Delete array value containing given text - php

Question

I have this array:
$array = array(
[0] => "obm=SOME_TEXT",
[1] => "sbm=SOME_TEXT",
[2] => "obm=SOME_TEXT"
);
How can I remove array's element(s) containing value obm or sbm (which is always at the top of the string in the array) and update indexes?
Example 1:
print_r(arrRemove("smb", $array));
Output:
$array = array(
[0] => "obm=SOME_TEXT",
[1] => "obm=SOME_TEXT"
);
Example 2:
print_r(arrRemove("omb", $array));
Output:
$array = array(
[0] => "sbm=SOME_TEXT"
);

Answer 1

You can simply loop through the array using a foreach and then use strpos() to check if the array contains the given input string, and array_values() to update the indexes:
function arrRemove($str, $input) {
foreach ($input as $key => $value) {
// get the word before '='
list($word, $text) = explode('=', $value);
// check if the word contains your searchterm
if (strpos($word, $str) !== FALSE) {
unset($input[$key]);
}
}
return array_values($input);
}
Usage:
print_r(arrRemove('obm', $array));
print_r(arrRemove('sbm', $array));
Output:
Array
(
[0] => sbm=SOME_TEXT
)
Array
(
[0] => obm=SOME_TEXT
[1] => obm=SOME_TEXT
)
Demo!

Answer 2

Maybe something like this?
$newarray = array_values(array_filter($oldarray, function($value){
return strpos($value, 'obm') !== 0;
}
));

Answer 3

This is handled by PHP
php.net/manual/en/function.array-pop.php
array_pop() pops and returns the last value of the array , shortening the array by one element.