How to search an IP in an IP range using PHP? - php

Question

I have about 1000 IP address. I calculate IP ranges for them using the bellow code:
public function ipRange($mainIp, $mask)
{
$mainIpLong = ip2long($mainIp);
$maskLong = ip2long($mask);
$netid = long2ip($mainIpLong & $maskLong);
$broadcast = long2ip($mainIpLong | ~$maskLong);
//here I insert $netid and $broadcast to a MySQL table
//so I have abount 1000 records
}
It calculates IP range correctly, for example if I call like this:
ipRange('91.99.98.243', '255.255.255.240');
Result will be:
$netid -> 91.99.98.240
$broadcast -> 91.99.98.255
Now I need to have a search function. It should find the sub-range for the given IP address, so if I call search('91.99.98.249'), the search() function should show the record that netid is 91.99.98.240 and broadcast field is 91.99.98.255.
How can I do that?

Answer 1

function find($ip){
//get $netid and $bcast from db one by one
//loop through all records
if(ip2long($ip)>=ip2long($netid) && ip2long($ip)<=ip2long($bcast) ){
echo $netid;
echo $bcast;
}
}

Answer 2

I solved it.
Note: _getConnection() function connects to database.
ip_address fields includes: IP, netid and broadcast.
public function search($ip)
{
$ranges = $this->_getConnection()->fetchAll("SELECT netid, broadcast FROM ip_address");
foreach($ranges as $range) {
$min = ip2long($range['netid']);
$max = ip2long($range['broadcast']);
if(ip2long($ip) > $min && ip2long($ip) < $max) {
$result = $this->_getConnection()->fetchAll("SELECT * FROM ip_address WHERE netid = ? AND broadcast = ?", array($range['netid'], $range['broadcast']));
}
}
return $result;
}