using php's include is possible to include part of another page without including all that entire content of that page?
From pageX.php i want Div #A not div #B the whole pageX.php
<div id="A">
<p>Don't show me</p>
</div>
<div id="B">
<p>Display Me</p>
</div>
i'm aware of JQuery's ajax Load but im wondering if there's a method like that in php.
I am not aware of any function that can include a specific part of a php file but typically this can be achieved in two ways.
Split your UI component markups into separate files so that can be included separately and easily re-used in many places. (example here)
Have all the UI components markups as different functions in a common file which can be called easily.
function printDivA() {
echo <<< DIV_A
<div id="A">
<p>Don't show me</p>
</div>
DIV_A;
}
Related
I have researched some answers that talk about php, javascript, iframes etc. but I have tried a couple and none of them work. I am new to HTML coding.. and coding in general!
<link rel="menu" href="menu.html"> does nothing
<!--#include virtual="/menu.html" --> does nothing (presumably because its a comment?)
<iframe src="page.html"></iframe>
or object... both place the menu in a silly little scroll box.
I want to run my menu on my page as if it were a function in C. Where I can just include it, and it be there, or just link it.
Thanks for the help!
Ryan
webpage file: biology.html
menu file: menu.html
<div class="container">
<img src="homeicon.jpg" width="50" alt="Home">
<div class="redhover">
<div class="dropdown">
<button class="dropbtn">GCSEs</button>
<div class="dropdown-content">
Chemistry
Biology
</div>
</div>
<div class="dropdown">
<button class="dropbtn">A-Levels</button>
<div class="dropdown-content">
Chemistry
Biology
</div>
</div>
<div class="dropdown">
<button class="dropbtn">University</button>
<div class="dropdown-content">
Telecommunications
Electronic Engineering
</div>
</div>
<div class="dropdown">
<button class="dropbtn">More</button>
<div class="dropdown-content">
About me
Youtube
</div>
</div>
</div>
</div>
You can use php to include files on other pages. Here is some example code to get you started:
<?php
require_once('menu.php');
?>
You can put this in your HTML page appropriately, however you must make sure that php can be processed on your server and the file containing php code must end in the .php extension.
There are also other methods of including files via php, see here:
http://php.net/manual/en/function.include.php
and
http://php.net/manual/en/function.require.php
Edit - I'm not a big fan of this approach, but it will work on Github pages.
Create a file called nav.js with your menu defined as a js variable, then use javascript to insert it into an empty div created on each page. This way to update your nav you only have to ever edit nav.js Not pretty but it works
nav.js
var navigation = "<nav>";
navigation += "<ul>";
navigation += "<li>Home</li>";
navigation += "<li>About</li>";
navigation += "</ul>";
navigation += "</nav>";
document.getElementById("navigation").innerHTML = navigation;
Other pages
<div id="navigation"></div>
<!--rest of page goes here.-->
<script src="nav.js"></script>
Fiddle: https://jsfiddle.net/ze3hLxx8/1/
There are multiple ways to include a file into another depending on the backend technology you wish / want / need to use.
PHP
The most common way to do it in php is by using the include or require statement inside a php file.
In your specific case your biology.html file must be converted to a biology.php file and then you can add the relative code to include the file:
<?php include('menu.php');?>
This simple statement will add the content in your menu.php file to the current page. This will not work if php is not present on the server and obviously will not work locally without a local development environment
The differences between require and include can be found on the official documentation:
include: http://php.net/manual/en/function.include.php
require: http://php.net/manual/en/function.require.php
SSI
Another method is to use Server Side Includes. To use the SSI it must be supported and enabled on the webserver. To use SSI you need to change the extension from biology.html to biology.shtml and then add the following statement:
<!--#include file="menu.html" -->
More information on server side includes can be found on wikipedia: https://en.wikipedia.org/wiki/Server_Side_Includes
Is there a quick way, via script maybe, to remove a certain pair of div's out of all my wordpress posts? For example:
I want to go from this:
<div class="single_textimage">
<div class="youtube_play"><iframe src="-,-"></iframe></div>
<div class="single_textimage_text">Some text.</div>
<div class="single_textimage_copyright">Some text.</div>
</div>
To this:
<div class="youtube_play"><iframe src="-,-"></iframe></div>
AND
From this:
<div class="single_textimage">
<img class="aligncenter size-full wp-image-1700" src="-,-" />
<div class="single_textimage_text">Some text.</div>
<div class="single_textimage_copyright">Some text.</div>
</div>
To this:
<img class="aligncenter size-full wp-image-1700" src="-,-" />
So I want the divs: single_textimage, single_textimage_text and single_textimage_copyright to go.
I hope there is an easy script, or difficult for that matter. Via "php", "mysql" or "jquery" for example, that I can put in test.php in the root or something...
I hope I supplied you with enough information. If I haven't made myself clear enough, please reply. :)
Seems to me like you should be able to take those out of whatever template your using - probably in a PHP include, but I don't really use WordPress, so I wouldn't know where without seeing all your files. If you're bent on using jQuery instead of modifying the template, I would throw in some CSS too, to hide the elements that will be removed:
.single_textimage, .single_textimage_text, .single_textimage_copyright{
display:none;
}
Then you can take the elements you want to keep out of their parent DIVs, and place them right after (or before):
$('.youtube_play, .wp-image-1700').each(function(){
$(this).parent().after($(this));
});
Then you can remove the elements you don't want from the page:
$('.single_textimage, .single_textimage_text, .single_textimage_copyright').remove();
Here's a fiddle: https://jsfiddle.net/3uztorzL/
I would use this search and replace utility to update all of the content in the DB:
https://interconnectit.com/products/search-and-replace-for-wordpress-databases/
You'll need a regex to replace <div class="single_textimage_text">Some text.</div> (assuming the "some text" is different in each post). The utility supports regex replace. This may do it:
<div class="single_textimage_text">(.*?)</div>
Make sure you make a backup before you do the replace.
I want to try and get the latest movie I checked on the IcheckMovies site and display it on my website. I don't know how, I've read about php_get_contents() and then getting an element but the specific element I want is rather deep in the DOM-structure. Its in a div in a div in a list in a ...
So, this is the link I want to get my content from: http://www.icheckmovies.com/profiles/robinwatchesmovies and I want to get the first title of the movie in the list.
Thanks so much in advance!
EDIT:
So using the file_get_contents() method
<?php
$html = file_get_contents('http://www.icheckmovies.com/profiles/robinwatchesmovies/');
echo $html;
?>
I got this html output. Now, I just need to get 'Smashed' so the content of the href link inside the h3 inside a div inside a div inside a list. This is where I don't know how to get it.
...
<div class="span-7">
<h2>Checks</h2>
<ol class="itemList">
<li class="listItem listItemSmall listItemMovie movie">
<div class="listImage listImageCover">
<a class="dvdCoverSmall" title="View detailed information on Smashed (2012)" href="/movies/smashed/"></a>
<div class="coverImage" style="background: url(/var/covers/small/10/1097928.jpg);"></div>
</div>
<h3>
<a title="View detailed information on Smashed (2012)" href="/movies/smashed/">Smashed</a>
</h3>
<span class="info">6 days ago</span>
</li>
<li class="listItem listItemSmall listItemMovie movie">
<li class="listItem listItemSmall listItemMovie movie">
</ol>
<span>
</div>
...
There are some libraries which could help you!
One I've used for the same purpose, a long time ago, is this: http://simplehtmldom.sourceforge.net/
I hope it help you!
follow steps to achieve this
STEP1:-
First get the contents using file_get_contents in a php file
ex: getcontent.php
<?php
echo file_get_contents("http://www.icheckmovies.com/movies/checked/?user=robinwatchesmovies ");
?>
STEP2:-
CALL the above script using ajax call and add the content to a visibility hidden field in the html.
ex:
$('#hidden_div').html(response);
html:-
<html>
<body>
<div id='hidden_div' style='visibility:hidden'>
</div>
</body>
</html>
STEP3:-
now extract the id what ever you want.
What you are asking for is called as web scraping ,I have done this a few months back, the process goes like this,
Make a HttpRequest to the site from which you need the content,check
the php class for it
Use a DOM parse library for handling the downloaded page (it would be in html),simple HTLM DOM would be a good choice
Extract your required information
Here are some tutorials for you,
HTML Parsing and Screen Scraping with the Simple HTML DOM
Library
Beginning web page scraping with php
SO Posts:
HTML Scraping in Php
And best of all Google is your friend just search for "PHP scraping"
I have a Symfony 1.4 project. As you know the Template layout is defined independently, in the apps' templates' folder and then it is universally applied to all other templates. My layout is very simple, something like this:
<div id = "header">
</div>
<div id = "content">
<?php echo $sf_content ; ?>
</div>
<div id = "footer">
</div>
$sf_content, as most symfonians would know, essentially spits out the template for whatever web page is being viewed at the moment. If I needed some specific data for my header, such as logout, logo etc, I would simply include it within my header. THis works great because it is static in nature. The challenge I am facing is how I can include data that is dynamic in nature and specific to a page within the header tag because the UI demands that I include it there.
For instance, one of my webpages requires user specific data to be loaded in a dropdown/select menu. This is dynamic and could range from 0 to 100 and is specific to each user. To create this dropdown menu is not an issue, and I already have that part done. The challenge is, how do I load it in the header, given that my data becomes part of $sf_content and that is spit out in my content div.
Is there a way for me to move a specific part of my $sf_content into the header div ?
In your actions.php:
$this->getResponse()->setSlot('someData', 'and its value');
In layout.php:
<div id="header">
<?php echo get_slot('someData'); ?>
</div>
<div id="content">
<?php echo $sf_content ; ?>
</div>
<div id="footer">
</div>
Slots work for this. They can either be set in the action as in the first answer above or you can define them in the templates themselves. This is what I've done where I have dynamic data to define for the layout.
In your example:
<div id="header">
<?php include_slot('some slot name')?>
</div>
<div id="content">
<?php echo $sf_content() ?>
</div>
<div id="footer">
</div>
In the templates you would define the following:
<?php slot('some slot name')?>
//your code goes here
<?php end_slot() ?>
When the layout is then rendered Symfony will place the code between the slot() and end_slot() into the point at which you defined by using include_slot().
For ease I created a global partial that is included in all templates that defines the various common slots used through out the application. There is more info on slots and their usage here
Can php divide the page into small block and gradually appear?
I divided my main page into several small blocks, like:
<?php
include('header.php');
<div id="content">
<!-- some content -->
</div>
include('partone.php');
include('parttwo.php');
include('partthree.php');
include('footer.php');
?>
I need open the page, first load header.php, div#content, footer.php, then gradually loaded partone.php, parttwo.php, partthree.php. Is there a way could do that? thanks.
PHP is executed server side, so your code will include all the files listed, and send the entire output to the client computer at once.
If you want only parts of the page to appear at a time, try enclosing them in divs and use JavaScript.
Sounds like you should be using javascript to do this.
Have a look at the jQuery get method.
This might be what you're after: http://www.webresourcesdepot.com/load-content-while-scrolling-with-jquery/
Demo: http://www.webresourcesdepot.com/dnspinger/
Modify your code to look like the following
<?php
include('header.php');
?>
<div id="content">
<!-- some content -->
</div>
<div id="partOne"></div>
<div id="partTwo"></div>
<div id="partThree"></div>
<?php
include('footer.php');
?>
Then make 3 ajax requests to load in partone.php, parttwo.php and partthree.php to their respecitve divs in the above code. Plenty of tutorials on how to do this via all the different javascript frameworks out there. Personally I use jquery, but you can use whatever is your preference for this.