Retrieving specific data from sql query - php

Question

Let's say I have the following query, wich gives me the amount of coupons downloaded and redeemed, grouped by date: [EDIT](I can't modify this query)[/EDIT]
$sql = "SELECT DATE(datetime) ,
SUM(CASE WHEN datetime!='' THEN 1 ELSE 0 END) As downloaded ,
SUM(CASE WHEN used = 1 AND DATE(datetime) != '' THEN 1 ELSE 0 END) AS redeemed
FROM Promotion_Redeem
WHERE datetime BETWEEN '2013-10-01' AND '2013-10-04'
GROUP BY DATE(datetime)";
How can I get the sum of downloaded and the sum of redeemed? this should be within $sql, somewhere... below is the result for this query:
row number 1
array (size=3)
0 => string '2013-10-01' (length=10)
1 => string '126' (length=3)
2 => string '11' (length=2)
row number 2
array (size=3)
0 => string '2013-10-02' (length=10)
1 => string '106' (length=3)
2 => string '5' (length=1)
row number 3
array (size=3)
0 => string '2013-10-03' (length=10)
1 => string '228' (length=3)
2 => string '12' (length=2)
row number 4
array (size=3)
0 => string '2013-10-04' (length=10)
1 => string '149' (length=3)
2 => string '9' (length=1)
[EDIT]bove you can see I get 4 rows, each one whith an array... I want, for instance, the sum of the third field from each of these arrays... In my example, this would equals to 37 (that means, 37 coupons redeemed)[/EDIT]
I got this data structure after using this:
while ($row = mysql_fetch_row($result)) {
echo "row number ".++$i;
var_dump($row);
}
Thanks in advance

Answer 1

Modify your php loop like so:
$downloaded=0;
$redeemed=0;
while ($row = mysql_fetch_row($result)) {
echo "row number ".++$i;
$downloaded+=$row[1];
$redeemed+=$row[2];
var_dump($row);
}
echo "Downloaded: $downloaded<br>";
echo "Redeemed: $redeemed<br>";