What I am trying to do is to make something similar to what I see all the time on almost any website. The button that says Share to facebook. The goal for me is to let my guests share the item they are viewing in my store (Ran on prestashop) on their blog I run (Running on Oxwall).
The goal is for the button to not only link to a blog post submission webpage but to already have the subject line filled out with the item they are sharing's name and the blog post to display the information about the item. I would like to try and do all this using PHP. I am not sure how to go about doing it but I am sure that I could pass the value. Please note that I can mod BOTH the blog site and the shop as I run both and want to connect them.
As an extra bonus I am also running a forum using phpbb3 if I could do the same thing but onto that as well I would greatly thank you. I am trying to interlink everything into one big network. I know its not an easy task but I am sure there is an easy way to pass data onto the other site so that this can be done.
Facebook a 2 tools to get items informations in the page, it parses the page looking for the most common tags and it uses OpenGraph.
You can also provide product informations in the head of your page (between head tags), then blog side, you retrieve only the contents and parse it as XML.
I advise you to cache this data to avoid useless connections between websites and awful overloads while parsing.
You can use your own specifications, Open Graph or another standard, but i advise to use a standard.
Related
first post here.
I am making a site for someone who wants to embed their own youtube links. I am relatively new to web development and this is my first commission so I was wondering how I could hand over the site to the client and allow them to upload their links without me having to edit the mark up for him.
I understand how to use an '<iframe' youtube link in HTML to embed videos and am considering creating a database using PHPmyadmin that uses a form that the client can fill in with the iframe link whenever he needs to embed a new video.
I understand if that sounds like a convoluted way of doing this but if anyone knows a more intuitive way to solve this issue please let me know :)
I think it can be done using a database, may be MySQL, to keep it simple and a simple backend programming language, PHP would do.
You create an admin page just to collect the URLs from the admin. A nice little login page which stores admin username and password in a table. And you can use this module to assign roles to admin, add an admin or delete one.
Inside the module created above, create a page with a form to fetch and store URLs in the database. If you are going to categorize the videos, use suitable columns. Say you are going to categorize based on the genre and length, the table in your database should contain genre and length so that you can use them as filters later on.
Use cookies to create session for the admin. This is to avoid redirecting him to the login page after every single reload.
For all other user who is not admin, do not redirect to the admin page. Redirect them to a common page where they can search and enjoy the videos that the admin has added.
Again, like mentioned in many comments above, wordpress does it all. You have an option to use it too, it's free.
I've been tasked with providing the backend for a news feed that will be used by our company apps. The feed will pull articles from our current website, which is built with ModX (evolution). So far, I've designed the feed to send JSON through a specified url containing the needed information. It's currently in the following format (using Ditto placeholders):
{
"title":"[+longtitle+]",
"description":"[+description+]",
"link":"[(site_url)][~[+id+]~]"
},
Here's my issue - the link I'm providing through the JSON (in the link tag) opens the full, desktop version of the page. Our current site is not responsive, and was not originally designed to handle mobile devices. We would like to open a small, clean page showing ONLY the ['content'] of that particular article. I'm looking for a way to link to a page showing only this content - no header, no footer, nothing.
I know that I could create a new page to handle all of this, but it needs to be dynamic. New articles are created regularly, and I'd like to avoid having to add another page to handle this for every article, while also making it simple for the writing team to integrate this feature.
One of my ideas so far is:
Pass a GET parameter to the URL "link" in the JSON - something like - www.mysite.com/article1?contentOnly=true. Then, in my article, detect this parameter in PHP and handle accordingly. I would need this snippet on each article written, so it may cause issues down the road if our staff writers forget to add it.
I haven't worked with ModX long, so I'm assuming there's a better way to handle this. Any ideas would be greatly appreciated. Please let me know if I need to provide more information.
I am not 100 % sure how you have done this, but here's my tip.
Don't use the resource itself to output the JSON. Doing this based on a GET-paramter will required the entire site to be uncached. Instead, use a single resource for the feed and supply the id/permalink there.
For example: mysite.com/feed?id=1, mysite.com/feed?latest or something like that.
Done this way, you could have an empty template with just the snippet that is parsing to JSON in it. This has to be uncached of course, but the rest of the site could be cached as normal.
This is really a point me in the right direction question. What path should I take if I want to display the number of page views each gallery page receives?
Retrieve Google Analytics Data via PHP, or
Capture the page views directly on my pages with my own PHP and mySQL setup?
Seems, like number 1 would be the better choice. I just don't know how difficult this option will be. Any insights on this?
Option 2 is definitely simpler.
If you do figure out how to get the page results out of Google Analytics, they will not be up-to-date. It takes Google at least several hours before the page views show up.
That also depends if You want to have info on more questions (statistics). I often use custom setup to track such things cause I can later use some data to do statistics about users actions.
For example, You want to give users (owners of photos) info about witch users (male or female, 30+ or below 30, and so on) are viewing. How many guests, how many registered users. There are tons of data You can retrive by building custom system.
It all depends on what You want to have at the end.
I suspect that if You want to have only raw data about number of users You coud somehow parse data from Google Analytics as well.
And as posted below. Google have to take time to update, custom setup not.
Now I have my website built on PHP & Mysql. Consider this like a forum. Now when a user posts a reply in my website 1 (ex. www.website1.com), I want to be able to show the starting thread and it's related replies in a sister website of mine. I want to do this in a way that it does not show the rest of the page & other page contents (like logo etc.). I don't think iframe would be a solution because an iframe would embed the whole page and the users visiting my sister website (totally different domain i.e. www.website2.com) would be able to see all the page contents, like logo etc. I want to avoid that. I want to make them see only limited information from website 1 and only the info. that I intend.
I hope that makes sense. In a way, you could say that I am trying to replicate my 1 website, and show only a limited part of it. Users browsing 2nd website can post a reply in the 2nd website and it should automatically be posted & visible to the visitors of the website 1. Users of website 1 should not know that a user of website 2 has posted it. They would feel that some user from website 1 has posted it. Do I have to use 2 separate mysql DB or just 1? I think it would be problematic if I am trying to use different DB. I also feel I might have to face DB connectivity issues as I can connect to only 1 DB at a time.
It's basically like users of website1.com should feel that they are replying to users of website1.com & users of website2.com should feel that they are replying to users of website2.com. (I need it this way to bridge the gap between them). At the same time I want to make the front end of the websites different so that they don't feel that they are replying to some other users outside the domain. These websites would be under my control and I will have access to the source code at any time. If I need to change the source code, these changes are welcome.
Is this really possible?
Thank you in advance.
I'd recommend generating RSS (might be runtime) and using it on the sister website. If RSS is not suitable for your needs, you can create your own XML-based format (or any other :) )
Make two forums which use one database. Both websites would put new messages in the same database.
Make an API for website1, so that website2 can retrieve and post messages on the forum. Website2 would do a HTTP request to website1, which returns XML or JSON, so that website2 can request a list of posts that it can display.
Have both sites connect to the same database and display the content they pull in whatever way is appropriate for the particular site. Each site can only pull the fields relevant to that site.
If the idea is to have two websites with the same data but different presentations, then you would want to simply share a single database between them - assuming they are hosted in the same place and can both get at the database.
You can then just create different PHP pages that both access the same database in the same way but display the data differently.
The best way to do this would be to have a shared library of functions or classes that both sites use to manipulate the data. You would then build a different "presentation layer" on top of that for each site.
I am creating a classifieds website.
Im storing all ads in mysql database, in different tables.
Is it possible to find these ads somehow, from googles search engine?
Is it possible to create meta information about each ad so that google finds them?
How does major companies do this?
I have thought about auto-generating a html-page for each ad inserted, but 500thousand auto-generated html pages doesn't really sound that good of a solution!
Any thoughts and idéas?
UPDATE:
Here is my basic website so far:
(ALL PHP BASED)
I have a search engine which searches database for records.
After finding and displaying search results, you can click on a result ('ad') and then PHP fetches info from the database and displays it, simple!
In the 'put ad' section of my site, you can put your own ad into a mysql database.
I need to know how I should make google find ads in my website also, as I dont think google-crawler can search my database just because users can.
Please explain your answers more thoroughly so that I understand fully how this works!
Thank you
Google doesn't find database records. Google finds web pages. If you want your classifieds to be found then they'll need to be on a Web page of some kind. You can help this process by giving Google a site map/index of all your classifieds.
I suggest you take a look at Google Basics and Creating and submitting SitemapsPrint
. Basically the idea is to spoon feed Google every URL you want Google to find. So if your reference your classifieds this way:
http://www.mysite.com/classified?id=1234
then you create a list of every URL required to find every classified and yes this might be hundreds of thousands or even millions.
The above assumes a single classified per page. You can of course put 5, 10, 50 or 100 on a single page and then create a smaller set of URLs for Google to crawl.
Whatever you do however remember this: your sitemap should reflect how your site is used. Every URL Google finds (or you give it) will appear in the index. So don't give Google a URL that a user couldn't reach by using the site normally or that you don't want a user to use.
So while 50 classifieds per page might mean less requests from Google, if that's not how you want users to use your site (or a view you want to provide) then you'll have to do it some other way.
Just remember: Google indexes Web pages not data.
How would you normally access these classifieds? You're not just keeping them locked up in the database, are you?
Google sees your website like any other visitor would see your website. If you have a normal database-driven site, there's some unique URL for each classified where it it displayed. If there's a link to it somewhere, Google will find it.
If you want Google to index your site, you need to put all your pages on the web and link between them.
You do not have to auto-generate a static HTML page for everything, all pages can be dynamically created (JSP, ASP, PHP, what have you), but they need to be accessible for a web crawler.
Google can find you no matter where you try to hide. Even if you can somehow fit yourself into a mysql table. Because they're Google. :-D
Seriously, though, they use a bot to periodically spider your site so you mostly just need to make the data in your database available as web pages on your site, and make your site bot-friendly (use an appropriate robots.txt file, provide a search engine-friendly site map, etc.) You need to make sure they can find your site, so make sure it's linked to by other sites -- preferably sites with lots of traffic.
If your site only displays specific results in response to search terms you'll have a harder time. You may want to make full lists of the records available for people without search terms (paged appropriately if you have lots of data).
First Create a PHP file that pulls the index plus human readable reference for all records.
That is your main page broken out into categories (like in the case of Craigslist.com - by Country and State).
Then each category link feeds back to the php script the selected value regardless of level(s) finally reaching the ad itself.
So, If a category is selected which contains more categories (like states contain cities) Then display the next list of categories. Else display the list of ads for that city.
This will give Google.com a way to index a site (aka mysql db) dynamically with out creating static content for the millions (billions or trillions) of records involved.
This is Just an idea of how to get Google.com to index a database.