I posted earlier about another resizing script not working and I got a little farther with this script which does things a little differently.
I got a little farther, only now there is a new problem. The first three lines of the code successfully place three identical files in the target directory with the file and it's two thumbnail files named accordingly. I then want to load the thumbnails, which are still full-size, and resize them but the script stops at imagecreatefromjpeg() and I can't seem to figure out why because $src has a value.
I thought that I could possibly remove that line and replace $source with $src in my imagecopyresized() function, and that gets me even closer. But it then returns a thumbnail of the target size, but the thumbnail is black.
move_uploaded_file($tmpFilePath, $newFilePath);
copy($newFilePath, $thumb500);
copy($newFilePath, $thumb200);
function thumbImage($src, $dest, $newheight) {
list($width, $height) = getimagesize($src);
$newwidth = $width * ($newheight / $height);
// Load
$thumb = imagecreatetruecolor($newwidth, $newheight);
header('Content-type: image/jpeg');
$source = imagecreatefromjpeg($src);
// Resize
imagecopyresized($thumb, $source, 0, 0, 0, 0, $newwidth, $newheight, $width, $height);
// Output
imagejpeg($thumb, $dest);
}
thumbImage($thumb500, $thumb500, 500);
thumbImage($thumb200, $thumb200, 200);
I feel as if this must be a common issue. Any suggestions anyone?
For me the supplied code block works if I use a JPEG image as source.
The problem may be that you use a PNG image that uses transparency. As JPEG can not handle transparencies, the transparent background colour will be filled. Maybe that is the problem. If not, please provide a sample image that has the problematic behaviour.
5
imagecopyresized takes an image resource as its second parameter, not a file name. You'll need to load the file first. If you know the file type, you can use imagecreatefromFILETYPE to load it. For example, if it's a JPEG, use imagecreatefromjpeg and pass that the file name - this will return an image resource.
If you don't know the file type, all is not lost. You can read the file in as a string and use imagecreatefromstring (which detects file types automatically) to load it as follows:
{$oldImage = imagecreatefromstring(file_get_contents($_FILES['image']['tmp_name']));
}
enter code here
Related
I am trying to create an employee poster for a website that I develop. My goal is to take an image from a directory on the server of any file type (.png, .gif, .jpeg, etc.) and copy it onto another generate imaged that will then be outputted to the browser.
The problem is that I use:
$final_image = imagecreatefrompng("large_background.png");
for making the final image and for some reason if I add profile images with the type jpeg's, gif's, etc, (any type that isn't a jpeg) it doesn't work. The images never show up in the output. However, if I use png's it does work.
To solve this problem I tried converting the image to a png and then creating a png from it as shown in the code below. Unfortunately it doesn't work. Profile images still do not show up on the background.
// get image from database
$image_from_database = could be a .png, .jpeg, .gif, etc.
// get the image from the profile images directory
$path = "profile_images/".$image_from_database;
// create a png out of the image
$image = imagecreatefrompng(imagepng($path));
// add the $image to my larger $final_image (which is a png)
imagecopy($final_image, $image, $x, $y, 0,0, $height, $width);
imagepng($final_image, $ouput_url);
...
Can anybody tell me why this won't work? My profile images do not show up in the output of the final image.
My questions,
Is this line imagecreatefrompng(imagepng(...)); even possible? Essentially I want to convert an image of any type into a png and then create a png from it.
I'm just running a few local tests... The following works:
$src = imagecreatefromgif('test.gif');
$dest = imagecreatefrompng('test.png');
imagecopy($dest, $src, 0, 0, 0, 0, 100, 100);
header('Content-Type: image/png');
imagepng($dest);
imagedestroy($src);
imagedestroy($dest);
So does this:
$src = imagecreatefromstring(file_get_contents('test.gif'));
If you're still having trouble after trying the latter example, please update your question. The actual images you're using would be helpful, in addition to a functional code example.
After you read an image with a imagecreatefrom* function, it doesn't matter what format the original was.
imagecreatefrom* functions return an image resource. When the image is loaded you are using internal representation of the images and not PNG, JPEG or GIF images.
If the images are successfully loaded imagecopy should have no problems with them.
This code uses images in different formats and works without a problem:
$img = imagecreatefrompng('bg.png');
$png_img = imagecreatefrompng('img.png');
$jpeg_img = imagecreatefromjpeg('img.jpeg');
$gif_img = imagecreatefromgif('img.gif');
/* or use this, so you don't need to figure out which imagecreatefrom* function to use
$img = imagecreatefromstring(file_get_contents('bg.png'));
$png_img = imagecreatefromstring(file_get_contents('img.png'));
$jpeg_img = imagecreatefromstring(file_get_contents('img.jpeg'));
$gif_img = imagecreatefromstring(file_get_contents('img.gif'));
*/
imagecopyresampled($img, $png_img, 10, 10, 0,0, 100, 100, 200, 200);
imagecopyresampled($img, $jpeg_img, 120, 10, 0,0, 100, 100, 200, 200);
imagecopyresampled($img, $gif_img, 230, 10, 0,0, 100, 100, 200, 200);
header('Content-Type: image/png');
imagepng($img);
Your example
$image = imagecreatefrompng(imagepng($path));
is wrong.
imagepng is used to output an image resource as a PNG image. If you provide a path as a second argument a PNG image file is created, otherwise it's printed to the output like echo does.
What imagepng actually returns is a boolean, indicating, if the output was successful.
You are then passing that boolean to imagecreatefrompng which expects a filepath. This is obviously wrong.
I suspect you have a problem with loading images.
imagecreatefrom* functions return FALSE on failure and you should check, if you have any problems with that.
Maybe your image paths are relative to doc root and your working directory is different.
Or you have permission problem.
Or your images are just missing.
It's impossible to tell from your question.
I've been trying to get transparency to work with my application (which dynamically resizes images before storing them) and I think I've finally narrowed down the problem after much misdirection about imagealphablending and imagesavealpha. The source image is never loaded with proper transparency!
// With this line, the output image has no transparency (where it should be
// transparent, colors bleed out randomly or it's completely black, depending
// on the image)
$img = imagecreatefromstring($fileData);
// With this line, it works as expected.
$img = imagecreatefrompng($fileName);
// Blah blah blah, lots of image resize code into $img2 goes here; I finally
// tried just outputting $img instead.
header('Content-Type: image/png');
imagealphablending($img, FALSE);
imagesavealpha($img, TRUE);
imagepng($img);
imagedestroy($img);
It would be some serious architectural difficulty to load the image from a file; this code is being used with a JSON API that gets queried from an iPhone app, and it's easier in this case (and more consistent) to upload images as base64-encoded strings in the POST data. Do I absolutely need to somehow store the image as a file (just so that PHP can load it into memory again)? Is there maybe a way to create a Stream from $fileData that can be passed to imagecreatefrompng?
you can use this code :
$new = imagecreatetruecolor($width, $height);
// preserve transparency
imagecolortransparent($new, imagecolorallocatealpha($new, 0, 0, 0, 127));
imagealphablending($new, false);
imagesavealpha($new, true);
imagecopyresampled($new, $img, 0, 0, $x, 0, $width, $height, $w, $h);
imagepng($new);
imagedestroy($new);
It will make a transparent image for you. Good Luck !
Blech, this turned out to ultimately be due to a totally separate GD call which was validating the image uploads. I forgot to add imagealphablending and imagesavealpha to THAT code, and it was creating a new image that then got passed to the resizing code. Which should probably be changed anyway. Thanks very much to goldenparrot for the excellent method of converting a string into a filename.
Do I absolutely need to somehow store the image as a file (just so that PHP can load it into memory again)?
No.
Documentation says:
You can use data:// protocol from php v5.2.0
Example:
// prints "I love PHP"
echo file_get_contents('data://text/plain;base64,SSBsb3ZlIFBIUAo=');
I need to create a page that will automatically create a thumbnail from all images if selected folder and show them on the same page. But the thing is, I don't want to save them. I want to display them on the same page without saving. And I need to do that in PHP. Is it possible? Please help!
Note: If that is not possible,I can put them in some folder.
You have to make a second PHP-file then. You have to make an image tag in the first file <img src='image.php' /> and in this image.php you have to print out the image like:
header("Content-type: image/png");
$im = imagecreatefrompng("image.png");
list($width, $height) = getimagesize($im);
$newimage = imagecreatetruecolor($new_width, $new_height);
imagecopyresampled($newimage, $im, 0, 0, 0, 0, "100", "100", $width, $height);
imagepng($newimage);
imagedestroy($newimage);
imagedestroy($im);
You might also consider using data URIs. Use the code in DRP96's answer to create the thumbnail, but instead of doing it in a separate PHP and requiring many image requests, embed the images directly on the page.
Most modern browsers support data URIs now, but as usual, watch out for IE.
replace this line
list($width, $height) = getimagesize($im);
with this
list($width, $height) = getimagesize("image.png");
how to take image from one folder and rename and re-size the images and move to another folder?
I need to get image from one folder and rename and re-size the same image and move into another folder using php
You will most likely be using gd for resizing the images.
Here is a pretty crappy, but hopefully useful code sample. In this case, $originalName is the name given in the $_FILES array's tmp_name position. I am resizing to a width of 1200 in this case, with the height adapting according to such width. You might (and most likely will) not desire this behavior. This is just some ugly code I used in some courses I taught about 3 years ago, I don't have the newer samples in this computer so you will have to get used to the idea :)
$newDir is where the file will be located. by calling imagejpeg or imagepng and passing the filename as second argument, it means to the function that you wish to save the image in that location.
if ($type == 'image/jpeg') {
$original = imagecreatefromjpeg($originalName);
}
else {
$original = imagecreatefrompng($originalName);
}
$width = imagesx($original);
$height = imagesy($original);
//prepare for creation of image with width of 1000
$new_height = floor($height * (1200 / $width));
// create the 1200 width image
$tmp_img = imagecreatetruecolor(1200, $new_height);
// copy and resize old image into new image
imagecopyresized($tmp_img, $original, 0, 0, 0, 0,
1200, $new_height, $width, $height);
//create a random and unique name to identify (here it isn't that random ;)
$newDir = '/this/is/some/directory/and/filename.';
if ($type == 'image/jpeg') {
imagejpeg($tmp_img, $newDir."jpg");
}
else {
imagepng($tmp_img, $newDir."png");
}
Many file system functions are already built-in with PHP (e.g. rename), and you'll find most of what you need to resize images by using the GD library here.
There are libraries available in PHP for image resize.
Here are some useful links you may like.
http://www.fliquidstudios.com/2009/05/07/resizing-images-in-php-with-gd-and-imagick/
http://php.net/manual/en/book.image.php
PHP/GD - Cropping and Resizing Images
http://net.tutsplus.com/tutorials/php/image-resizing-made-easy-with-php/
Use imagick http://php.net/manual/en/imagick.resizeimage.php
If I were you I would write a PE using a diffent language (one that you might be best used to) to adjust anything of the given image then just feel free to phpexec it to do all the steps you mentioned, you can sit relax and wait for the end result. HHAHAHHA :-)
Use imagick library to resize; it's good.
I have an image which i am going to be using as a background image and will be pulling some other images from the database that i want to show within this image. So if i am pulling only 1 image, i want the bottom part of the background image to close after the first image, if there are multiple images then i want it close after those images are shown. The problem with not using separate images is that the borders of the images have a design format and i cannot show them separately.
Take a look at this image . The design format of the right and left borders are more complicated than that to just crop them and use them. Any suggestions if there is any dynamic image resizing thing?
Yes there is. Look at the imageXXXX functions; the ones you are particularly interested in are imagecreate, imagecreatetruecolor, imagecreatefrompng, imagecopyresampled, imagecopyresized, and imagepng (assuming you're dealing with PNG images - there's similar load / save functions for jpeg, gif, and a few other formats).
You should try using the GD extension for PHP, especially have a look at imagecopyresized(). This allows you to do some basic image conversion and manipulation very easily.
A basic example that takes two GET parameters, resizes our myImage.jpg image and outputs it as a PNG image:
<?php
// width and height
$w = $_GET['w'];
$h = $_GET['h'];
// load image
$image = imagecreatefromjpeg('myImage.jpg');
// create a new image resource for storing the resized image
$resized = imagecreatetruecolor($w, $h);
// copy the image
imagecopyresized($resized, $image, 0, 0, 0, 0, $w, $h, imagesx($image), imagesy($image));
// output the image as PNG
header('Content-type: image/png');
imagepng($resized);
Have you tried PHPThumb? I used this class often and its pretty clean and lightweight. I used it here.