Count days within a month from date range - php

Question

I have three date ranges in mysql table as follow
from 2013-09-29 to 2013-10-02
from 2013-10-14 to 2013-10-16
from 2013-10-28 to 2013-11-05
I want to count only days that occur in Month of October, for example from first range (2013-09-29 to 2013-10-02) I should get difference of two days (1st and 2nd October) , and it should ignore days from September month, Finally i want to count total days in a given month from above date ranges.
Can it be done from direct mysql query. or any short PHP logic.
here is my table structure
id,employee_id,leave_start,leave_to
I am looking for a method some thing like
function countLeaves($employee_id,$month)
{
// code
return $numberOfLeaves
}

Answer 1

You need to calculate the first day of the month 2013-10-01 and the last day of the month 2013-10-31 and then you could use a query like this:
SELECT
DATEDIFF(
LEAST(d_end, '2013-10-31'),
GREATEST(d_start, '2013-10-01'))+1 days
FROM
ranges
WHERE
d_start<='2013-10-31' AND d_end>='2013-10-01'
Please see fiddle here.

Answer 2

function getAllDates($fromDate, $toDate,$rejectmonth)
{
if(!$fromDate || !$toDate ) {return false;}
$dateMonthYearArr = array();
$fromDateTS = strtotime($fromDate);
$toDateTS = strtotime($toDate);
for ($currentDateTS = $fromDateTS; $currentDateTS <= $toDateTS; $currentDateTS += (60 * 60 * 24))
{
if($rejectmonth == date("m",$currentDateTS))
continue;
$currentDateStr = date("Y-m-d",$currentDateTS);
$dateMonthYearArr[] = $currentDateStr;
}
return $dateMonthYearArr;
}
use this function will return the array dates which are in the date ranges.
getAllDates('2013-09-10','2013-19-10',10);

Answer 3

$month = strtotime(date('Y-m-01', time()));
$daysCount = (int)(time() - $month) / (24 * 3600);
and if you need to check from any date to any date:
/**
* #var $dateFrom string Date to count from,
* you can use date('Y-m-01') as start of current month
* #var $dateTo string End of period date, example: '2013-09-05'
**/
function getDaysCount($dateFrom, $dateTo)
{
return (int)(strtotime($dateTo) - strtotime($dateFrom)) / (24 * 3600);
}