PHP: How to create foreach loop (simple code) - php

Question

I am new to PHP and have created a little code for a file upload on a form.
The code works fine but I was wondering if I could achieve the same using a foreach loop so that it could also handle more files and I dont have to write a separate line for each of them.
Can someone here help me with this and tell me how to write it properly.
My Code (working):
session_start();
$varUID = $_POST['UID'];
$varSender = $_SESSION['email'];
$varFile1 = $_FILES["file1"]["name"];
$varExt1 = pathinfo($varFile1, PATHINFO_EXTENSION);
$varFile2 = $_FILES["file2"]["name"];
$varExt2 = pathinfo($varFile2, PATHINFO_EXTENSION);
$varFile3 = $_FILES["file3"]["name"];
$varExt3 = pathinfo($varFile3, PATHINFO_EXTENSION);
move_uploaded_file($_FILES["file1"]["tmp_name"], "uploads/" . $varUID . "_1" . "." . $varExt1);
move_uploaded_file($_FILES["file2"]["tmp_name"], "uploads/" . $varUID . "_2" . "." . $varExt2);
move_uploaded_file($_FILES["file3"]["tmp_name"], "uploads/" . $varUID . "_3" . "." . $varExt3);
echo $varUID;
Thanks for any help with this,
Tim

Answer 1

foreach ($_FILES as $key => $file) {
$name = $file["name"];
$ext = pathinfo($name, PATHINFO_EXTENSION);
preg_match('/(\d+)$/', $key, $match); // get 2 out of "file2"
$nr = $match[1];
move_uploaded_file($file["tmp_name"], "uploads/" . $varUID . "_" . $nr . "." . $ext);
}

Answer 2

$varUID = $_POST['UID'];
$varSender = $_SESSION['email'];
$i = 1;
foreach ($_FILES as $key => $file) {
$varFile = $file[$key]["name"];
$varExt = pathinfo($varFile, PATHINFO_EXTENSION);
move_uploaded_file($file[$key]["tmp_name"], "uploads/" . $varUID . "_" . $i . "." . $varExt);
$i++;
}
echo $varUID;