Echo PHP array as HTML? - php

Question

Okay, so I've literally spent all day trying to achieve this and have gotten nowhere.
I am creating a flipbook (using turn.js).
I have names and cause of death stored in a MySQL database.
I want to print 5 names and their cause of death on each page.
To add a page in turn.js, all i have to do is add a in
So i load the name and cause of death values into arrays, and then echo a whole div however with the array variable.
I'm really having trouble getting this into code.
At the moment I have managed to get this onto seperate pages, but how would i get it to print only 5 on a page, and then create a new page (untill there are no more names)
Here is what i have so far.
<?php
$dbc = mysql_connect('localhost', 'xxxx', 'xxxxxxx');
if (!$dbc) {
die('Not Connected: ' . mysql_error());
}
$db_selected = mysql_select_db("xxxxxx", $dbc);
if (!$db_selected)
{
die ("Can't Connect : " . mysql_error);
}
$query = "SELECT * FROM TABLE";
$result = mysql_query($query);
$victim = array();
$cod = array();
$count = 0;
while ($row = mysql_fetch_assoc($result)) {
$victim['$count'] = $row['Victim'];
$cod['$count'] = $row['COD'];
$count++;
}
?>
<div id="deathnote">
<div style="background-image:url(images/coverpage.jpg);"></div>
<div style="background-image:url(images/page1.jpg);"></div>
<div style="background-image:url(images/page2.jpg);"></div>
<div style="background-image:url(images/page3.jpg);"></div>
<div style="background-image:url(images/page4.jpg);"></div>
<div style="background-image:url(images/page5.jpg);"></div>
<?php
for ($x=0; $x=$count; $x++) {
echo "<div style='background-image:url(images/page5.jpg);'></div><div class='content'><div class='name'>" . $victim['$x'] . "</div><div class='cod'>" . $cod['$x'] . "</div></div></div>";
}
?>
Any help will be GREATLY appreciated.
Thanks in advance, guys :)

Answer 1

Take a look at the $_GET variable http://php.net/manual/de/reserved.variables.get.php there you can set variables in the URL like http://lol.de/?form=1&to=5
$from = $_GET['from'];
$to = $_GET['to'];
if(!is_numeric($from) || !is_numeric($to)) die('SQL Injection');
$count = $to - $from;
$query = "SELECT * FROM TABLE LIMIT ".$from-",".$count;
Then you create a dynamic link, where you add 5 to $from and $to.
Not tested, just a Idea.

Answer 2

Check the last two line on your code, e.g.:
for ($x=0; $x=$count; $x++) {
echo "<div style='background-image:url(images/page5.jpg);'></div><div class='content'><div class='name'>" . $victim['$x'] . "</div><div class='cod'>" . $cod['$x'] . "</div></div></div>";
Change them to:
$onPage = 5;
$currentPage = 1;
for ($x=0; $x=$count; $x++) {
if (($x % $onPage) == 0)
{
echo "<div style='background-image:url(images/page" . $currentPage . "jpg);'></div>";
$currentPage++;
}
echo "<div class='content'>"
. "<div class='name'>" . $victim['$x'] . "</div>"
. "<div class='cod'>" . $cod['$x'] . "</div>"
. "</div>";
}
You can play around with the "modulus" operator - %, to achieve the result you need.

Answer 3

Try below code.
$recordPerPage = 5;
<?php
for ($x=1; $x<=$count; $x++) {
if($x <= $recordPerPage ) {
echo "<div style='background-image:url(images/page".$x.".jpg);'></div><div class='content'><div class='name'>" . $victim['$x'] . "</div><div class='cod'>" . $cod['$x'] . "</div></div></div>";
}
$x = $recordPerPage;
$recordPerPage += $recordPerPage;
}
?>
Hope this will help to you!
Cheers!

Answer 4

This may help you.
<?php
$recordPerPageCount = 5;
$pageCount = 1;
for ($x=0; $x<$count; $x++) {
if($x % $recordPerPageCount == 0) {
//This block will execute each time after diplaying five records in a page
$pageCount++;
}
echo "<div style='background-image:url(images/page".$pageCount.".jpg);'></div><div class='content'><div class='name'>" . $victim['$x'] . "</div><div class='cod'>" . $cod['$x'] . "</div></div></div>";
}
?>