I know this has been asked before, but I can't get it working.
I'm loading a file on a page whose path and name are a variable contained in a PHP script.
My script.php is outputing a variable $filename which contains the path to a file that has to be open in an ajax request.
So, the file can be for example:
'../path/to/file/filea.json' or
'../another/path/fileb.json'
I tried this in my jQuery:
$.ajax({
url:'script.php',
success:$.ajax({
url: ??? // This ($filename) is what I'm trying to get from the 1st Ajax call
sucess: function(data){
//other code here
}
})
);
I know $filename is wrong in the second Ajax call but how do I get the value of that variable?
$.ajax({
url: "script.php",
success: function(data){
$.ajax({
var someParam=data; //response Data from 1st Ajax Call
type: "post",
url: "example.php",
data: 'page='+someParam,
success: function(data){
//Do More Here!
});
});
Try this:
inside script.php
echo json_encode($filename); //somewhere you need to have this echo.
jQuery
$.ajax({
url: 'script.php',
success: function (data) {
alert(data); //or console.log() and doublecheck you have the right info
$.ajax({
url: JSON.parse(data),
success : function (data) {
//other code here
}
})
}
}); // added a extra } to close the ajax
This solved the problem:
$.ajax({
async:false,
url: 'script.php',
success: function(data){
$.ajax({
url: data,
success: //code here
})
})
#Sergio: script.php wasn't echoeing the output of $filename... Thanks for reminding!
Related
Hey all im trying to use ajax to get a php file and run a few functions.
My ajax looks like this :
jQuery(document).ready(function(){
jQuery(".claim-button").click(function(){
alert("click ok");
var baseUrl = document.location.origin;
jQuery.ajax({
type: "POST",
url: '/custom_functions/win_checker.php'
});
});
});
Then in the php file I put something simple jsut to test it works:
echo "Test";
I get the jquery "click ok" but it does not return the php echo.
Im am very new to ajax could someone please advise what im doing wrong.
Many thanks
David
You need to have success to capture the PHP response:
jQuery(document).ready(function(){
jQuery(".claim-button").click(function(){
alert("click ok");
var baseUrl = document.location.origin;
jQuery.ajax({
type: "POST",
url: '/custom_functions/win_checker.php',
data: {var1: 'someValue'},
success: function(response){
alert(response); // this will alert 'Test'
}
});
});
});
In PHP, you will get parameters in $_POST.
To handle the output of the AJAX request, you have to provide a function to be executed on success:
jQuery(document).ready(function(){
jQuery(".claim-button").click(function(){
alert("click ok");
var baseUrl = document.location.origin;
jQuery.ajax({
type: "POST",
url: '/custom_functions/win_checker.php',
success: function(result) {
// Do with your result what you want, e.g. print it to the console
console.log(result);
}
});
});
});
hi i want to send javascript data via ajax to the same page in wordpress. Cannot fetch the data in testajax.php page. its shows Undefined index: name. And how to send the data on same php page rather than testajax.php ?
<script>
jQuery.ajax({
type: "POST",
url: 'http://localhost/projects/xxx/wordpress/wp-content/themes/xxx/testajax.php',
data: {name:'foo'},
success: function(data)
{
alert('success');
}
});
var foo = 'somename';
jQuery.ajax({
url:'yourUrl',
type: "POST",
data: {'name':foo},
success: function(data)
{
alert('success');
}
});
php
<?php
if(isset($_POST['name'])){
//Do whatever you want
}else{
//Do whatever you want
}
?>
jQuery.ajax({
url: "./_FILE_" // ./index.php for example
type: "POST",
data: {name:'foo'},
success: function(data)
{
alert('success');
}
});
$(document).ready(function(){
$("#S1").change(function()
{
var IDCat=this.value;
$.ajax({
type: "GET",
url: 'product_modify.php',
data: {IDCat:IDCat},
success: function(data)
{
$("#p1").text(data);
$("#tempForm").load('tv_form.php');
}
});
});
});
It is my code , in load() function when I call 'tv_form.html' file it works, but when i call 'tv_form.php' it doesn't work , error is 403 forbidden
where is the problem ? .html works, but .php doesn't work.
Add URL instead of file name.
$(document).ready(function(){
$("#S1").change(function()
{
var IDCat=this.value;
$.ajax({
type: "GET",
url: 'product_modify.php',
data: {IDCat:IDCat},
success: function(data)
{
$("#p1").text(data);
$("#tempForm").load('URL to tv_form.php'); // www.example.com/file.php
}
});
});
});
I want to pass values to a PHP script so i am using AJAX to pass those, and in the same function I am using another AJAX to retrieve those values.
The problem is that the second AJAX is not retrieving any value from the PHP file. Why is this? How can I store the variable passed on to the PHP script so that the second AJAX can retrieve it?
My code is as follows:
AJAX CODE:
$(document).ready(function() {
$("#raaagh").click(function(){
$.ajax({
url: 'ajax.php', //This is the current doc
type: "POST",
data: ({name: 145}),
success: function(data){
console.log(data);
}
});
$.ajax({
url:'ajax.php',
data:"",
dataType:'json',
success:function(data1){
var y1=data1;
console.log(data1);
}
});
});
});
PHP CODE:
<?php
$userAnswer = $_POST['name'];
echo json_encode($userAnswer);
?>
Use dataType:"json" for json data
$.ajax({
url: 'ajax.php', //This is the current doc
type: "POST",
dataType:'json', // add json datatype to get json
data: ({name: 145}),
success: function(data){
console.log(data);
}
});
Read Docs http://api.jquery.com/jQuery.ajax/
Also in PHP
<?php
$userAnswer = $_POST['name'];
$sql="SELECT * FROM <tablename> where color='".$userAnswer."'" ;
$result=mysql_query($sql);
$row=mysql_fetch_array($result);
// for first row only and suppose table having data
echo json_encode($row); // pass array in json_encode
?>
No need to use second ajax function, you can get it back on success inside a function, another issue here is you don't know when the first ajax call finished, then, even if you use SESSION you may not get it within second AJAX call.
SO, I recommend using one AJAX call and get the value with success.
example: in first ajax call
$.ajax({
url: 'ajax.php', //This is the current doc
type: "POST",
data: ({name: 145}),
success: function(data){
console.log(data);
alert(data);
//or if the data is JSON
var jdata = jQuery.parseJSON(data);
}
});
$(document).ready(function() {
$("#raaagh").click(function() {
$.ajax({
url: 'ajax.php', //This is the current doc
type: "POST",
data: ({name: 145}),
success: function(data) {
console.log(data);
$.ajax({
url:'ajax.php',
data: data,
dataType:'json',
success:function(data1) {
var y1=data1;
console.log(data1);
}
});
}
});
});
});
Use like this, first make a ajax call to get data, then your php function will return u the result which u wil get in data and pass that data to the new ajax call
In your PhP file there's going to be a variable called $_REQUEST and it contains an array with all the data send from Javascript to PhP using AJAX.
Try this: var_dump($_REQUEST); and check if you're receiving the values.
you have to pass values with the single quotes
$(document).ready(function() {
$("#raaagh").click(function(){
$.ajax({
url: 'ajax.php', //This is the current doc
type: "POST",
data: ({name: '145'}), //variables should be pass like this
success: function(data){
console.log(data);
}
});
$.ajax({
url:'ajax.php',
data:"",
dataType:'json',
success:function(data1){
var y1=data1;
console.log(data1);
}
});
});
});
try it it may work.......
Ok so I know long hand ajax but trying to use the jQuery short cut. I have two documents
form.php
submit.php
In my "form" page I am calling the "submit" page to process the insert. I am currently using the jquery ajax:
<script type="text/javascript">
jQuery('form').submit(function() {
string = jQuery("form").serializeArray();
jQuery.ajax({
type: "POST",
url: "submit.php",
data: string,
dataType: "json",
})
return false;
});
</script>
When I view firebug it is processing the ajax fine. I am getting 200 and post parameters are set. What I am trying to do is have the ajax return the submit.php file. I know it has something to do with the "success" function but I don't know how to add this. I tried a few things like:
<script type="text/javascript">
jQuery('form').submit(function() {
string = jQuery("form").serializeArray();
jQuery.ajax({
type: "POST",
url: "submit.php",
data: string,
dataType: "json",
success: function(html){
alert(html);
}
})
return false;
});
</script>
and
<script type="text/javascript">
jQuery('form').submit(function() {
string = jQuery("form").serializeArray();
jQuery.ajax({
type: "POST",
url: "submit.php",
data: string,
dataType: "json",
success: function(html){
$('.result').html(data);
}
})
return false;
});
</script>
but neither of these are working. Again I am simply trying to send the ajax request and then return the contents of the submit.php page. Not only does the submit.php page hold the script to process the php/ajax insert but it also display success statements like "insert was successful" so that is why I need to not only run the script in the page but also return the contents of that page. Thank you for any help.
Chagne the dataType:'json' to dataType:'html' for the callback that you wish to display the contents of submit.php.
You were close in your second attempt, but you made a typo. Try:
success: function (data) {
$('.result').html(data);
}
Also, unless your server is returning JSON, you probably want to change the dataType:
dataType: "html"