Fill array from query with mysqli_fetch_assoc() - php

Question

I had this and everything worked fine (I had a generic table builder, but now I am having to stray from that):
while ($x = mysqli_fetch_assoc($result))
{
$fields[] = $x['Field'];
}
Now I have something similar to this:
$result = mysqli_query($con, 'SELECT r.id AS ID, CONCAT(g.fname, g.lname) AS Name, r.apple AS Apple,
r.dog AS Dog, DATEDIFF(r.Dog, r.Apple) AS Days,
r.total_price AS "Total Price", u.name AS Name, r.in AS "In",
r.out AS "Out", r.time_in AS "Time In", r.time_out AS "Time Out",
CONCAT(c.fname,c.lname) AS Charlie, r.here AS "Apple",
r.leave AS "Dog"
FROM really r, georgia g, unit u, charlie c
WHERE g.id = r.georgia AND r.unit = u.id AND r.charlie = c.id
HAVING r.in = TRUE AND r.out = FALSE');
//fill fields array with fields from table in database
while ($x = mysqli_fetch_assoc($result))
{
$fields[] = $x['Field'];
}
I am now getting an error for the line $fields[] = $x['Field']; because of the word Field. Why? Because I now have a full query? How can I fix this without referencing each field name?

Answer 1

Because there is not a field named Field in you query result:
'SELECT r.id AS ID, CONCAT(g.fname, g.lname) AS Name, r.apple AS Apple,
r.dog AS Dog, DATEDIFF(r.Dog, r.Apple) AS Days,
r.total_price AS "Total Price", u.name AS Name, r.in AS "In",
r.out AS "Out", r.time_in AS "Time In", r.time_out AS "Time Out",
CONCAT(c.fname,c.lname) AS Charlie, r.here AS "Apple",
r.leave AS "Dog"
FROM really r, georgia g, unit u, charlie c
WHERE g.id = r.georgia AND r.unit = u.id AND r.charlie = c.id
HAVING r.in = TRUE AND r.out = FALSE'
There are some fields in your query result: ID, Name, Apple, etc.. You can try to fetch the these field as below, or change your query command.
while ($x = mysqli_fetch_assoc($result))
{
$fields[] = $x['ID'];
}