Create a loop that will increment time by one hour [duplicate] - php

This question already has answers here:
Print time in 15-minute increments between two times in the same day
(10 answers)
Closed 9 years ago.
I've spent so much time on trying to figure out how to create a loop that will echo time between given $start_time and $end_time incrementing it by one hour in format HH:MM.
For example if i have $start_time = "09:00" and $end_time="15:00" the output should be like:
09:00
10:00
11:00
12:00
13:00
14:00
15:00
Any idea how to do it? I know i should use php timestamps and strtotime etc. by i have never used them, so i can't do anything, pls help...

You can do it with mktime()
$start = 7;
$end = 15;
for ($time = $start; $time <= $end; $time++) {
echo date("H:00", mktime($time+1)).'<br>';
}
EDIT:
Just for fun, here is another example
foreach(range(intval('07:00:00'),intval('16:00:00')) as $time) {
echo date("H:00", mktime($time+1)).'<br>';
}

$interval = date_interval_create_from_date_string('1 hour');
$begin = date_create('09:00');
$end = date_create('15:00')->add($interval);
foreach (new DatePeriod($begin, $interval, $end) as $dt) {
echo $dt->format('H:i') . "\n";
}
Demos:
https://eval.in/56289
https://eval.in/56291
https://eval.in/56292

If you just want to echo the times you can do something simple like this:
$start_time = 9;
$end_time = 15;
for ($time = $start_time; $time <= $end_time; $time++) {
if ($time < 10)
echo "0";
echo $time . ":00\n";
}

$start_time = "15:49";
$hours = 9;
list($h, $m) = explode(':', $start_time);
while ($hours-->0)
{
echo $h++ . ":" . $m . "\n";
}

Its been awhile since I've coded PHP but look at this link.
Note I posted this before the Question was edited.
while($starttime < $endtime)
{
echo $starttime;
$starttime = date_add($starttime, date_interval_create_from_date_string('1 hour'));
}

Related

PHP How to divide weeks into days

How to enlist all the days between for instance 2018-06-04 and 2018-06-10 that between 2018-06-04 - 2018-06-10 those days will be 2018-06-05, 2018-06-06, 2018-06-07, 2018-06-08, 2018-06-09, the same goes for 2018-06-11 - 2018-06-17 and so on...
So far I'ive managed to divide month into week chunks (below), I want to further divide weeks into days...
2018-06-04 - 2018-06-10
2018-06-11 - 2018-06-17
2018-06-18 - 2018-06-24
2018-06-25 - 2018-07-01
http://zakodowac.pl/
This is my PHP code which produces week chunks above 2018-06-04 - 2018-06-10 and so on...:
function getMondays($y, $m) {
return new DatePeriod(
new DateTime("first monday of $y-$m"),
DateInterval::createFromDateString('next monday'),
new DateTime("last day of $y-$m")
);
}
function list_week_days($year, $month) {
foreach (getMondays($year, $month) as $monday) {
echo $monday->format(" Y-m-d\n");
echo '-';
$sunday = $monday->modify('next Sunday');
echo $sunday->format(" Y-m-d\n");
echo '<br>';
}
}
list_week_days(2018, 06);
could you try this:
$begin = strtotime('2018-06-04');
$end = strtotime('2018-06-10');
while($begin < $end){
$begin = $begin +84600;
echo date('Y-m-d', $begin) . ' ';
}
if correctly understood, then the following should yield the results you expect:
// set current date
$date = '04/30/2009';
// parse about any English textual datetime description into a Unix timestamp
$ts = strtotime($date);
// calculate the number of days since Monday
$dow = date('w', $ts);
$offset = $dow - 1;
if ($offset < 0) {
$offset = 6;
}
// calculate timestamp for the Monday
$ts = $ts - $offset*86400;
// loop from Monday till Sunday
for ($i = 0; $i < 7; $i++, $ts += 86400){
print date("m/d/Y l", $ts) . "\n";
}
if you want to be even more clever, you can use:
// set current date
$date = '04/30/2009';
// parse about any English textual datetime description into a Unix timestamp
$ts = strtotime($date);
// find the year (ISO-8601 year number) and the current week
$year = date('o', $ts);
$week = date('W', $ts);
// print week for the current date
for($i = 1; $i <= 7; $i++) {
// timestamp from ISO week date format
$ts = strtotime($year.'W'.$week.$i);
print date("m/d/Y l", $ts) . "\n";
}
All of which, alongside more information, can be found on this website and credit goes to the author of that post.

Add up time from DateTime in PHP

I'll try to explain my problem. I am beginner with PHP and need help manipulating Date/Time.
So here is my situation.
I get Date/Time values from the database in this format: 07/02/2017 11:00 pm
First I need to calculate a difference between two dates and output duration.
Then add up duration and output total time.
The code is very dirty as I am just researching now. I also came to a problem that DateTime does no carry over points. As far as understand I need to convert days to hours and add them up.
Can anybody more experienced make sense of this?
$total_time = new DateTime('00:00');
$start_date = new DateTime('2017-05-01 12:20 PM');
$end_date = new DateTime('2017-05-01 12:30 PM');
$interval = $start_date->diff($end_date);
$total_days = $interval->days;
$hours = $interval->h;
if ($total_days !== FALSE) {
$hours += 24 * $total_days;
}
$minutes = $interval->i;
$total_time ->add($interval);
echo $hours .'hours ' . $minutes . 'minutes';
echo $total_time->format('h:i'); ?>
You can add a DateInterval to the DateTime.
You can check on http://php.net/manual/en/datetime.add.php
Looking at your code:
$total_hours = 0;
$total_minutes = 0;
//must be initialized outside of the while loop
$start_date = new DateTime('2017-05-01 12:20 PM');
$end_date = new DateTime('2017-05-01 12:30 PM');
$interval = $start_date->diff($end_date);
$hours = $interval->h + 24*$interval->d; /*there is no need to check
if you have total days, since 0 days would still work as expected */
$minutes = $interval->i;
echo 'Duration: '.$hours.' hours '.$minutes.' minutes';
$total_hours += $hours;
if(($total_minutes += $minutes) >= 60) {
$total_hours += 1;
$total_minutes -= 60;
}
//after the end of the while loop
echo 'Total time:'.$total_hours.':'.$total_minutes;
Now I don't understand what is the expected output of total time, if you can elaborate on what is not working it would be easier to help

find cout of specific day between two date php without using any loop?

I need to find out count of a specific Day between two date.
I can do this by using loop between two date, but if there is difference of 10 years(suppose) between date loop will run 10*365 times.
Is any easier way to do this?
Thanks in advance
function countDays($day, $start, $end)
{
$start = strtotime($start);
$end = strtotime($end);
$datediff = $end - $start;
$days = floor($datediff / (60 * 60 * 24));
//get the day of the week for start and end dates (0-6)
$w = array( date('w', $start ), date('w', $end) );
//get partial week day count
if ($w[0] < $w[1])
{
$partialWeekCount = ($day >= $w[0] && $day <= $w[1]);
}else if ($w[0] == $w[1])
{
$partialWeekCount = $w[0] == $day;
}else
{
$partialWeekCount = ($day >= $w[0]
$day <= $w[1]);
}
//first count the number of complete weeks, then add 1 if $day falls in a partial week.
return intval($days / 7) + $partialWeekCount;
}
Function Call - countDays( 5, "2017-04-14", "2017-04-21")
You are looking for date_diff() function. The date_diff() function returns the difference between two DateTime objects.
<?php
$date1=date_create("2013-03-15");
$date2=date_create("2013-12-12");
$diff=date_diff($date1,$date2);
echo $diff->format("%R%a days");
?>
To find occurrence of specific day (for eg: Sunday). Please note: I have used 7 for Sunday. You can use 1 for Monday, 2 for Tuesday and so on
$cnt = 0;
$start = new DateTime("2013-03-15");
$end = new DateTime("2013-12-12");
$interval = DateInterval::createFromDateString('1 day');
$period = new DatePeriod($start, $interval, $end);
foreach ($period as $dt)
{
if ($dt->format('N') == 7)
{
$cnt++;
}
}
echo $cnt;

PHP- Display days weekly by giving 2 dates

I'd like display dates by week number between giving 2 dates like example below. Is this possible in PHP?
if the dates are 2010-12-01 thru 2010-12-19, it will display it as follows.
week-1
2010-12-01
2010-12-02
2010-12-03
2010-12-04
2010-12-05
2010-12-06
2010-12-07
week-2
2010-12-08
2010-12-09
2010-12-10
2010-12-11
2010-12-12
2010-12-13
2010-12-14
week-3
2010-12-15
2010-12-16
2010-12-17
2010-12-18
2010-12-19
and so on...
I use mysql. It has startdate end enddate fields.
thank you in advance.
I can get how many weeks in those giving 2 dates and display them using a
datediff('ww', '2010-12-01', '2010-12-19', false); I found on the internet.
And I can display dates between two dates as follows. But I am having trouble grouping them by week.
$sdate = "2010-12-01";
$edate = "2010-12-19";
$days = getDaysInBetween($sdate, $edate);
foreach ($days as $val)
{
echo $val;
}
function getDaysInBetween($start, $end) {
// Vars
$day = 86400; // Day in seconds
$format = 'Y-m-d'; // Output format (see PHP date funciton)
$sTime = strtotime($start); // Start as time
$eTime = strtotime($end); // End as time
$numDays = round(($eTime - $sTime) / $day) + 1;
$days = array();
// Get days
for ($d = 0; $d < $numDays; $d++) {
$days[] = date($format, ($sTime + ($d * $day)));
}
// Return days
return $days;
}
New answer.
$current_date = strtotime('2010-12-01');
$end_date = strtotime('2010-12-19');
$day_count = 0;
$current_week = null;
do {
if ((int)($day_count / 7) + 1 != $current_week) {
$current_week = (int)($day_count / 7) + 1;
echo 'week-'.$current_week.'<br />';
}
echo date('Y-m-d', $current_date).'<br />';
$current_date = strtotime('+1 day', $current_date);
$day_count ++;
} while ($current_date <= $end_date);
You will definitely need this: Simplest way to increment a date in PHP?. Write a forloop and increment the day every time. You will also need the DateTime class and functions as date. Indeed asking for date('W', yourDateHere) is a nice idea.
You will get something like this (pseudocode)
$startDate;
$endDate;
$nrOfDays = dateDiffInDays($endDate, $startDate);
$currentWeek = date('W',$startDate);
for($i = 0; $i < $nrOfDays; $i++)
{
$newDay = date('+$i day', $startDate); // get the incremented day
$newWeek = date('W', $newDay); // get the week of the new day
if($newWeek != $currentWeek) // check if we must print the new week, or if we are still in the current
print $newWeek;
print $newDay; // print the day
}
Hope this helps. Good luck.
Tools sufficient to do the job:
strtotime('2010-11-23') - to get a timestamp from a date
strtotime('+1 day', $someTimestamp) - to get the next day
date('W', $someTimestamp) - to get the week number (if you want to group by ISO week number)
array_chunk($orderedListOfSuccessiveDates, 7) - to split in groups of seven days (if you don't want to group by ISO week number)
Warning: Never, ever increment days by adding 86400 to the timestamp! That is the easiest way to break everything when Daylight Saving comes along. Either use the strtotime function or the DateTime class.
Here you go. Although this is with weeks starting on sundays (just change it to monday if need be). And it doesnt work if the dates arent in the same year. But it should be pretty easy to fix that. If not_same_year then ...
$start_date = mktime(0, 0, 0, 12, 01, 2010);
$start_date_week_number = (int) date("W", $start_date);
$end_date = mktime(0, 0, 0, 12, 19, 2010);
$end_date_week_number = (int) date("W", $end_date);
$n = $start_date_week_number;
$w = 1;
$date = $start_date;
while($n <= $end_date_week_number) {
echo("<strong>Week " . $w . "</strong><br />");
$s = 0;
$e = 6;
if($n == $start_date_week_number) $s = (int) date("w", $start_date);
elseif($n == $end_date_week_number) $e = (int) date("w", $end_date);
while($s <= $e) {
echo(date("j-m-y", $date) . "<br />");
$c_date = getdate($date);
$date = mktime($c_date['hours'], $c_date['minutes'], $c_date['seconds'], $c_date['mon'], $c_date['mday'] + 1, $c_date['year']);
$s++;
}
$n++; $w++;
}
DEMO HERE
Edit: just fixed it when I realized you wanted to count the weeks (not get the actual week number)...
$startDate = new DateTime('2010-01-01');
$endDate = new DateTime('2010-01-14');
$weeksDays = getWeeksDaysBetween($startDate, $endDate);
foreach($weeksDays as $week => $days)
{
echo "Week $week<ul>";
foreach($days as $day){
echo "<li>$day</li>";
}
echo "</ul>";
}
function getWeeksDaysBetween($startDate, $endDate)
{
$weeksDays = array();
$dateDiff = $endDate->diff($startDate);
$fullDays = $dateDiff->d;
$numWeeks = floor($fullDays / 7) + 1;
$weeksDays[1][] = $startDate->format('Y-m-d');
for ($i = 1; $i <= $fullDays; $i++)
{
$weekNum = floor($i / 7) + 1;
$dateInterval = DateInterval::createFromDateString("1 day");
$weeksDays[$weekNum][] = $startDate->add($dateInterval)->format('Y-m-d');
}
return $weeksDays;
}

Create an Array of the Last 30 Days Using PHP

I am trying to create an array starting with today and going back the last 30 days with PHP and I am having trouble. I can estimate but I don’t know a good way of doing it and taking into account the number of days in the previous month etc. Does anyone have a good solution? I can’t get close but I need to make sure it is 100% accurate.
Try this:
<?php
$d = array();
for($i = 0; $i < 30; $i++)
$d[] = date("d", strtotime('-'. $i .' days'));
?>
Here is advance latest snippet for the same,
$today = new DateTime(); // today
$begin = $today->sub(new DateInterval('P30D')); //created 30 days interval back
$end = new DateTime();
$end = $end->modify('+1 day'); // interval generates upto last day
$interval = new DateInterval('P1D'); // 1d interval range
$daterange = new DatePeriod($begin, $interval, $end); // it always runs forwards in date
foreach ($daterange as $date) { // date object
$d[] = $date->format("Y-m-d"); // your date
}
print_r($d);
Working demo.
Official doc.
For those who want to show sales of the past X days,
As asked in this closed question (https://stackoverflow.com/questions/11193191/how-to-get-last-7-days-using-php#=), this worked for me.
$sales = Sale::find_all();//the sales object or array
for($i=0; $i<7; $i++){
$sale_sum = 0; //sum of sale initial
if($i==0){
$day = strtotime("today");
} else {
$day = strtotime("$i days ago");
}
$thisDayInWords = strftime("%A", $day);
foreach($sales as $sale){
$date = strtotime($sale->date_of_sale)); //May 30th 2018 10:00:00 AM
$dateInWords = strftime("%A", $date);
if($dateInWords == $thisDayInWords){
$sale_sum += $sale->total_sale;//add only sales of this date... or whatever
}
}
//display the results of each day's sale
echo $thisDayInWords."-".$sale_sum; ?>
}
Before you get angry:
I placed this answer here to help someone who was directed here from that question. Couldn't answer there :(
You can use time to control the days:
for ($i = 0; $i < 30; $i++)
{
$timestamp = time();
$tm = 86400 * $i; // 60 * 60 * 24 = 86400 = 1 day in seconds
$tm = $timestamp - $tm;
$the_date = date("m/d/Y", $tm);
}
Now, within the for loop you can use the $the_date variable for whatever purposes you might want to. :-)
$d = array();
for($i = 0; $i < 30; $i++)
array_unshift($d,strtotime('-'. $i .' days'));

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