I've two timestamps with a gap between a few hours and a few days.
Is there a way in PHP and / or MySQL to get the time slice for every day?
INPUT
Timestamp 1: 2013-10-30 10:00:00
Timestamp 2: 2013-10-31 11:00:00
OUTPUT
2013-10-30: 14 hours
2013-10-31: 11 hours
Easiest way to perform operations on dates is to convert them to timestamps.
Here, what you can do is to get three timestamps :
$ts1 = strtotime("2013-10-30 10:00:00");
$ts2 = strtotime("2013-10-31 00:00:00");
$ts3 = strtotime("2013-10-31 11:00:00");
$first_time_slice = ts2 - ts1; //here you got your first time slice in seconds, convert it to hours
$second_time_slice = ts3 - ts2; //idem for the second time slice
It can be done in MySql like this:
SELECT TIMEDIFF(TIMESTAMP(DATE('2013-10-30 10:00:00') + INTERVAL 1 DAY), '2013-10-30 10:00:00'),
TIMEDIFF('2013-10-31 11:00:00', TIMESTAMP(DATE('2013-10-31 11:00:00')))
Related
I have a couple of columns in my mysql table of datatype time. The times are listed in military hours I believe, and i need get the difference(hours/mins) between the two times in PHP. Example:
MYSQL:
Start_time End_time
08:00:00 09:15:00
In php how can calculate (Start_time) - (End_time) = (result should be in mins).
You can get it in mysql using this.
SELECT TIMESTAMPDIFF(SECOND, column1, column2);
to get it in php see this answer
Getting time difference between two times in PHP
Or use something like the following where you would use the dates you got from mysql as the strings to DateTime.
1 <?php
2
3 $time1 = new DateTime('13:00:59');
4 $time2 = new DateTime('19:01:00');
5 $interval = $time1->diff($time2);
6 print_r($interval->format('%h:%s'));
To get the interval in a different format change the format string. You can find the valid string values in the DateTime documentation here
To get minutes use "%i" or "%l", the latter has leading zeros.
1 <?php
2
3 $time1 = new DateTime('13:00:59');
4 $time2 = new DateTime('19:01:00');
5 $interval = $time1->diff($time2);
6 print_r($interval->format('%l'));
Need some help.
I am using PHP.
So I have coordinates data.
Specifically Longtitude and Latitude.
So let's say I have 15 data of Long and Lat to be inserted on a table.
However, the api gives me only a single datetime because these coordinates are in array.
For example:
[14.4364372;121.0125753, 14.4364375;121.0125755, 14.4364377;121.0125758, 14.436436;121.012574, 14.4364342;121.0125721, 14.4364326;121.0125704, 14.436433;121.0125707, 14.4364334;121.0125711, 14.4364338;121.0125716, 14.4364342;121.012572, 14.4364345;121.0125724, 14.4364348;121.0125728, 14.4364351;121.0125731, 14.4364353;121.0125733, 14.4364356;121.0125735]
So first you will explode it to get rid of the delimeter ','
And loop it to count how many are data,then explode again the delimiter ';' to count the long and lat given.
But it only have a single datetime.
What i want here is to insert these data including datetime but with interval of 30 seconds per insert.
How can i do that?
Expected output would be like this:
INSERT INTO table_gps(ticket,datetime,long,lat) VALUES(0,09/16/2016 03:30:26 pm, 14.4364363,121.0125745)
INSERT INTO table_gps(ticket,datetime,long,lat) VALUES(0,09/16/2016 03:30:56 pm, 14.4364364,121.0125746)
Here is my code:
$msg= 'YC GPS2~09/16/2016 13:29:46~-~[14.4364362;121.0125744, 14.4364363;121.0125745]';
if(strpos($msg,'YC GPS2')!==false){
//explode data
$explode=explode('~',$msg);
$ky=$explode[0];
$datetime=$explode[1];
$ticket=$explode[2];
$coords=$explode[3];
$coords=explode(',',$coords);
for($i=0;$i<count($coords);$i++){
$xpVal=$coords[$i];
if($xpVal){
$xp3=explode(';',$xpVal);
$lng=$xp3[0];
$lat=$xp3[1];
$lng=str_replace('[','',$lng);
$lat=str_replace(']','',$lat);
$time = date("m/d/Y h:i:s a", time() + 30);// where 30 is the seconds
echo "INSERT INTO GPS2(ticket,datetime,long,lat) VALUES(".$ticket.",".$time.",".$lng.",".$lat.") ";
}
}
}else{
echo '0';
}
Thanks.
In order to add how many seconds you want to particular date in PHP you can use the following.
$time = date("m/d/Y h:i:s a", time() + 30);// where 30 is the seconds
The following is really easy way to add days, minutes, hours and seconds to a time using PHP. Using the date function to set the format of the date to be returned then using strtotime to add the increase or decrease of time then after a comma use another strtotime passing in the start date and time.
//set timezone
date_default_timezone_set('GMT');
//set an date and time to work with
$start = '2014-06-01 14:00:00';
//display the converted time
echo date('Y-m-d H:i',strtotime('+1 hour +20 minutes',strtotime($start)));
Times can be entered in a readable way:
+1 day = adds 1 day
+1 hour = adds 1 hour
+10 minutes = adds 10 minutes
+10 seconds = adds 10 seconds
I have a problem with my script and I dont understand where is the problem. So I have this code :
$i_now = strtotime(date('Y-m-d'));
$i_date_last_bonus = strtotime($o_member->date_last_bonus);
$i_datediff = round(abs($i_now - $i_date_last_bonus) / 86400);
print_r("Date Now :".date('Y-m-d'));
print_r("Last Win :".$o_member->date_last_bonus);
I get the $i_datediff = 1 and I dont understand why because in the print_r I have Date Now :2015-12-04 and Last Win:2015-12-03
Can you help me please where I make the error ? Thx in advance and sorry for my english
In one day there are 24 Hrs, in each hour there are 60Min, in each min there are 60sec. Hence, there are 24*60*60 = 86400sec in one day.
Now, The strtotime() function parses an English textual datetime into a Unix timestamp (the number of seconds since January 1 1970 00:00:00 GMT). Means it returns seconds.
so, i_now = 1449187200 andi_date_last_bonus = 1449100800
Difference is 86400sec.
Now $i_datediff = round(abs($i_now - $i_date_last_bonus) / 86400); this is converting seconds in days.
And Difference is 86400 / 86400 = 1
means 1 day.
This result is correct as you get the number of seconds between two dates first and then you divide it by the number of seconds in 24 hours (86400) which gives you 1 (day) as a result.
Im currently trying to calculate the amount of periods (each period is 1 week, after a certain date or day). Lets say first period start on 01-01-2013 (tuesday) until 29-01-2013 (tuesday)(4 periods in total).
I have a table that looks like:
id | startDate (datetime) | endDate (datetime)
I have two input fields where a user can fill in a start date and end date. I would like to fill any date between 01-01-2013 and 29-01-2013 and decide how many times it passes a tuesday (the date the period starts) again.
So if I would select 01-01-2013 until 07-01-2013 would result in: 1, but if i would select 06-01-2013 till 09-01-2013 this would result in 2 and 06-01-2013 till 16-01-2013 would result in 3 etc.
To be clear, I dont want to know the amount of weeks between the two dates, only the amount of times it 'crosses' the same day (tuesday) that was given in the database. Every period is 1 week. Is there anyone that could help me out?
Use PHP's date() function.
$startday = strtotime($start_date_from_db);//date from db;
$endday = strtotime($end_date_from_db);//date from db;
$counter = 0;
for($i=$startday; $i<=$endday; $i+=86400) {
$current_day = date('w', $i);
if($current_day == 2) { //0 for sunday, 1 for monday, 2 for tuesday
$counter++;
}
}
When comparing dates a good method is:
1- transform the dates to timestamps:
$timestamp1 = strtotime($date1);
$timestamp2 = strtotime($date2);
2- do the desired operation, in this case:
$timebetween = $timestamp2 - $timestamp1;
3- Transform result (number of seconds) to desired value, in this case:
$weeks= $timebetween / 604800;
I have a MySQL DB with StartDates in the format of yyyy-mm-dd and starttimes in the format of HH:MM using a 24 hour clock. What would be the easiest way to compare the difference of two days in PHP? Would using a datetime object could I set it to be with the information given and just give it to zeros for the seconds? I need to get the amount of time between both dates down to the minute. I was putting the startdate (Just the day since its always within the same month for my application) and time together concatenated together and then pulling out what I need like below, but I haven't been able to get it straight yet. Thanks for the look!
$tempvar1 = $times[$i][$j];
$tempvar2 = $times[$i][$j+1];
$day1 = $tempvar1[0].$tempvar1[1];
$day2 = $tempvar2[0].$tempvar2[1];
$hours1 = $tempvar1[2].$tempvar1[3];
$hours2 = $tempvar2[2].$tempvar2[3];
$minutes1 = $tempvar1[5].$tempvar1[6];
$minutes2 = $tempvar2[5].$tempvar2[6];
$numdays = ($day2-$day1) - 1;
$time1 = ($hours1*60)+$minutes1;
$time2 = ($hours2*60)+$minutes2;
MySQL has plenty of date/time functions:
SELECT TIMEDIFF(endtime, starttime), DATEDIFF(endtime, starttime)
FROM ...
doc links for timediff and datediff
That'll you get strings in the format of 'hh:mm:ss.ssss' for timediff, and a straight-up integer representing the days between the two dates, respectively.