There are ".count($data)."Ports".PHP_EOL;
$found=false;
foreach ($data as $key => $value) {
//EDIT AFTER COMMENT**
if($value['port_number']==250401){
echo $value['port_name'].' '.$value['crossing_name'].PHP_EOL;
$found=true;
break;
}
}
if(!$found) echo "couldn't find port #";
can you try to change json_decode($port, true); (true will change object to array and it will be better to access it) like this and access it like in array echo $data[69]['passenger_vehicle_lanes']['maximum_lanes'].'<br>';
I am trying to figure out how to fwrite into a .php file with variables given through $_POST, or $_GET, supplied by the user to set variables and such. So, how would I go about getting the below code to work so that instead of fwriting the code, insert a $_GET variable for example, or in the below description, being $derp.
<?php
$derp = "working!";
$something = '<?php echo "Well Thats {$derp}' ?>';
$file = fopen("worked.php","w");
if (fwrite($file,$something) > 0) {
echo "Fwrite Successful!";
}
fclose($file);
?>
Although this use case looks very weird the following should work:
$data = array('<?php');
foreach ($_REQUEST as $key => $value) {
$data[] = "\$$key = \"$value\";";
}
$data[] = '?>';
$data = join("\n", $data);
file_put_contents('/path/to/file.php', $data);
Beware: This code imposes several security risks.
WTF is going on here?
The above code iterates through all array elements of $_GET and $_POST, combined.
By that it creates an array of lines to be written to a file.
This array will then be join()ed into a string by using the NEWLINE ascii character as the glue.
Assuming this script is called with the following query string:
?foo=bar&bar=baz
The file /path/to/file.php will then contain (file_put_contents):
<?php
$foo = "bar";
$bar = "baz";
?>
The example above does not support nested query parameters like foo[bar]=baz.
I use this :
<?php
foreach($_SERVER as $key => $value){
echo "<b>$key:</b> $value<br>\n";
}
?>
Which outputs in browser. Is there anyway to redirect output to file and hide it from the browser page ?
I would suggest something like:
<?php
foreach($_SERVER as $key => $value)
{
file_put_contents('the_file.txt', "<b>$key:</b> $value<br>\n", FILE_APPEND);
}
?>
Make sure that the_file.txt has write permissions.
Instead of echoing build an output to put in your file:
<?php
$in='';
foreach($_SERVER as $key => $value){
$in .= $key.' - '.$value.PHP_EOL;
}
//save it
file_put_contents('_SERVER.txt', $in);
?>
Also, Your not going to want to add any html tags.
To write a file you would want to use file_put_contents(). To generate a (human) readable representation of the contents of $_SERVER you should look into print_r() or var_export().
file_put_contents("/tmp/exported-server.txt", print_r($_SERVER, true));
using $s = print_r($_SERVER), $s = var_export($_SERVER) or even ob_start(); var_dump($_SERVER); $s = ob_get_clean(); makes sure you get a proper visualization of any value type. Your approach only works well for strings and numbers, but fails for arrays, objects, …
I am new to JS & JSON.I am struggle with converting JSON array to JavaScript array.How to do that? Here is my code:
var data = {
items: [
<? $i=1; foreach($query->result() as $row){ ?>
<? if($i!=1){ ?>,<? } ?>
{label: '<?=$row->district_name;?>', data: <?=$row->countid;?>}
<? $i++; } ?>
]
};
how to get the JSON array value to JavaScript Array.
i just tried but it doesn't work. please some suggestions.
here is my javascript array
for(i=0;i<5;i++){
chartData[i]=data.items[i].label+";"+data.items[i].data;
}
As the others already said, be careful when talking about JavaScript and JSON. You actually want to create a JavaScript object and not JSON.
Don't mix PHP and JavaScript like this. It is horrible to maintain. Create an array beforehand, encode it as JSON* and print it:
<?php
$results = $query->result(); // get results
function m($v) { // a helper function for `array_map`
return array('label' => $v->district_name,
'data' => $v->countid);
}
$data = array('items' => array_map('m', $results));
?>
var data = <?php echo json_encode($data); ?>
*: Here we use the fact that a JSON string is valid JavaScript too. You can just echo it directly in the JavaScript source code. When the JS code runs, it is not JSON, it is interpreted as JavaScript object.
You really oughtn't think too hard about this. PHP does a fine job of serializing arrays as JSON.
var data = {
items: <?php
$arr = array();
foreach($query->result() as $row) {
$arr[] = array('label' => $row->district_name,
'data' => $row->countid);
}
echo json_encode($arr);
?>
};
[insert same disclaimer as above about how you're really trying to create a JavaScript object]
This is JSON:
var foo = "{bar: 1}";
This is not JSON:
var foo = {bar: 1};
Your code snippet is not using JSON at all and my educated guess is that you don't even need it. If you are using PHP to generate some JavaScript code, you can simply tweak your PHP code to print text that will contain real JavaScript variables. There is no need to encode stuff as plain text!
Now it's clear we don't need JSON, let's use a dirty trick. PHP has json_encode() and we can abuse the fact that a JSON strings resemble JavaScript variables. All we have to do is call json_encode() on our PHP variable and forget to quote the result:
<?php
$foo = array(
'bar' => 1,
'dot' => FALSE,
);
echo 'var JSONString = "' . json_encode($foo) . '";' . PHP_EOL;
echo 'var realVariable = ' . json_encode($foo) . ';' . PHP_EOL;
Compare:
var JSONString = "{"bar":1,"dot":false}";
var realVariable = {"bar":1,"dot":false};
Edit: Yep, my JSONString is not a valid string... but we get the idea <:-)
I have a PHP script that's being called through jQuery AJAX. I want the PHP script to return the data in JSON format to the javascript. Here's the pseudo code in the PHP script:
$json = "{";
foreach($result as $addr)
{
foreach($addr as $line)
{
$json .= $line . "\n";
}
$json .= "\n\n";
}
$json .= "}";
Basically, I need the results of the two for loops to be inserted in $json.
Php has an inbuilt JSON Serialising function.
json_encode
json_encode
Please use that if you can and don't suffer Not Invented Here syndrome.
Here are a couple of things missing in the previous answers:
Set header in your PHP:
header('Content-type: application/json');
echo json_encode($array);
json_encode() can return a JavaScript array instead of JavaScript object, see:
Returning JSON from a PHP Script
This could be important to know in some cases as arrays and objects are not the same.
There's a JSON section in the PHP's documentation. You'll need PHP 5.2.0 though.
As of PHP 5.2.0, the JSON extension is bundled and compiled into PHP by default.
If you don't, here's the PECL library you can install.
<?php
$arr = array ('a'=>1,'b'=>2,'c'=>3,'d'=>4,'e'=>5);
echo json_encode($arr); // {"a":1,"b":2,"c":3,"d":4,"e":5}
?>
Usually you would be interested in also having some structure to your data in the receiving end:
json_encode($result)
This will preserve the array keys as well.
Do remember that json_encode only works on utf8 -encoded data.
You can use Simple JSON for PHP. It sends the headers help you to forge the JSON.
It looks like :
<?php
// Include the json class
include('includes/json.php');
// Then create the PHP-Json Object to suits your needs
// Set a variable ; var name = {}
$Json = new json('var', 'name');
// Fire a callback ; callback({});
$Json = new json('callback', 'name');
// Just send a raw JSON ; {}
$Json = new json();
// Build data
$object = new stdClass();
$object->test = 'OK';
$arraytest = array('1','2','3');
$jsonOnly = '{"Hello" : "darling"}';
// Add some content
$Json->add('width', '565px');
$Json->add('You are logged IN');
$Json->add('An_Object', $object);
$Json->add("An_Array",$arraytest);
$Json->add("A_Json",$jsonOnly);
// Finally, send the JSON.
$Json->send();
?>
$msg="You Enter Wrong Username OR Password";
$responso=json_encode($msg);
echo "{\"status\" : \"400\", \"responce\" : \"603\", \"message\" : \"You Enter Wrong Username OR Password\", \"feed\":".str_replace("<p>","",$responso). "}";