I created this regexp but finds only the first occurrence, where am I wrong?
$pattern = '/\\[h-imagegallery id=([0-9,]+)\\]/';
$subject = 'ueihui [h-imagegallery id=4,55] jwff [h-imagegallery id=425]';
print_r($matches);
the result is:
Array
(
[0] => [h-imagegallery id=4,55]
[1] => 4,55
)
Related
I am new to using preg_match and I am having a hard time trying to grasp it. For example for this code below.. It only returns one match which is "h" .. isn't is supposed to return an array of 3 key value pairs?
$subject = "hey";
preg_match("/[a-z]/", $subject, $matches);
print_r($matches);
To return more matches you use preg_match_all() instead,
$subject = "hey";
preg_match_all("/[a-z]/", $subject, $matches);
print_r($matches);
This would print,
Array
(
[0] => Array
(
[0] => h
[1] => e
[2] => y
)
)
I have a very long string of html. From this string I want to parse pairs of rus and eng names of cities. Example of this string is:
$html = '
Абакан
Хакасия республика
Абан
Красноярский край
Абатский
Тюменская область
';
My code is:
$subject = $this->html;
$pattern = '/<a href="([\/a-zA-Z0-9-"]*)">([а-яА-Я]*)/';
preg_match_all($pattern, $subject, $matches);
For trying I use regexer . You can see it here http://regexr.com/399co
On the test used global modifier - /g
Because of in PHP we can't use /g modifier I use preg_match_all function. But result of preg_match_all is very strange:
Array
(
[0] => Array
(
[0] => <a href="/forecasts5000/russia/republic-khakassia/abakan">Абакан
[1] => <a href="/forecasts5000/russia/krasnoyarsk-territory/aban">Абан
[2] => <a href="/forecasts5000/russia/tyumen-area/abatskij">Аба�
[3] => <a href="/forecasts5000/russia/arkhangelsk-area/abramovskij-ma">Аб�
)
[1] => Array
(
[0] => /forecasts5000/russia/republic-khakassia/abakan
[1] => /forecasts5000/russia/krasnoyarsk-territory/aban
[2] => /forecasts5000/russia/tyumen-area/abatskij
[3] => /forecasts5000/russia/arkhangelsk-area/abramovskij-ma
)
[2] => Array
(
[0] => Абакан
[1] => Абан
[2] => Аба�
[3] => Аб�
)
)
First of all - it found only first match (but I need to get array with all matches)
The second - result is very strange for me. I want to get the next result:
pairs of /forecasts5000/russia/republic-khakassia/abakan and Абакан
What do I do wrong?
Element 0 of the result is an array of each of the full matches of the regexp. Element 1 is an array of all the matches for capture group 1, element 2 contains capture group 2, and so on.
You can invert this by using the PREG_SET_ORDER flag. Then element 0 will contain all the results from the first match, element 1 will contain all the results from the second match, and so on. Within each of these, [0] will be the full match, and the remaining elements will be the capture groups.
If you use this option, you can then get the information you want with:
foreach ($matches as $match) {
$url = $match[1];
$text = $match[2];
// Do something with $url and $text
}
You can also use T-Regx library which has separate methods for each case :)
pattern('<a href="([/a-zA-Z0-9-"]*)">([а-яА-Я]*)')
->match($this->html)
->forEach(function (Match $match) {
$match = $match->text();
$group = $match->group(1);
echo "Match $match with group $group"
});
I also has automatic delimiters
i want to get a particular value from string in php. Following is the string
$string = 'users://data01=[1,2]/data02=[2,3]/*';
preg_replace('/(.*)\[(.*)\](.*)\[(.*)\](.*)/', '$2', $str);
i want to get value of data01. i mean [1,2].
How can i achieve this using preg_replace?
How can solve this ?
preg_replace() is the wrong tool, I have used preg_match_all() in case you need that other item later and trimmed down your regex to capture the part of the string you are looking for.
$string = 'users://data01=[1,2]/data02=[2,3]/*';
preg_match_all('/\[([0-9,]+)\]/',$string,$match);
print_r($match);
/*
print_r($match) output:
Array
(
[0] => Array
(
[0] => [1,2]
[1] => [2,3]
)
[1] => Array
(
[0] => 1,2
[1] => 2,3
)
)
*/
echo "Your match: " . $match[1][0];
?>
This enables you to have the captured characters or the matched pattern , so you can have [1,2] or just 1,2
preg_replace is used to replace by regular expression!
I think you want to use preg_match_all() to get each data attribute from the string.
The regex you want is:
$string = 'users://data01=[1,2]/data02=[2,3]/*';
preg_match_all('#data[0-9]{2}=(\[[0-9,]+\])#',$string,$matches);
print_r($matches);
Array
(
[0] => Array
(
[0] => data01=[1,2]
[1] => data02=[2,3]
)
[1] => Array
(
[0] => [1,2]
[1] => [2,3]
)
)
I have tested this as working.
preg_replace is for replacing stuff. preg_match is for extracting stuff.
So you want:
preg_match('/(.*?)\[(.*?)\](.*?)\[(.*?)\](.*)/', $str, $match);
var_dump($match);
See what you get, and work from there.
I have a string contains the following pattern "[link:activate/$id/$test_code]" I need to get the word activate, $id and $test_code out of this when the pattern [link.....] occurs.
I also tried getting the inside items by using grouping but only gets active and $test_code couldn't get $id. Please help me to get all the parameter and action name in array.
Below is my code and output
Code
function match_test()
{
$string = "Sample string contains [link:activate/\$id/\$test_code] again [link:anotheraction/\$key/\$second_param]]] also how the other ationc like [link:action] works";
$pattern = '/\[link:([a-z\_]+)(\/\$[a-z\_]+)+\]/i';
preg_match_all($pattern,$string,$matches);
print_r($matches);
}
Output
Array
(
[0] => Array
(
[0] => [link:activate/$id/$test_code]
[1] => [link:anotheraction/$key/$second_param]
)
[1] => Array
(
[0] => activate
[1] => anotheraction
)
[2] => Array
(
[0] => /$test_code
[1] => /$second_param
)
)
Try this:
$subject = <<<'LOD'
Sample string contains [link:activate/$id/$test_code] again [link:anotheraction/$key/$second_param]]] also how the other ationc like [link:action] works
LOD;
$pattern = '~\[link:([a-z_]+)((?:/\$[a-z_]+)*)]~i';
preg_match_all($pattern, $subject, $matches);
print_r($matches);
if you need to have \$id and \$test_code separated you can use this instead:
$pattern = '~\[link:([a-z_]+)(/\$[a-z_]+)?(/\$[a-z_]+)?]~i';
Is this what you are looking for?
/\[link:([\w\d]+)\/(\$[\w\d]+)\/(\$[\w\d]+)\]/
Edit:
Also the problem with your expression is this part:
(\/\$[a-z\_]+)+
Although you have repeated the group, the match will only return one because it is still only one group declaration. The regex won't invent matching group numbers for you (Not that i've ever seen anyway).
I need to save the number between every pair of curly brackets as a variable.
{2343} -> $number
echo $number;
Output = 2343
I don't know how to do the '->' part.
I've found a similar function, but it simply removes the curly brackets and does nothing else.
preg_replace('#{([0-9]+)}#','$1', $string);
Is there any function I can use?
You'll probably want to use preg_match with a capture:
$subject = "{2343}";
$pattern = '/\{(\d+)\}/';
preg_match($pattern, $subject, $matches);
print_r($matches);
Output:
Array
(
[0] => {2343}
[1] => 2343
)
The $matches array will contain the result at index 1 if it is found, so:
if(!empty($matches) && isset($matches[1)){
$number = $matches[1];
}
If your input string can contain many numbers, then use preg_match_all:
$subject = "{123} {456}";
$pattern = '/\{(\d+)\}/';
preg_match_all($pattern, $subject, $matches);
print_r($matches);
Output:
Array
(
[0] => Array
(
[0] => {123}
[1] => {456}
)
[1] => Array
(
[0] => 123
[1] => 456
)
)
$string = '{1234}';
preg_replace('#{([0-9]+)}#e','$number = $1;', $string);
echo $number;