Map value to color scale - php

I have a list of values which should be plotted to a map with a certain color.
The plotting to the map is already done, but I need to figure out a way to map the value n to a color that represents its value.
An example and my solution so far is to normalize the values based on the min and max and then assign them to hex color 0 for the lowest and 255 for the highest. This of course limits my self to the grey scale. Here is the code:
$color = ($value / $max) * 255 // (min is zero)
But how to do this if the values should go from blue to red for instance?
Is there any common libraries or tools that can solve this? So far I haven't been able to locate any.

There might be libs to do that. However let's get a short warm up into the general principles. In general you have following options:
A predefined color index, e.g. $coloridx=array(0=>'#FFFFFF',1=>'#FFEE00',...);
Any algorithm, e.g. linear gradient, which is basically an iterations based adaption of all three RGB channels (R = red, G = green, B = blue).
A combination of both, which usually puts the result of any complex algorithm to the color index and then goes from there.
If you include algorithms in your considerations you must understand that there is no true or false. It all depends on what you would like to implement. There might be occasions where it makes sense to render variations of green into n=0..10 and then have red to black in everything beyond n>10. Caps and multipliers help to set accents. Things like that.
One way of implementing a linear gradient would be:
function lineargradient($ra,$ga,$ba,$rz,$gz,$bz,$iterationnr) {
$colorindex = array();
for($iterationc=1; $iterationc<=$iterationnr; $iterationc++) {
$iterationdiff = $iterationnr-$iterationc;
$colorindex[] = '#'.
dechex(intval((($ra*$iterationc)+($rz*$iterationdiff))/$iterationnr)).
dechex(intval((($ga*$iterationc)+($gz*$iterationdiff))/$iterationnr)).
dechex(intval((($ba*$iterationc)+($bz*$iterationdiff))/$iterationnr));
}
return $colorindex;
}
$colorindex = lineargradient(
100, 0, 0, // rgb of the start color
0, 255, 255, // rgb of the end color
256 // number of colors in your linear gradient
);
$color = $colorindex[$value];
I UPDATED the code to add dechex, which feeds back on the comments.

Colors values are representations. Numeric colors as well as hexadecimal colors. A "not grayscale" color contains at least 2 different informations: Red value, green value or blue values may be different. Performing operation on its representation gives wrong result. The 'Mapping" must then be performed on each pieces of information. You need to extract red, green and blue values, perform the mapping seperatly, then build the representation of the result color. Here is a quick helper that use a "min color" and "max color", performs mapping on red, green and blue values, according to the "n" value you need to work with, then return the result color in hexadecimal string. It works for any colors or gray scale color as well.
function linear_color($from, $to, $ratio) {
// normalize ralio
$ratio = $ratio<0?0:($ratio>1?1:$ratio);
// unsure colors are numeric values
if(!is_numeric($from))$from=hexdec($from);
if(!is_numeric($to))$to=hexdec($to);
$rf = 0xFF & ($from >> 0x10);
$gf = 0xFF & ($from >> 0x8);
$bf = 0xFF & $from;
$rt = 0xFF & ($to >> 0x10);
$gt = 0xFF & ($to >> 0x8);
$bt = 0xFF & $to;
return str_pad( dechex(($bf + (($bt-$bf)*$ratio)) + ($gf + (($gt-$gf)*$ratio) << 0x8) + ($rf + (($rt-$rf)*$ratio) << 0x10)), 6,'0',STR_PAD_LEFT);
}
Just specify 2 colors as numeric value or hexadecimal string (without hash!) like this :
$color_from = hexdec('c2c2c2');
$color_to = hexdec('1eb02b');
for($i=-0.2; $i<=1.3; $i+=0.04){
echo '<div style="background-color: #';
echo linear_color($color_from, $color_to, $i);
echo '">';
echo 'Result color when n = <strong>'.$i.'</strong>';
echo '</div>';
}

The other answer was very usefull. I decided to use JS as it reduces server load. The requirements also changed. The bar has to go from Red to white in the middle and then from white to yellow. And if the value is 0 it should be black. Here is my code for anyone who ever encounters a similar situation.
var normalize_base = 2*255;
var no_con_color = "black";
function decimalToHex(d, padding) {
var hex = Number(d).toString(16);
padding = typeof (padding) === "undefined" || padding === null ? padding = 2 : padding;
while (hex.length < padding) {
hex = "0" + hex;
}
return hex;
}
function normalize(max, min, value)
{
var normalized = (value - min) / (max - min) ;
return Math.floor(normalized * normalize_base);
}
function value2Color(value)
{
if(value <= 0 || value == undefined)
{
return no_con_color;
}
var g = 0;
var b = 0;
var r = 0;
if(value < 255)
{
r = 255;
g = value;
b = value;
} else {
r = (2*255) - value;
g = 255;
b = (2*255) - value;
}
return "#" + decimalToHex(r) + decimalToHex(g) + decimalToHex(b);
}

There is I2UI for this.
<div data-i2="color:['#404040','#00FF21']">
<span data-i2="rate:1">A</span>
<span data-i2="rate:2">B</span>
<span data-i2="rate:3">C</span>
<span data-i2="rate:4">D</span>
<span data-i2="rate:5">E</span>
</div>
There is a color range: from "Gray" - to "Green". The span element that has lowest rate value get the "Gray" color, the element with the biggest rate get "Green" color.
Thus, the span that are between edges get the color that has direct ratio to its rate.
Also, call JavaScript i2.emph() after the previous HTML have been loaded.
See demo

This is one-function-only code to convert any number from any given range (let's say [0,20]) to particular color where 0 is red, 10 is yellow, 20 is green. You can use any colors and even use combination of 4 colors, so it's red - yellow - green - blue.
See the end of the gist file, where this function is used.
Gist with the code:
Click here

Related

How to quantify colors in an image like Google does (somewhat)?

I've been searching this for a long time now and I want to know if any of you has some kind of resource or knowledge of some kind of algorithm that can take an image and return the percentage of most significant colors in an image. But not any color, I want to make the percentages fit with a predefined constant palette of 12 colors (the same you use in image search on google for sorting).
However, the script I made works in the sense that it gets the colors that are most PRESENT, but not necessarily most significant.
For example, take this image of the first black hole. It has mostly only black with some smudges of red/white/yellow/brown colors. But in proportions these are considered as almost nothing by checking only their amount.
Example: red = 1%, yellow = 3% and black = 96% (not exact values but accurate).
The problem is that even though they are not the most in amount, they are clearly the MAIN colors in the image as for how the human eye sees them. Is there an algorithm for that or a technique? Thank you for reading.
Let's say your image has resolution WxH.
You say you have a palette of 12 colors.
In order to make an algorithm that sort this colors based on how much they appear in the image, you could create 3 variables:
A global counter counter of valid colors within the image;
array of frequencies with length equals to palette size;
array of colors representing the palette.
A possible algorithm could be:
for(int i = 0; i < W; i++){
for(int j = 0; j < H; j++){
Color dif = new Color(255, 255, 255, 1);
Color currDif;
int minIndex = -1;
for(int k = 0; k < palette.length; k++){
currDif = palette[k] - image[i][j];
if(dif > currDif){
dif = currDif;
minIndex = k;
}
}
if( CloseEnough(dif, palette[minIndex]) ){
frequency[minIndex]++;
counter++;
}
}
}
Then, to verify the percentages, one can just:
for(int i = 0; i < 12; i++){
print("Color i appears (Palette[i] / counter) %");
}
I considered if you find a color that is not close enough to any color in the palette, you ignore it, but obviously you can consider it by simply incrementing the counter anyway, so these colors will be the percentage left.
The functions CloseEnough and < are of your choice to make, but they could work like this:
bool CloseEnough(Color c1, Color c2){
return abs(c1.r - c2.r) < 30 && abs(c1.g - c2.g) < 30 && abs(c1.b - c2.b) < 30;
//note that 30 can be quite small
//this value can be modified based on testing and result quality
}
//the closer to black a color is, the smaller it will be
bool < (Color c1, Color c2){
return (c1.r + c1.g + c1.b) < (c2.r + c2.b + c2.g);
}
There may be better solutions out there, but hope it helps.

randomly generating colors with php

So I'm working on making my header change color everyday, and I was attempting to create this using a random color. There are 2 colors in the header and I am making them complimentary colors. the first color is generated randomly, and then the second is modified by changing the Hue via 150`. The problem is when certain colors are chosen, they could be either too vibrant or dark. I have a check running so that I can slightly control the brightness value, but there are still some colors that are too bright ( for instance extreme yellows ). I'l post my code below. Any help or suggestions is appreciated! Thanks!
// grab a random color on hue
$h = rand(0,360);
// color values 50-120 tend to be extremely bright,
// make adjustments to the S and L accordingly
// a better solution is available?
if ($h > 50 && $h < 120) {
$s = rand(60,80);
$l = rand(30,50);
} else {
$s = rand(60,90);
$l = rand(38,63);
}
// declare string to place as css in file for primary color
$randomColor = "hsl(". $h .",". $s ."%,". $l ."%)";
// declare degree for secondary color (30 = analogous, 150 = complimentary)
$degree = 150;
// point to secondary color randomly on either side of chart
$bool = rand(0,1);
if ($bool) {
$x = $degree;
} else {
$x = -$degree;
}
// set value of the new hue
$nh = $h + $degree;
// if the new hue is above 360 or below 0, make adjustments accordingly
if ($nh > 360) {
$nh -= 360;
}
if ($nh < 0 ) {
$nh = 360 - $nh;
}
// set the secondary color
$secondaryColor = "hsl(". abs($h + $x) .",". $s ."%,". $l ."%)";
This seems very simple and I'm sure there is a better method. I looked around, but all I noticed were the basic formula's via degrees for the hue etc. Thanks again!
This is really more of a question of which colors you deem acceptable for viewing. This certainly isn't an optimal solution but it's an approach that is readable at least (it's also slightly more random than your original, if you even care about that):
function randColor() {
return array( rand(0,360), rand(0,100), rand(0,100) );
}
function isAcceptableColor($colorArr) {
// return true if the color meets your criteria
}
do {
$color = randColor();
} while ( ! isAcceptableColor($color) );

Php function order color by lightness

Is it possible to sort colors by php on lightness .
Now i calc the differenct with this function
public function colorDiff($rgb1,$rgb2)
{
// do the math on each tuple
// could use bitwise operates more efeceintly but just do strings for now.
$red1 = hexdec(substr($rgb1,0,2));
$green1 = hexdec(substr($rgb1,2,2));
$blue1 = hexdec(substr($rgb1,4,2));
$red2 = hexdec(substr($rgb2,0,2));
$green2 = hexdec(substr($rgb2,2,2));
$blue2 = hexdec(substr($rgb2,4,2));
return abs($red1 - $red2) + abs($rgreen1 - $green2) + abs($blue2 - $blue2) ;
}
But this will not sort images on lightness.
You can get a decent value for luminance (the perceived lightness) with the following formula:
$red * .3 + $green * .59 + $blue * .11
Quoting from the linked article:
The explanation for these weights is due to the fact that for equal amounts of color the eye is most sensitive to green, then red, and then blue. This means that for equal amounts of green and blue light the green will, nevertheless, seem much brighter."
1) You need math defination of lightness. So it should function from color to integer that represent lightness
2) If you suppose (for example) than it is sum of $red+$green+$blue you can use this kind of sort
usort($colors,function ($rgb1,$rgb2){
$red1 = hexdec(substr($rgb1,0,2));
$green1 = hexdec(substr($rgb1,2,2));
$blue1 = hexdec(substr($rgb1,4,2));
$red2 = hexdec(substr($rgb2,0,2));
$green2 = hexdec(substr($rgb2,2,2));
$blue2 = hexdec(substr($rgb2,4,2));
return ($red1+$green1+$blue1) - ($reg2+$green2+$blue2);
})
You could convert your RGB color to HSL colorspace and the sort on the L component:
http://axonflux.com/handy-rgb-to-hsl-and-rgb-to-hsv-color-model-c

Color coding based on number

I want to display a color between red, yellow, green depending on a number between 1 to 100.
1 being green and 100 being red, 50 being yellow. I want to basically create a gradient between that.
So far, I tried:
$r = floor(255 * ($number / 100));
$g = 255 - $r;
And it somewhat does it, but gives me brownish & dark colors, & no yellow at all.
It's because you shouldn't change both channels at once but rise R in the first half and lower G in the second.
Try a function like this:
function GreenYellowRed($number) {
$number--; // working with 0-99 will be easier
if ($number < 50) {
// green to yellow
$r = floor(255 * ($number / 50));
$g = 255;
} else {
// yellow to red
$r = 255;
$g = floor(255 * ((50-$number%50) / 50));
}
$b = 0;
return "$r,$g,$b";
}
To test it:
$output = "";
for ($i = 1; $i <= 100; $i++) {
$rgb = GreenYellowRed($i);
$output .= "<div style='background-color: rgb($rgb)'>$rgb</div>";
}
echo $output;
I've found that dealing with the HSV color model is easier than the RGB model. It helps you easily choose the color you want to work with; with RGB you'd need to understand how different values of R, G and B will combine to give you the color you want/don't want.
Also, this SO question might be useful: How can I cycle through hex color codes in PHP?
I don't know of a mathematical model for a "color curve" that passes through specified RGB color values (e.g. what you describe as green/yellow/red), which would allow you to calculate any intermediate color in that curve. In any case, a model of a function (which is what that would be) is only as good as the data points it needs to fit, so you 'd have to be much more specific than green/yellow/red to get decent results even if someone points out the math.
Remember that we are not interested in mathematical interpolation here, but rather in "color-space interpolation" (a term which I just made up) -- in other words, what would look like a "natural" interpolation to a human.
An easier solution for those of us who do not have the necessary color theory knowledge, and which I 'd suggest, is to pre-select a number of colors with a color picker tool, divide the 0-100 range into as many bands as the colors you picked, and use simple integer division to project from 0-100 to a color band.
Food for thought: Indeed, how does SO decide the color of the upvote count for comments?
Update: I just asked the above over on meta. Let's see...
After a bit of looking, none of the solutions looked pleasing. As stated above, HSV is probably the way to go, since modern browsers can render color with it just fine.
To get a good idea of the colors you are working with, check out this color wheel:
http://www.colorspire.com/rgb-color-wheel/
I want to start with blue, so I use 255 for normalization.
function temp_color($temp){
$start = 40;
$end = 85;
$normal = round(255-((($temp - $start)/($end-$start))*255));
$color = "hsl($normal, 100%, 30%);";
$span = "<span style=\"color: $color\">$temp</span>";
return $span;
}

Hex Code Brightness PHP?

I want users on my website to be able to pick a hex colour, and I just want to display white text for dark colours and black text for light colours. Can you work out the brightness from a hex code (preferably PHP)?
$hex = "78ff2f"; //Bg color in hex, without any prefixing #!
//break up the color in its RGB components
$r = hexdec(substr($hex,0,2));
$g = hexdec(substr($hex,2,2));
$b = hexdec(substr($hex,4,2));
//do simple weighted avarage
//
//(This might be overly simplistic as different colors are perceived
// differently. That is a green of 128 might be brighter than a red of 128.
// But as long as it's just about picking a white or black text color...)
if($r + $g + $b > 382){
//bright color, use dark font
}else{
//dark color, use bright font
}
I made one similar - but based on weightings of each colour (based on the C# version of this thread)
function readableColour($bg){
$r = hexdec(substr($bg,0,2));
$g = hexdec(substr($bg,2,2));
$b = hexdec(substr($bg,4,2));
$contrast = sqrt(
$r * $r * .241 +
$g * $g * .691 +
$b * $b * .068
);
if($contrast > 130){
return '000000';
}else{
return 'FFFFFF';
}
}
echo readableColour('000000'); // Output - FFFFFF
EDIT:
Small optimisation:
Sqrt is known as an expensive math operation, which is probably neglectable in most scenarios, but anyway, it could be avoided by doing something like this.
function readableColour($bg){
$r = hexdec(substr($bg,0,2));
$g = hexdec(substr($bg,2,2));
$b = hexdec(substr($bg,4,2));
$squared_contrast = (
$r * $r * .299 +
$g * $g * .587 +
$b * $b * .114
);
if($squared_contrast > pow(130, 2)){
return '000000';
}else{
return 'FFFFFF';
}
}
echo readableColour('000000'); // Output - FFFFFF
It simply doesn't apply the sqrt, instead it powers the desired cut off contrast by two, which is a much cheaper calculation
I know this is a very old topic, but for users who came from "Google Search", this link may be what they are looking for. I've searched for something like this and I think it's a good idea to post it here:
https://github.com/mexitek/phpColors
use Mexitek\PHPColors\Color;
// Initialize my color
$myBlue = new Color("#336699");
echo $myBlue->isLight(); // false
echo $myBlue->isDark(); // true
That's it.
You need to convert the RGB values to HLS/HSL (Hue Lightness and Saturation) you can then use the Lightness to determine whether you need light text or dark text.
This page has some details on how to the conversion in PHP as well as selecting complementary colour from this.
I've only just spotted that the site is an astrology site - so apologies if anyone's offended.
If you have imagemagick extension activated, you can simply create an ImagickPixel object, call setColor with your hex value, and then call getHSL() (and get the last item of the obtained array I suppose)...
I tried a different approach to this, I used HSL (hue, saturation & lightness) lightness percentage to check if the color is dark or light. (like #chrisf said in his answer)
function:
function colorislight($hex) {
$hex = str_replace('#', '', $hex);
$r = (hexdec(substr($hex, 0, 2)) / 255);
$g = (hexdec(substr($hex, 2, 2)) / 255);
$b = (hexdec(substr($hex, 4, 2)) / 255);
$lightness = round((((max($r, $g, $b) + min($r, $g, $b)) / 2) * 100));
return ($lightness >= 50 ? true : false);
}
On the return line it checks if the lightness percentage is higher than 50% and returns true otherwise false is returned. You can easily change it to return true if the color has 30% lightness and so on. The $lightness variable can return from 0 to 100 0 being the darkest and 100 being the lightest.
how to use the function:
$color = '#111111';
if ( colorislight($color) ) {
echo 'this color is light';
}
else {
echo 'this color is dark';
}

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