I am getting the issue
Warning: Use of undefined constant otherInput - assumed 'otherInput'
(this will throw an Error in a future version of PHP) Warning: A
non-numeric value encountered
I know there is some issue with the quote.
What I am doing is, I have to click on the anchor tag called Click me one and sending the data-id in the script. I am getting the id value in the script but I am getting the error on $(".showme'+otherInput+'").show();
I am using WordPress and I have to use the below code in the function.php so I have to use my script inside the PHP tag.
This is the screenshot of the code
Here is the code
<!DOCTYPE html>
<html>
<head>
<title></title>
<style type="text/css">
.showme{display: none;}
</style>
</head>
<body>
<div class="clickme" data-id="1">Click me one</div>
<div class="showme showme1">this is example</div>
<?php
echo '<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.5.1/jquery.min.js"></script>
<script type="text/javascript">
$(".clickme").click(function(){
var otherInput=$(this).data("id");
$(".showme'+otherInput+'").show();
});.
</script>';
?>
</body>
</html>
It looks like everything in your php block is all JQuery/Javascript.
Q: What do you even need the PHP block and the "echo" for?
Current:
<?php
echo '<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.5.1/jquery.min.js"></script>
<script type="text/javascript">
$(".clickme").click(function(){
var otherInput=$(this).data("id");
$(".showme'+otherInput+'").show();
});.
</script>';
?>
Suggested change:
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.5.1/jquery.min.js"></script>
<script type="text/javascript">
$(".clickme").click(function(){
var otherInput=$(this).data("id");
$(".showme"+otherInput).show();
});.
</script>'
Just follow the regular js standard, and if you willing to implement your script inside the php code:
Replace your code with these changes:
<!DOCTYPE html>
<html>
<head>
<title></title>
<style type="text/css">
.showme{display: none;}
</style>
</head>
<body>
<div class="clickme" data-id="1">Click me one</div>
<div class="showme showme1">this is example</div>
<?php
echo '<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.5.1/jquery.min.js"></script>
<script type="text/javascript">
$(".clickme").click(function(){
var otherInput=$(this).data("id");
$(".showme"+otherInput).show();
//here otherInput js variable is just used as regular js variable inside the script, so no need to extra commas to call that js variable, just use it like you do in js files, and will work fine.
});
</script>';
?>
</body>
</html>
Here my index.php page structure:
<?php
session_start();
include("lang/".$_SESSION['lang'].".php");
?>
<!DOCTYPE html>
<html lang="en">
<head>
...
</head>
<body>
<a href="#" data-module="home">
<div id="content"></div>
</body>
<script src="jquery.js"></script>
<script src="script.js"></script>
</html>
I have a piece of js code to load the right clicked module.
$('a[data-module]').click(function(event) {
event.preventDefault();
var module = $(this).attr('data-module');
$('#content').load('modules/' + module + '.php');
});
My problem is:
On each module page, I use $_SESSION variables. But with .load() jQuery function, it don't works anymore.
Do you have a reason for that ?
Thanks.
I thought this would be simple enough, but I can't get it to work.
I have two files. main.html and data.php
The two files are in the same folder on a server.
I want to get a string from the PHP file and use it in jQuery. In the example below, I want the browser to create a pop-up, with the text "xxxx". I get no pop-up.
data.php
<?php
$var = "xxxx";
echo json_encode($var);
?>
main.html
<!DOCTYPE html>
<html>
<head>
<script type="text/javascript" src="scripts/jquery-1.11.1.js"></script>
<script>
$(document).ready(function() {
var testString = <?php $var = json_decode(file_get_contents('data.php'), true); echo $var; ?>;
alert(testString);
});
</script>
</head>
<body>
<h1>Test</h1>
</body>
</html>
Any takers?
<!DOCTYPE html>
<html>
<head>
<script>
$(document).ready(function() {
$.ajax({
url:"data.php",
success:function(result){
alert(result);
}
});
});
</script>
</head>
<body>
<h1>Test</h1>
</body>
</html>
The first problem with this is that on many servers .html is not parsed for PHP
The second problem is that the file_get_contents will actually display the full contents of your .php file (including the <?php) which is likely not what you're looking for.
Instead I would use an AJAX request such as http://api.jquery.com/jquery.get/
For this you will need to include jQuery in your <head>
You should get the php data before html initiates, like below
<?php
$var = json_decode(file_get_contents('data.php'), true);
?>
<!DOCTYPE html>
<html>
<head>
<script>
$(document).ready(function() {
var testString = <?php echo $var; ?>;
alert(testString);
});
</script>
</head>
<body>
<h1>Test</h1>
</body>
</html>
I'm trying to pass a simple variable from my jQuery to my php and then echo it on my HTML. It doesn't seem to work though.
I can't get my variable $result to show up on my page. Any thoughts? The Ajax POST seems to be working fine. The problem seems to be communication between php and HTML.
index.html:
<!DOCTYPE html>
<html>
<head>
<title>My Site</title>
<script src="http://code.jquery.com/jquery-latest.min.js" type="text/javascript"></script>
<script type='text/javascript' src='front.js'></script>
</head>
<body>
<?php echo $result; ?>
</body>
</html>
front.js:
$(document).ready(function() {
$.post('/back.php', {name: "Bob"}, function(data) {
});
});
back.php:
<?php $result = $_POST['name']; ?>
Try this
index.html:
<!DOCTYPE html>
<html>
<head>
<title>My Site</title>
<script src="http://code.jquery.com/jquery-latest.min.js" type="text/javascript"></script>
<script type='text/javascript' src='front.js'></script>
</head>
<body>
</body>
</html>
front.js:
$(document).ready(function() {
$.post('/back.php', {name: "Bob"}, function(result) {
$('body').html(result);
});
});
back.php:
<?php echo $_POST['name']; ?>
Change this
<body>
<div id="show-data"></div>
</body>
And
$(document).ready(function() {
$.post('/back.php', {name: "Bob"}, function(data) {
$('#show-data').html(data);
});
});
And
<?php echo $result = $_POST['name']; ?>
Change Your PHP Code :
<?php echo $_POST['name']; ?>
And Also Your HTML Code :
<!DOCTYPE html>
<html>
<head>
<title>My Site</title>
<script src="http://code.jquery.com/jquery-latest.min.js" type="text/javascript"></script>
</head>
<body>
</body>
<script>
$(document).ready(function() {
$.post('/back.php', {name: "Bob"}, function(data) {
$('body').append(data)});
});
</script>
</html>
$result in back.php and $result in index.html aren't related. Setting it in back.php has no effect on index.html. If you echo something in back.php however, that output will be passed to the empty callback function you have in your $.post() call. You can handle the data there and use javascript to insert it into your page.
Just add the following line to your code: $('body').html(data);
Like your question we have three different files one is index.html
1) index.html
<!DOCTYPE html>
<html>
<head>
<title>My Site</title>
<script src="http://code.jquery.com/jquery-latest.min.js" type="text/javascript"></script>
<script type='text/javascript' src='front.js'></script>
</head>
<body>
<?php echo $result; ?>
</body>
</html>
2) front.js
$(document).load(function(){
$.ajax({
url: '/back.php',
type: 'POST',
data: 'name=Bob',
async: false,
success: function(data) {
$('body').html(data);
},
cache: false
});
});
3) back.php
<?php echo $result = $_POST['name']; ?>
Now use this, your files will work out. Please let me know if you have any queries.
Puh, lot of mistakes. First, your index.html contains PHP - Code which won't be executed because this is not a PHP - Skript (ending with php).
Second you are saving the value of your request to back.php in a variable, which won't be existing after the request is finished. You can either:
rename index.html to index.php, exchange your statement to
<?php echo $_POST['name']; ?>
and change your request to
$.get('/index.php', {name: "Bob"}, function(data) {
});
which would cause a continously reloading of the site,
or store your result in a $_SESSION (see PHP Session Handling), and retrieve that in your index.php (you got to rename the file).
I am new in jquery. I was trying to use Jcombo plugin but that one wasn't working for me. Here what I did :
<!doctype html>
<head>
<script type="text/javascript" src="http://code.jquery.com/jquery-latest.js"></script>
<script type="text/javascript" src="http://www.prodiven.com/jcombo/jquery.jCombo.min.js"></script>
<script type="text/javascript">
$(function() {
/* simple combos */
$("#state1").jCombo("getStates.php");
});
</script>
</head>
<body>
<select id="state1"></select>
</body>
</html>
getStates.php file output was like this:
{"1":"Bangladesh","2":"Arabic"}
Any idea why I can't see drop down selection. Thanks
I got the solution .. It was problem with the plugin. I just noticed that in jCombo.min.js script dataType was "jsonp" I changed it to :
dataType:"json"
now it's working...