PHP String Extraction [duplicate] - php

Question

This question already has an answer here:
PHP preg_match to find multiple occurrences
(1 answer)
Closed 8 years ago.
I'm weak with regex, need help. My problem is I have to extract all the string that matches the given pattern I have into an array. See the problem below:
The string
<?php
$alert_types = array(
'warning' => array('', __l("Warning!") ),
'error' => array('alert-error', __l("Error!") ),
'success' => array('alert-success', __l("Success!") ),
'info' => array('alert-info', __l("For your information.") ),
);?>
The Preg_Match Code
preg_match("/.*[_][_][l][\(]['\"](.*)['\"][\)].*/", $content, $matches);
I'm only getting the first one match which is Warning!. I'm Expecting matches will have the following values:
Warning!, Error!, Success!, For your information.
Actually I'm using file_get_contents($file) to get the string.
Can anyone help me to solve this. Thankyou in advance.

Answer 1

preg_match() only finds the first match in the string. Use preg_match_all() to get all matches.
preg_match_all("/.*__l\(['\"](.*?)['\"]\).*/", $content, $matches);
$matches[1] will contain an array of the strings you're looking for.
BTW, you don't need all those single-character brackets. Just put the character into the regexp.
var_dump($matches);
array(2) {
[0]=>
array(4) {
[0]=>
string(45) " 'warning' => array('', __l("Warning!") ),"
[1]=>
string(52) " 'error' => array('alert-error', __l("Error!") ),"
[2]=>
string(58) " 'success' => array('alert-success', __l("Success!") ),"
[3]=>
string(65) " 'info' => array('alert-info', __l("For your information.") ),"
}
[1]=>
array(4) {
[0]=>
string(8) "Warning!"
[1]=>
string(6) "Error!"
[2]=>
string(8) "Success!"
[3]=>
string(21) "For your information."
}
}