two mysqli querys, one in a while loop - php

Question

Can't seam to find the answer to this.
I have a mysqli loop statement. And in that loop I want to run another query. I cant write these two sql together. Is that possible?
I thought since I use stmt and set that to prepare statement. So i add another variable stmt2. Running them seperate works, but run it like I wrote it gives me "mysqli Fatal error: Call to a member function bind_param() on a non-object"
Pseudocode :
loop_sql_Statement {
loop_another_sql_statement(variable_from_firsT_select) {
echo "$first_statement_variables $second_statemenet_variables";
}
}
$sql = "select dyr_id, dyr_navn, type_navn, dyr_rase_id, dyr_fodt_aar, dyr_kommentar, dyr_opprettet, dyr_endret
from dyr_opphald, dyr, dyr_typer
where dyropphald_dyr_id = dyr_id
and dyr_type_id = type_id
and dyropphald_opphald_id = ?";
$stmt = $mysqli->prepare($sql);
$stmt->bind_param("i",
$p_opphald_id);
$stmt->execute();
$stmt->bind_result($dyr_id, $dyr_navn, $type_navn, $dyr_rase_id, $dyr_fodt_aar, $dyr_kommentar, $dyr_opprettet, $dyr_endret);
echo "<table>";
while($stmt->fetch()) {
echo "<tr><td>$dyr_navn</td><td>$type_navn</td><td>$dyr_rase_id</td><td>$dyr_fodt_aar</td><td>";
$sql2 = "select ekstra_ledetekst, ekstradyr_ekstra_verdi from dyr_ekstrainfo, ekstrainfo where ekstradyr_ekstra_id = ekstra_id and ekstradyr_dyr_id = ?";
try {
$stmt2 = $mysqli->prepare($sql2);
$stmt2->bind_param("i",
$dyr_id);
$stmt2->execute();
$stmt2->bind_result($ekstra_ledetekst, $ekstra_ledetekst);
echo "<td>";
while($stmt2->fetch()) {
echo "$ekstra_ledetekst => $ekstra_ledetekst<br>";
}
}catch (Exception $e) {}
echo "</td></tr>";
}
echo "</table>";
The answer:
Silly me, I didnt know I had to have two mysqli connection. So the solution was to declare another mysqli connection.
$mysqli = new mysqli($start, $name, $pwd, $selected_db);
$mysqli2 = new mysqli($start, $name, $pwd, $selected_db);

Answer 1

You should be able to do that, although you make have to start a second connection.