Function returns "Array" instead of actual output - php

Question

I have this code:
function returnArray() {
$intData = array("1", "3");
return $intData[array_rand($intData)];
}
I'm trying to make a function similar to the one above.
Instead of adding integers with commas I'm trying to implode the commas with the integers.
Sort of like a dynamic version of the above using json_decode, file_get_contents, a foreach loop, array, array_rand & return
This is my code:
function Something() {
foreach (json_decode(file_get_contents('removed'), true) as $jsonArr) {
$arrData = array(implode(",", $jsonArr));
$roundData = $arrData[array_rand($arrData)];
return $roundData;
}
}
I was just wondering if I'm doing it right and if the array is correct or not.
Also it doesn't return anything from the array.
When I try to implode, it throws an error
implode invalid argument

Answer 1

It seems you're trying to print a random room_id from the JSON response.
The problem lies here:
$intData = array(implode(",", $arrRoomsReverse['room_id']));
You can't initialize an array like that.
Just push the room_id element to the array, like so:
$intData[] = $arrRoomsReverse['room_id'];
Now, you can simply get a random room_id outside the loop:
$intRoom = $intData[array_rand($intData)];
The function would look like:
function returnArray()
{
$str = file_get_contents('...');
$jsonArr = json_decode($str, true);
foreach ($jsonArr as $arrRoomsReverse)
{
$intData[] = $arrRoomsReverse['room_id'];
}
$intRoom = $intData[array_rand($intData)];
return $intRoom;
}
And to call the function:
echo returnArray();